1 Introduction
Let E be an elliptic curve over
$\mathbb {Q}$
without complex multiplication. Serre showed in [Reference Serre15] that the adelic representation attached to
$E/\mathbb {Q}$
has open image, in particular, there is a minimal natural number
$C_E$
such that the mod
$\ell $
representation
${\bar {\rho }}_{E,\ell }$
is surjective for any prime
$\ell> C_E$
.
In determining effective bounds on
$C_E$
, one typically uses effective versions of the Chebotarev Density Theorem under the assumption of the Generalized Riemann Hypothesis (GRH) as was first done by Serre. The bounds on
$C_E$
usually depend on the radical
$\operatorname {\mathrm {rad}}(N_E)$
of the conductor
$N_E$
of E over
$\mathbb {Q}$
. In Serre’s original treatment [Reference Serre16], the following theorem was shown. By GRH, we mean the conjecture which applies to the Artin L-functions of Galois extensions
$L/K,$
where L and K are number fields.
Theorem 1.1 [Reference Serre16, Theorem 21]
Assume GRH. Let E and
$E'$
be two elliptic curves defined over
$\mathbb {Q}$
. Suppose that E and
$E'$
are not
$\mathbb {Q}$
-isogenous. Then, there exists a prime p of good reduction for E and
$E'$
such that
$a_p(E) \neq a_p(E')$
and satisfying the inequality
where
$C_1$
is an absolute constant.
Based on the method used, the constant
$C_1$
here is unfortunately rather large. Recent work of Mayle–Wang [Reference Mayle and Wang10] has given an explicit result on the smallest prime which achieves
$a_p(E) \neq a_p(E')$
. The constants are quite small, and like Serre’s result, depend on only knowledge of the primes of bad reduction of the two elliptic curves E and
$E'$
.
Theorem 1.2 [Reference Mayle and Wang10, Theorem 2]
Assume GRH. Let E and
$E'$
be two elliptic curves over
$\mathbb {Q}$
without complex multiplication. Suppose E and
$E'$
are not
$\mathbb {Q}$
-isogenous. Then, there exists a prime p of good reduction for E and
$E'$
such that
$a_p(E) \neq a_p(E')$
and satisfying the inequality
where
$N_E$
and
$N_{E'}$
denote the conductors of E and
$E'$
, respectively.
The method is based on using effective forms of the Chebotarev Density Theorem together with the Faltings–Serre method, in particular, by studying the “deviation group”
$\delta (G)$
of the
$2$
-adic representations attached to two elliptic curves.
In our work, we explain how to replace
$\delta (G)$
with smaller quotients in Mayle–Wang’s original arguments. Using these smaller quotients, allows us to prove an improved effective isogeny theorem for elliptic curves over
$\mathbb {Q}$
with a certain condition on the mod
$2$
representations.
Theorem 1.3 Assume GRH. Let E and
$E'$
be two elliptic curves over
$\mathbb {Q}$
. Suppose E and
$E'$
are not
$\mathbb {Q}$
-isogenous. Assume the mod 2 representations
$\bar {\rho }_{E,2}$
and
$\bar {\rho }_{E',2}$
are not isomorphic, or if they are isomorphic that they are absolutely irreducible. Then, there exists a prime p of good reduction for E and
$E'$
such that
$a_p(E) \neq a_p(E')$
and satisfying the inequality
Remark 1.4 Mayle–Wang, in Theorem 1.2, include a hypothesis that the elliptic curves E and
$E'$
be without complex multiplication; in Proposition 5.1 and Theorem 1.3, we have dropped this assumption. All we require here is the existence of a prime of good reduction such that
$a_p(E) \neq a_p(E')$
, which is satisfied once we assume the two elliptic curves are not
$\mathbb {Q}$
-isogenous, a consequence of Faltings’ Theorem [Reference Faltings7] (see translation in [Reference Cornell and Silverman6]).
The representation
${\bar {\rho }}_{E,\ell }$
is absolutely irreducible if and only if its image does not lies in a non-split Cartan subgroup or a Borel subgroup. In the case of
$\ell = 2$
,
${\bar {\rho }}_{E,\ell }$
is absolutely irreducible if and only if it is surjective.
We also prove another improved effective isogeny theorem which applies for elliptic curves over
$\mathbb {Q}$
which are quadratic twists of each other and do not have complex multiplication.
Theorem 1.5 Assume GRH. Let E and
$E'$
be two elliptic curves over
$\mathbb {Q}$
which are quadratic twists of each other and do not have complex multiplication. In addition, assume
${\bar {\rho }}_{E,2}$
is irreducible and the image of
$\rho _{E,2}$
contains
$-I$
. Suppose E and
$E'$
are not
$\mathbb {Q}$
-isogenous. Then, there exists a prime p of good reduction for E and
$E'$
such that
$a_p(E) \neq a_p(E')$
and satisfying the inequality
This version requires the results of Rouse and Zureick–Brown [Reference Rouse and Zureick-Brown13] which characterizes the images of the
$2$
-adic representations attached to an elliptic curve over
$\mathbb {Q}$
.
Using Theorem 1.2, Mayle–Wang [Reference Mayle and Wang10, Theorem 1] prove the following bound for Serre’s Open Image Theorem.
Theorem 1.6 Assume GRH. Let E be an elliptic curve over
$\mathbb {Q}$
without complex multiplication. Then,
A consequence of our improved effective isogeny Theorems 1.3 and 1.5 is an improvement in the constants for Serre’s Open Image Theorem.
