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Ruin problems in Markov-modulated risk models

Published online by Cambridge University Press:  30 May 2017

David C.M. Dickson*
Affiliation:
Department of Economics, Centre for Actuarial Studies, University of Melbourne, Melbourne, VIC 3010, Australia
Marjan Qazvini
Affiliation:
Department of Economics, Centre for Actuarial Studies, University of Melbourne, Melbourne, VIC 3010, Australia
*
*Correspondence to: David C.M. Dickson, Department of Economics, Centre for Actuarial Studies, The University of Melbourne, Melbourne, VIC 3010, Australia. Tel: +61 3 8344 4727. Fax: +61 3 8344 6899. E-mail: dcmd@unimelb.edu.au
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Abstract

Chen et al. (2014), studied a discrete semi-Markov risk model that covers existing risk models such as the compound binomial model and the compound Markov binomial model. We consider their model and build numerical algorithms that provide approximations to the probability of ultimate ruin and the probability and severity of ruin in a continuous time two-state Markov-modulated risk model. We then study the finite time ruin probability for a discrete m-state model and show how we can approximate the density of the time of ruin in a continuous time Markov-modulated model with more than two states.

Information

Type
Papers
Copyright
© Institute and Faculty of Actuaries 2017 
Figure 0

Table 1 Exponential claims, with E[S1]=E[S2].

Figure 1

Table 2 Exponential claims, with E[S1]>E[S2].

Figure 2

Table 3 Exponential claims, with E[S1]<E[S2].

Figure 3

Table 4 Pareto claims when E[S1]=E[S2].

Figure 4

Table 5 Pareto claims when E[S1]>E[S2].

Figure 5

Table 6 Pareto claims when E[S1]<E[S2].

Figure 6

Table 7 Exponential claims, y=3 and E[S1]=E[S2].

Figure 7

Table 8 Exponential claims, y=3 and E[S1]>E[S2].

Figure 8

Table 9 Exponential claims, y=3 and E[S1]<E[S2].

Figure 9

Table 10 Pareto claims, y=3 and E[S1]=E[S2].

Figure 10

Table 11 Pareto claims, y=3 and E[S1]>E[S2].

Figure 11

Table 12 Pareto claims, y=3 and E[S1]<E[S2].

Figure 12

Figure 1 Case 2: ψ1(40)=0.03418 and ψ2(40)=0.03071.

Figure 13

Figure 2 Case 3: ψ1(120)=0.02304 and ψ2(120)=0.02721.

Figure 14

Figure 3 Case 5: ψ1(40)=0.34427 and ψ2(40)=0.33677.

Figure 15

Figure 4 Case 6: ψ1(40)=0.43292 and ψ2(40)=0.47021.

Figure 16

Figure 5 Exponential claims.

Figure 17

Figure 6 Pareto claims.