Theorem 1.7 Assume GRH. Let E be an elliptic curve over
$\mathbb {Q}$
without complex multiplication. Then,
The Magma computational algebra system [Reference Bosma, Cannon and Playoust2] was used for verifying assertions in this article. The electronic resources are available from
2 Explicit forms of the Chebotarev Density Theorem
Let
$L/K$
be a finite Galois extension with Galois group G. Define the counting function
$\pi _C(x, L/K)$
, for a conjugacy class C of the Galois group G of
$L/K$
, to be the function
$$\begin{align*}\pi_C(x, L/K) = \left|\left\{ \mathfrak{p} \text{ a prime of } K \mid \mathfrak{p} \text{ unramified in } L/K, \left( \frac{L/K}{\mathfrak{p}} \right) = C, \, \text{N}_{K/\mathbb{Q}}(\mathfrak{p}) \leq x \right\}\right|, \end{align*}$$
where for a prime
$\mathfrak {p}$
of K unramified in
$L/K$
, the notation
$$ \begin{align} \left( \frac{L/K}{\mathfrak{p}} \right) \end{align} $$
denotes the Artin symbol which gives the Frobenius conjugacy class at
$\mathfrak {p}$
in G.
Theorem 2.1 (Chebotarev Density Theorem)
Let
$\pi _C(x,L/K)$
be as above. Then,
Effective versions of Chebotarev’s Density Theorem exist as well and we shall be applying results in which the constants are explicitly computable in terms of the absolute discriminant
$d_L$
of L as well as the degree
$n_L$
of L over
$\mathbb {Q}$
. The first of these was given by Lagarias and Odlyzko [Reference Lagarias and Odlyzko8]. Their result relies on the validity of GRH.
We now state the first explicit form of Theorem 2.1.
Theorem 2.2 [Reference Lagarias and Odlyzko8, Theorem 1.1]
There exists an effectively computable positive absolute constant
$c_1$
such that if GRH holds for the Dedekind zeta function of L, then for every
$x \geq 2$
,
$$\begin{align*}\left|\pi_C(x,L/K) - \frac{|C|}{|G|}\operatorname{\mathrm{Li}}(x)\right| \leq c_1 \left( \frac{|C|}{|G|} x^{1/2} \log(|d_L|x^{n_L}) + \log |d_L| \right). \end{align*}$$
An important corollary, one that we shall make use of, is finding an
$x_0$
such that
$\pi _C(x_0,L/K)> 0$
.
Corollary 2.3 [Reference Lagarias and Odlyzko8, Corollary 1.2]
There exists an effectively computable positive absolute constant
$c_2$
such that if GRH holds for the Artin L-functions of
$L/\mathbb {Q}$
,
$L \neq \mathbb {Q}$
, then for every conjugacy class C of G there exists a prime ideal
$\mathfrak {p}$
of K unramified in
$L/\mathbb {Q}$
such that
$$\begin{align*}\left( \frac{L/K}{\mathfrak{p}} \right) = C \end{align*}$$
and
If
$L = \mathbb {Q}$
, then
$\mathfrak {p} = (2)$
is a solution.
The above is a non-nullity result about
$\pi _C(x,L/K)$
; it asserts the size of x we must take to ensure that
$\pi _C(x,L/K)$
is nonzero, that is, there is some unramified prime ideal
$\mathfrak {p}$
of K whose Artin symbol hits C and with norm smaller than x.
Theorem 2.4 [Reference Oesterlé11, Théorème 4]
There exists an effectively computable positive absolute constant
$c_3$
such that if GRH and Artin’s Conjecture (AC) hold for the Artin L-functions of
$L/\mathbb {Q}$
,
$L \neq \mathbb {Q}$
, then for every conjugacy class C of G, we have that
for all
$x \geq 2$
such that
$x \geq c_3(\log |d_L|)^2$
.
Oesterlé [Reference Oesterlé11, Théorème 4] finds that
$c_3 = 70$
, although his proof was seemingly never published. An improvement to Lagarias and Odlyzko is given by Bach–Sorenson [Reference Bach and Sorenson1].
Theorem 2.5 [Reference Bach and Sorenson1, Theorem 5.1]
Assume GRH. Let
$K/\mathbb {Q}$
be a Galois extension of number fields, with
$K \neq \mathbb {Q}$
. Let
$d_K$
denote the discriminant of K. Let
$n_K$
denote the degree of K. Let
$C \subseteq \operatorname {\mathrm {Gal}}(K/\mathbb {Q})$
be a nonempty subset closed under conjugation. Then, there is a prime p of
$\mathbb {Q}$
unramified in
$K/\mathbb {Q}$
with
$$\begin{align*}\left( \frac{K/\mathbb{Q}}{p} \right) \subseteq C, \end{align*}$$
satisfying
for some triple
$(a,b,c)$
taken from [Reference Bach and Sorenson1, Table 3] according to the quantities
$\log |d_K|$
and
$n_K$
. We may take
$a = 4$
,
$b=2.5$
, and
$c=5$
to cover all cases of
$\log |d_K|$
and
$n_K = [K:\mathbb {Q}]$
.
A corollary to the above is given in Mayle–Wang [Reference Mayle and Wang10, Corollary 6] when we need to pick the prime p to be coprime to a given positive integer m.
Corollary 2.6 [Reference Mayle and Wang10, Corollary 6]
Assume GRH. Let
$K/\mathbb {Q}$
be a Galois extension of number fields, with
$K \neq \mathbb {Q}$
. Let m be a positive integer, and set
$\tilde {K} = K(\sqrt {m})$
. Denote
$d_{\tilde {K}}$
to be the absolute value of the discriminant of
$\tilde {K}$
. Let
$n_{\tilde {K}}$
denote the degree of
$\tilde {K}$
. Let
$C \subseteq \operatorname {\mathrm {Gal}}(K/\mathbb {Q})$
be a nonempty subset that is closed under conjugation. Then, there exists a prime number p not dividing m that is unramified in
$K/\mathbb {Q}$
with
$\left (\frac {K/\mathbb {Q}}{p}\right ) \subseteq C$
and satisfying
for some triple
$(\tilde {a},\tilde {b},\tilde {c})$
taken from [Reference Bach and Sorenson1, Table 3] according to the quantities
$\log |d_{\tilde {K}}|$
and
$n_{\tilde {K}}$
. We may take
$\tilde {a} = 4$
,
$\tilde {b} = 2.5$
, and
$\tilde {c} = 5$
to cover all cases of
$\log |d_{\tilde {K}}|$
and
$n_{\tilde {K}} = [\tilde {K}:\mathbb {Q}]$
.
For a fixed
$n_K$
, we say a triple
$(a,b,c)$
is bigger than a triple
$(a',b',c')$
(resp. a triple
$(a',b',c')$
is smaller than a triple
$(a,b,c)$
) if
for all values of
$\log |d_K|$
in a row of [Reference Bach and Sorenson1, Table 3].
We give our own version of Theorem 2.5 and Corollary 2.6. The idea is to collapse [Reference Bach and Sorenson1, Table 3] into a one-dimensional table, removing the condition on
$\log |d_{\tilde {K}}|$
so that each triple is valid for a range of
$n_{\tilde {K}}$
. We do this by picking a “pivot” triple for each column, for which all triples appearing before the pivot are absorbed into a special constant
$p_0(n_{\tilde {K}})$
, and all triples appearing after are checked to be smaller than the pivot triple.
The pivot triple in each column of [Reference Bach and Sorenson1, Table 3] is chosen to be the first one so that (2.4) holds.
Proposition 2.7 Assume GRH. Let
$K/\mathbb {Q}$
be a Galois extension of number fields with
$K \neq \mathbb {Q}$
. Let m be a positive integer, and set
$\tilde {K} = K(\sqrt {m})$
. Denote
$d_{\tilde {K}}$
to be the discriminant of
$\tilde {K}$
. Let
$n_{\tilde {K}}$
denote the degree of
$\tilde {K}/\mathbb {Q}$
. Let
$C \subseteq \operatorname {\mathrm {Gal}}(K/\mathbb {Q})$
be a nonempty subset that is closed under conjugation. Then, there exists a triple
$(\bar {a}, \bar {b}, \bar {c})$
taken from Table 1, a special constant
$p_0(n_{\tilde {K}})$
, and a prime number p not dividing m that is unramified in
$K/\mathbb {Q}$
with
$\left (\frac {K/\mathbb {Q}}{p}\right ) \subseteq C$
and satisfying
where
$n_0 = \max (72,n_{\tilde {K}})$
. If we only have an upper bound for
$n_{\tilde {K}} \le n_1$
, then we have to replace each of
$\bar a, \bar b, \bar c$
with the maximum of their values over entries in Table 1 with
$n_{\tilde {K}} \le n_1$
, respectively, and
$n_0$
with
$\max (72,n_1)$
.
Triples
$(\bar {a},\bar {b},\bar {c})$
as appearing in Proposition 2.7.

Proof We have written a program in Magma which verifies the required inequalities (2.2). For inequality (2.3), there are two parts to check. The program checks that
and the inequality
follows from Lemma 2.8.
Lemma 2.8 [Reference Mayle and Wang10, Lemma 7]
If
$K/\mathbb {Q}$
is a nontrivial finite Galois extension, then
where
$d_K$
is the absolute value of the discriminant of K.
3 The deviation group
$\delta (G)$
In this section, we wish to construct a finite group, called the deviation group, denoted
$\delta (G)$
, from which we can find a finite subset that will determine if the two representations are isomorphic or not.
Our treatment of the deviation group will follow the exposition given in Ignasi’s thesis [Reference Rodríguez12]. We note that Ignasi’s exposition is, itself, taken from Chênevert’s thesis [Reference Chênevert5], whose work follows the work of Serre [Reference Serre17] (the propositions and lemmas which appear here, with the exception of Lemma 3.8, can also be found in [Reference Chênevert5, Chapter 5]).
Let G be a group, and L be a finite extension of
$\mathbb {Q}_\ell $
, for
$\ell $
prime, with ring of integers
$\mathcal {O}_\lambda $
, maximal ideal
$\lambda $
, and residue field
$k = \mathcal {O}_\lambda /\lambda \mathcal {O}_\lambda $
. We let
$\pi $
be a uniformizer, so
$\lambda = \pi \mathcal {O}_\lambda $
. Let
$\rho _1, \rho _2: G \to \operatorname {GL}_n(\mathcal {O}_\lambda )$
be two
$\lambda $
-adic representations. We begin by extending the map
$\rho _1 \times \rho _2 : G \to \operatorname {GL}_n(\mathcal {O}_\lambda ) \times \operatorname {GL}_n(\mathcal {O}_\lambda )$
from G to the group ring
$\mathcal {O}_\lambda [G]$
.
We define the map
$\rho : \mathcal {O}_\lambda [G] \to M_n(\mathcal {O}_\lambda ) \oplus M_n(\mathcal {O}_\lambda )$
to be
Let M be the full image of
$\rho $
inside
$M_n(\mathcal {O}_\lambda ) \oplus M_n(\mathcal {O}_\lambda )$
, and consider the composition map
$\delta : G \xrightarrow {\rho } M^\times \to (M/\lambda M)^\times $
.
Definition 3.1 [Reference Rodríguez12, Definition 2.1.1]
The image
$\delta (G)$
of G inside
$(M/\lambda M)^\times $
is called the deviation group of the pair of representations
$\rho _1,\rho _2$
.
Remark 3.2 Since M is a subalgebra of
$R = M_n(\mathcal {O}_\lambda ) \times M_n(\mathcal {O}_\lambda )$
, it might be tempting to think
$\delta (G)$
is a subgroup of
$(R/\lambda R)^\times = \operatorname {GL}_n(k) \times \operatorname {GL}_n(k)$
but this may not be the case. See the remark after [Reference Rodríguez12, Definition 2.1.1].
The deviation group turns out to be finite, as described by the following proposition.
Proposition 3.3 [Reference Rodríguez12, Proposition 2.1.2]
The group
$\delta (G)$
is finite, and in particular, we have
$|\delta (G)| \leq |k|^{2n^2}$
.
Proof Note that M is a submodule of the free
$\mathcal {O}_\lambda $
-module
$M_n(\mathcal {O}_\lambda ) \oplus M_n(\mathcal {O}_\lambda )$
. Since
$\mathcal {O}_\lambda $
is a local ring, M is free and is of rank r, where r satisfies
Given M is a
$\mathcal {O}_\lambda $
-module,
$M/\lambda M$
is a k-algebra of dimension r. Hence,
as claimed.
Remark 3.4 A similar bound on
$|\delta (G)|$
is employed by Mayle–Wang in their proof of Theorem 1.2, although they do not explicitly mention the deviation group. See the proof in [Reference Mayle and Wang10, Theorem 2].
Let us turn our attention now to the practical use of
$\delta (G)$
, that being its ability to help us determine when two representations are isomorphic.
Proposition 3.5 [Reference Rodríguez12, Proposition 2.1.3]
Let
$\Sigma \subseteq G$
be a subset that surjects onto
$\delta (G)$
. Then,
$\rho _1 \sim \rho _2$
if and only if
$\operatorname {\mathrm {tr}}(\rho _1(g)) = \operatorname {\mathrm {tr}}(\rho _2(g))$
for all
$g \in \Sigma $
.
Before we introduce the next proposition, some further explanations are needed (following [Reference Rodríguez12]). We assume now the representations
$\rho _1, \rho _2 : G \to \operatorname {GL}_n(\mathcal {O}_\lambda )$
are not isomorphic, that is, they are not conjugate in
$\operatorname {GL}_n(\mathcal {O}_\lambda )$
, but that the residual representations
$\bar {\rho }_1$
and
$\bar {\rho }_2$
obtained from
$\rho _1$
and
$\rho _2$
by reduction modulo
$\lambda $
are isomorphic. We then have an equality
$\bar {\rho }_1 = P\bar {\rho }_2P^{-1}$
for some matrix
$P \in M_n(k)$
.
Define
$\beta $
to be the largest integer such that
$\rho _1$
and
$\rho _2$
are conjugate modulo
$\lambda ^{\beta }$
, that is, there is a matrix
$P \in \operatorname {GL}_n(\mathcal {O}_\lambda )$
such that
$\rho _1 \equiv P\rho _2P^{-1} \ (\mathrm {mod}\ \lambda ^\beta )$
; we then have
$\beta \geq 1$
, since
$\bar {\rho }_1 \cong \bar {\rho }_2$
. In addition, there is an integer
$\alpha \geq 1$
such that
$\operatorname {\mathrm {tr}}(\rho _1) \equiv \operatorname {\mathrm {tr}}(\rho _2) \ (\mathrm {mod}\ \lambda ^\alpha )$
and
$\operatorname {\mathrm {tr}}(\rho _1) \not \equiv \operatorname {\mathrm {tr}}(\rho _2) \ (\mathrm {mod}\ \lambda ^{\alpha +1})$
; in particular,
$\rho _1$
and
$\rho _2$
are not conjugate modulo
$\lambda ^{\alpha +1}$
, so
$\beta \leq \alpha $
. Given that
$\rho _1$
and
$\rho _2$
are conjugate modulo
$\lambda ^\beta $
but not conjugate modulo
$\lambda ^{\beta +1}$
, if we replace
$\rho _2$
with a conjugate we may assume
$\rho _1 \equiv \rho _2 \ (\mathrm {mod}\ \lambda ^\beta )$
but
$\rho _1 \not \equiv \rho _2 \ (\mathrm {mod}\ \lambda ^{\beta +1})$
.
Hence, for any
$g \in G$
, we have
for some
$\theta _g \in M_n(\mathcal {O}_\lambda )$
and
$\pi $
a uniformizer of
$\mathcal {O}_\lambda $
. Rearranging, we get an equation for
$\rho _2(g)$
of the form
where
$I_n$
is the
$n \times n$
identity matrix. Let
$\theta : G \to M_n(\mathcal {O}_\lambda )$
be the map
$g \to \theta _g\rho _1(g)^{-1}$
, and notice that (3.2) becomes
Proposition 3.6 [Reference Rodríguez12, Proposition 2.2.1]
Let
$\rho _1, \rho _2 : G \to \operatorname {GL}_n(\mathcal {O}_\lambda )$
be representations that are not isomorphic, and suppose
$\bar {\rho }_1, \bar {\rho }_2: G \to \operatorname {GL}_n(k)$
are isomorphic. Let
$\beta $
be the largest integer such that
$\rho _1$
and
$\rho _2$
are conjugate modulo
$\lambda ^\beta $
, and as above, assume
$\rho _2$
has been replaced by a conjugate such that
$\rho _1 \equiv \rho _2 \ (\mathrm {mod}\ \lambda ^\beta )$
. Let
$$ \begin{align} \varphi: G & \to M_n(k) \rtimes \operatorname{GL}_n(k)\nonumber \\ & g \mapsto (\theta(g) \ (\mathrm{mod}\ \lambda), \rho_1(g) \ (\mathrm{mod}\ \lambda)), \end{align} $$
where the semidirect product is with respect to the action of
$\operatorname {GL}_n(k)$
on
$M_n(k)$
by conjugation, that is, multiplication is given by
Then,
$\varphi $
is a group homomorphism which factors through the deviation group
$\delta (G)$
.
Remark 3.7 The homomorphism
$\delta (G) \twoheadrightarrow \varphi (G)$
may not be injective. See [Reference Rodríguez12, Remark 2.2.2].
Lastly, we state a general lemma regarding determinants of matrices that we shall employ later.
Lemma 3.8 [Reference Rodríguez12, Lemma 2.2.3]
Let R be a discrete valuation ring with uniformizer
$\pi $
, and F its field of fractions. For any
$A \in \operatorname {GL}_n(F)$
,
It can be difficult to compute the exact size of
$\delta (G)$
, or find a tighter upper bound for it. We will, in the following section, work to replace
$\delta (G)$
with
$\varphi (G)$
in the case of
$2$
-adic representations. The codomain of
$\varphi $
is easily understood, and hence a bound for
$|\varphi (G)|$
is easily computable. This is what allows us to prove Theorem 1.3.
4 The tools of Mayle-Wang
The methodology of Mayle–Wang relies on the following proposition that is due to Serre (a proof of which can be found in [Reference Bucur and Kedlaya3, Theorem 4.7]). The proposition which follows is a refined version of Serre’s original argument due to Mayle–Wang [Reference Mayle and Wang10, Proposition 12] in which we have reworked the statement and proof to follow the work and notation done in Section 3. We note that the statement is similar to that of Proposition 3.5: here, we show that if the representations are not isomorphic, then their traces must disagree on some finite set. While the proofs are very similar, the advantage of the following proposition is that it is in a form to which we may readily apply Chebotarev.
Proposition 4.1 [Reference Mayle and Wang10, Proposition 12]
Let n be a positive integer. Let G be a group and
$\rho _1, \rho _2 : G \rightarrow \operatorname {GL}_n(\mathcal {O}_\lambda )$
be representations, and
$\delta (G)$
the deviation group of G of the two representations
$\rho _1$
and
$\rho _2$
. Suppose that there exists an element
$g \in G$
such that
$\operatorname {\mathrm {tr}} \rho _1(g) \not = \operatorname {\mathrm {tr}} \rho _2(g)$
. Then, there exists a subset
$C \subseteq \delta (G)$
for which:
-
(1) the set C is non-empty and closed under conjugation by
$\delta (G)$
; and -
(2) if the image in
$\delta (G)$
of an element
$g \in G$
belongs to C, then
$\operatorname {\mathrm {tr}} \rho _1(g) \not = \operatorname {\mathrm {tr}} \rho _2(g)$
.
Proof Let
$R :=M_n(\mathcal {O}_\lambda ) \times M_n(\mathcal {O}_\lambda )$
. Let M denote the
$\mathcal {O}_\lambda $
-subalgebra of R generated by the image of G under the product map
Recall that
$\delta (G)$
is the image of G under
$\rho _1 \times \rho _2$
in
$M/\lambda M$
.
Let
$\alpha $
be the largest nonnegative integer such that for each
$g \in G$
, one has that
As M is a
$\mathcal {O}_\lambda $
-subalgebra generated by the image of G under
$\rho _1 \times \rho _2$
, it follows that the congruence
$\operatorname {\mathrm {tr}} x_1 \equiv \operatorname {\mathrm {tr}} x_2 \ (\mathrm {mod}\ \lambda ^\alpha )$
holds for each pair
$(x_1,x_2) \in M$
. We obtain the
$\mathcal {O}_\lambda $
-module homomorphism
$\phi : M \to \mathcal {O}_\lambda $
given by
Since
$\phi (\lambda M) \subseteq \lambda \mathcal {O}_\lambda $
, we may consider the induced
$\mathcal {O}_\lambda /\lambda \mathcal {O}_\lambda $
-module homomorphism
$\bar {\phi }:M/\lambda M \to \mathcal {O}_\lambda /\lambda \mathcal {O}_\lambda $
.
Let
$C = \delta (G) \setminus \ker \bar {\phi }$
be the set of elements in
$\delta (G)$
whose image under
$\bar {\phi }$
in
$M/\lambda M$
all are nonzero. From the definition of
$\alpha $
and the linearity of the trace map, there exists
$g_0 \in G$
such that
Note that the image of
$(\rho _1 \times \rho _2)(g_0)$
in
$\delta (G)$
is contained in C, so C is nonempty. Also, C is closed under conjugation since the trace map is invariant under conjugation.
Finally, suppose that
$g \in G$
is such that the image of g in
$\delta (G)$
is contained in C. Then,
$\phi (\rho _1 \times \rho _2(g)) \not \in \lambda \mathcal {O}_\lambda $
, and in particular,
$\operatorname {\mathrm {tr}} \rho _1(g) \neq \operatorname {\mathrm {tr}} \rho _2(g)$
.
Remark 4.2 In the notation
$\delta (G)$
and
$\varphi (G),$
we suppress the dependence on the representations
$\rho _1$
and
$\rho _2$
as they are usually fixed in the context.
We now give an analogous version of Proposition 4.1 in the case, where the mod 2 representations are isomorphic and absolutely irreducible. This allows us to replace
$\delta (G)$
in Proposition 4.1 with
$\varphi (G)$
from Proposition 3.6, a set which is easier to estimate the size of. The idea to replace
$\delta (G)$
with
$\varphi (G)$
comes from Chênevert [Reference Chênevert5, p. 114], in which he gives a remark that, in the
$2$
-adic case, Serre [Reference Serre17] implies that
$\delta (G) \cong \varphi (G)$
. However, in a conversation with Chênevert, Serre mentions he might not have proven the map
$\delta (G) \to \varphi (G)$
was an isomorphism, but, in an unpublished letter to Tate, that the
$\alpha $
in the proof of Proposition 3.5 is equal to the
$\beta $
coming from the construction of the function
$\varphi $
if the residual representation is surjective. We show, in the 2-adic case, that
$\alpha = \beta $
, and that we can replace
$\delta (G)$
in Proposition 4.1 with
$\varphi (G)$
and get the same conclusion, that is, there is a subset
$C \subseteq \varphi (G)$
that is a conjugacy class, and if
$g \in G$
is such that
$\varphi (g) \in C$
, then
$\operatorname {\mathrm {tr}} \rho _1(g) \neq \operatorname {\mathrm {tr}} \rho _2(g)$
.
In order to prove this special case, we require a theorem of Carayol [Reference Carayol4].
Theorem 4.3 [Reference Carayol4, Theorem 1]
Let A be a local ring, R an A-algebra, and let
$\rho _1, \rho _2 : R \to M_n(A)$
be two representations of R of the same dimension n. Suppose that the residual representation
$\bar {\rho } : R \otimes _A F \to M_n(F)$
, where F is the residue field of A, is absolutely irreducible. Suppose that the traces for
$\rho _1$
and
$\rho _2$
are the same for every
$r \in R$
. Then,
$\rho _1$
and
$\rho _2$
are isomorphic as representations, that is, there exists a matrix
$Q \in \operatorname {GL}_n(A)$
such that
$\rho _1(r) = Q\rho _2(r)Q^{-1}$
for all
$r \in R$
.
We now prove the special case.
Proposition 4.4 Let n be a positive integer. Let G be a group and
$\rho _1, \rho _2 : G \rightarrow \operatorname {GL}_n(\mathbb {Z}_2)$
be representations, and suppose their reductions
$\bar {\rho }_1, \bar {\rho }_2$
are isomorphic and absolutely irreducible. Suppose that there exists an element
$g \in G$
such that
$\operatorname {\mathrm {tr}} \rho _1(g) \not = \operatorname {\mathrm {tr}} \rho _2(g)$
. Then, there exists a subset
$C \subseteq \varphi (G)$
for which:
-
(1) the set C is non-empty and closed under conjugation by
$\varphi (G)$
; and -
(2) if the image in
$\varphi (G)$
of an element
$g \in G$
belongs to C, then
$\operatorname {\mathrm {tr}} \rho _1(g) \not = \operatorname {\mathrm {tr}} \rho _2(g)$
.
Proof Our setup begins, as it did, in Section 3. Let
$\alpha $
be the largest nonnegative integer such that for each
$g \in G$
, we have
In addition, we let
$\beta $
be the largest integer such that
$\rho _1$
and
$\rho _2$
are conjugate modulo
$2^{\beta }$
, that is, there is a matrix
$P \in \operatorname {GL}_n(\mathbb {Z}_2)$
such that
$\rho _1 \equiv P\rho _2P^{-1} \ (\mathrm {mod}\ 2^\beta )$
. As demonstrated before, we have
$\beta \leq \alpha $
. Also, given that
$\rho _1$
and
$\rho _2$
are conjugate modulo
$2^\beta $
but not conjugate modulo
$2^{\beta +1}$
, if we replace
$\rho _2$
with a conjugate
$P\rho _2 P^{-1}$
for
$P \in \operatorname {GL}_n(\mathbb {Z}_2)$
, we may assume
This implies
$P\rho _2(g)P^{-1} - \rho _1(g) \equiv 0 \ (\mathrm {mod}\ 2^{\beta })$
for any
$g \in G$
. In particular, we get
$P\rho _2(g)P^{-1} - \rho _1(g) = \theta _g2^\beta $
for some
$\theta _g \in M_n(\mathbb {Z}_2)$
, which we can write as
In particular, note that
by the invariance of trace under conjugation.
We now show
$\alpha = \beta $
. Extend the maps
$\rho _1,\rho _2$
to the group ring
$\mathbb {Z}/2^\alpha \mathbb {Z}[G]$
by
$\rho _i(\sum a_jg_j) = \sum a_j\rho _i(g_j)$
, for
$i = 1,2$
and
$a_j \in \mathbb {Z}/2^\alpha \mathbb {Z}$
and
$g_j \in G$
. Then, notice that
$$ \begin{align} \operatorname{\mathrm{tr}}(\rho_1(\sum a_jg_j)) \ (\mathrm{mod}\ 2^\alpha) & \equiv \operatorname{\mathrm{tr}}(\sum a_j \rho_1(g_j)) \ (\mathrm{mod}\ 2^{\alpha})\nonumber \\ & \equiv \sum a_j\operatorname{\mathrm{tr}}(\rho_1(g_j)) \ (\mathrm{mod}\ 2^{\alpha}) \nonumber\\ & \equiv \sum a_j \operatorname{\mathrm{tr}}(\rho_2(g_j)) \ (\mathrm{mod}\ 2^{\alpha}) \nonumber\\ & \equiv \operatorname{\mathrm{tr}}(\rho_2(\sum a_jg_j)) \ (\mathrm{mod}\ 2^\alpha). \end{align} $$
Since we satisfy the hypotheses of Theorem 4.3 with
$A = \mathbb {Z}/2^{\alpha }\mathbb {Z}$
and
$R = \mathbb {Z}/2^{\alpha }\mathbb {Z}[G]$
, we can find a matrix
$Q \in \operatorname {GL}_n(\mathbb {Z}/2^{\alpha }\mathbb {Z})$
such that
$\rho _1(g) \equiv Q\rho _2(g)Q^{-1} \ (\mathrm {mod}\ 2^{\alpha })$
for all
$g \in G$
. However,
$\beta $
is the largest integer such that
$\rho _1$
and
$\rho _2$
are conjugate modulo
$2^{\beta }$
, so
$\alpha \leq \beta $
, implying
$\alpha = \beta $
.
Recall, from (3.4), the map
$\varphi : G \to M_n(\mathbb {F}_2) \rtimes \operatorname {GL}_n(\mathbb {F}_2)$
is defined by
We note our use of the notation
$[N]_2$
, for
$N \in M_n(\mathbb {Z}_2)$
, to denote the residue class of N modulo
$2$
.
Define the map
$\phi ' : M_n(\mathbb {F}_2) \rtimes \operatorname {GL}_n(\mathbb {F}_2) \to \mathbb {F}_2$
by
where the product of matrices is taken to be the action of
$\operatorname {GL}_n(\mathbb {F}_2)$
on
$M_n(\mathbb {F}_2)$
, and the trace is considered to be modulo
$2$
. By (4.5), notice
$$ \begin{align} \phi'(\varphi(g)) & = \operatorname{\mathrm{tr}}([\theta_g\rho_1(g)^{-1}]_2[\rho_1(g)]_2) \nonumber\\ & = \operatorname{\mathrm{tr}}([\theta_g\rho_1(g)^{-1}\rho_1(g)]_2) \nonumber\\ & = \operatorname{\mathrm{tr}}([\theta_g]_2) \\ & = [\operatorname{\mathrm{tr}}(\theta_g)]_2 \nonumber\\ & = [2^{-\alpha}(\operatorname{\mathrm{tr}}(\rho_2(g)) - \operatorname{\mathrm{tr}}(\rho_1(g)))]_2,\nonumber \end{align} $$
where we have used (4.3) above (with
$\beta $
replaced with
$\alpha $
, since
$\alpha = \beta $
) and the fact that, for a matrix
$N \in M_n(\mathbb {Z}_2)$
with
$\operatorname {\mathrm {tr}}(N) = \sum _{i=1}^{n} a_{ii}$
for entries
$a_{ii} \in \mathbb {Z}_2$
along the diagonal, we have
$$ \begin{align} \operatorname{\mathrm{tr}}([N]_2) & = \sum_{i = 1}^{n} [a_{ii}]_2 \nonumber\\ & = \left[ \sum_{i = 1}^{n} a_{ii} \right]_2 \nonumber\\ & = \left[\operatorname{\mathrm{tr}} (N)\right]_2 \end{align} $$
which shows the final equality (noting our use of
$[x]_2$
in (4.8) to denote the residue class of a
$2$
-adic integer
$x \in \mathbb {Z}_2$
).
Let C be the set of elements in
$\varphi (G)$
that take a nonzero value under the map
$\phi '$
. From the definition of
$\alpha $
and the linearity of the trace map, there exists
$g_0 \in G$
such that
Note that the image of
$g_0$
in
$\varphi (G)$
is inside C, so C is nonempty. In addition, let
${\phi (h) \in \phi (G)}$
for some
$h \in G$
; then, given
$\varphi $
is a homomorphism (Proposition 3.6) and by (4.7) and the invariance under conjugation of the trace map,
$$ \begin{align} \phi'(\varphi(h)\varphi(g)\varphi(h)^{-1}) & = \phi'(\varphi(hgh^{-1})) \nonumber\\ & = [2^{-\alpha}(\operatorname{\mathrm{tr}}(\rho_2(hgh^{-1})) - \operatorname{\mathrm{tr}}(\rho_1(hgh^{-1})))]_2 \nonumber\\ & = [2^{-\alpha}(\operatorname{\mathrm{tr}}(\rho_2(h)\rho_2(g)\rho_2(h)^{-1}) - \operatorname{\mathrm{tr}}(\rho_1(h)\rho_1(g)\rho_1(h)^{-1}))]_2 \nonumber\\ & = [2^{-\alpha}(\operatorname{\mathrm{tr}}(\rho_2(g)) - \operatorname{\mathrm{tr}}(\rho_1(g)))]_2 \nonumber\\ & = \phi'(\varphi(g)) \nonumber\\ & \neq 0, \end{align} $$
so C is closed under conjugation. Finally, suppose that
$g \in G$
is such that the image of g in
$\varphi (G)$
is contained in C. Then,
$\phi '(\varphi (g)) \not = 0$
, in particular,
$\operatorname {\mathrm {tr}} \rho _1(g) \neq \operatorname {\mathrm {tr}} \rho _2(g)$
.
5 Improved bounds for the effective isogeny theorem
For a prime
$\ell $
and an elliptic curve E, we define
We begin with the proof of Proposition 5.1. We note that the work which follows is the same as that of Mayle–Wang [Reference Mayle and Wang10], except for our use of Proposition 2.7 and Table 1.
Let E and
$E'$
be two elliptic curves over
$\mathbb {Q}$
and let
$A = E \times E'$
. Let
$G = \operatorname {\mathrm {Gal}}(\mathbb {Q}(A[2^{\infty }])/\mathbb {Q})$
. We may regard the
$2$
-adic representations
$\rho _{E,2}$
and
$\rho _{E',2}$
as representations of G instead of
$G_{\mathbb {Q}}$
since
$\mathbb {Q}(E[2^\infty ])$
and
$\mathbb {Q}(E'[2^\infty ])$
are subfields of
$\mathbb {Q}(A[2^{\infty }])/\mathbb {Q}$
.
The representation
$\rho _{A,2} = \rho _{E,2} \times \rho _{E',2}$
is a continuous homomorphism
$G \rightarrow \operatorname {GL}_2(\mathbb {Z}_2) \times \operatorname {GL}_2(\mathbb {Z}_2)$
with image being M as defined in the proof of Proposition 4.1. Since
$2 M$
is closed inside M, we see that
$\delta (G)$
is a closed subgroup of G and hence by the fundamental theorem of infinite Galois theory corresponds to a finite Galois extension
$K/\mathbb {Q}$
with
$K \subseteq \mathbb {Q}(A[2^\infty ])/\mathbb {Q}$
.
Since
$K \subseteq \mathbb {Q}(A[2^n])$
for some
$n \in \mathbb {N}$
, we have that
for some
$n \in \mathbb {N}$
and by [Reference Mayle and Wang10, Proposition 12],
The set
$\varphi (G)$
(defined in Proposition 3.6) is a subset of a very explicit semi-direct product, and estimating
$|\varphi (G)|$
gives a smaller bound.
Proposition 5.1 Assume GRH. Let E and
$E'$
be two elliptic curves over
$\mathbb {Q}$
. Suppose E and
$E'$
are not
$\mathbb {Q}$
-isogenous. Let
$\delta (G)$
be the deviation group of G with respect to the
$2$
-adic representations
$\rho _{E,2}$
and
$\rho _{E',2}$
.
Choose the triple
$(\bar {a}, \bar {b}, \bar {c})$
from Table 1 for
$n_0 = \max (72, 2|\delta (G)|)$
. Then, there exists a prime p of good reduction for E and
$E'$
, such that
$a_p(E) \neq a_p(E')$
such that
Furthermore, if E and
$E'$
are such that their mod 2 representations are isomorphic and absolutely irreducible, then we may replace
$|\delta (G)|$
with
$|\varphi (G)|$
.
Proof Let
$\mathcal {O}_\lambda = \mathbb {Z}_2$
. Let
$A = E \times E'$
and apply Proposition 4.1 with
$\ell = 2$
,
$n = 2$
,
$G = \operatorname {\mathrm {Gal}}(\mathbb {Q}(A[2^{\infty }])/\mathbb {Q})$
, and the
$2$
-adic representations
$\rho _1 = \rho _{E,2}$
and
$\rho _2 = \rho _{E',2}$
. By Faltings’ Theorem [Reference Faltings7], since the two elliptic curves E and
$E'$
are not
$\mathbb {Q}$
-isogenous,
$\rho _1$
and
$\rho _2$
are not isomorphic; therefore, by Serre [Reference Serre14, pp. IV–15], there is some prime p such that
$a_p(E) \neq a_p(E')$
. By Proposition 4.1, there exists a conjugacy class
$C \subseteq \delta (G)$
obeying the stated conclusion of this proposition.
Let K be the subfield of
$\mathbb {Q}(A[2^\infty ])$
for which
$\operatorname {\mathrm {Gal}}(K/\mathbb {Q}) = \delta (G)$
. Choosing
${m = \operatorname {\mathrm {rad}}(N_{E} N_{E'})}$
, Proposition 2.7 produces a prime p not dividing m such that
$\left (\frac {K/\mathbb {Q}}{p}\right ) \subseteq C$
and
where
$n_0 = \max (72, 2 |\delta (G)|)$
and
$\bar {a},\bar {b},\bar {c}$
are the maximum of their values over entries in Table 1 with
$n_{\tilde {K}} \le 2 |\delta (G)|$
, respectively. It follows from Proposition 4.1 that
and consequently
$a_p(E) \neq a_p(E')$
.
The abelian variety A has good reduction at some prime q if and only if both E and
$E'$
have good reduction at q. Thus,
$K/\mathbb {Q}$
is unramified outside of the prime divisors of
$m = N_E N_{E'}$
. As
$\tilde {K}$
is the compositum of K and
$\mathbb {Q}(\sqrt {m})$
, the primes that ramify in
$\tilde {K}$
are precisely those that ramify in K or in
$\mathbb {Q}(\sqrt {m})$
. Since
$\operatorname {\mathrm {rad}}(d_{\mathbb {Q}(\sqrt {m})}) \mid \operatorname {\mathrm {rad}}(2m) = \operatorname {\mathrm {rad}}(2N_E N_{E'})$
, and rad
$(d_K) \mid $
rad
$(2N_E N_{E'})$
, we have that
Now, applying Lemma 2.8 to (5.4) gives us
which matches (5.3).
To prove the final statement, note if
$\bar {\rho }_{E,2}$
and
$\bar {\rho }_{E',2}$
are isomorphic and absolutely irreducible, then we instead apply Proposition 4.4 over Proposition 4.1, in which case
$\delta (G)$
is replaced with
$\varphi (G)$
; in particular,
$|\delta (G)|$
can be replaced with
$|\varphi (G)|$
in (5.3).
Now we give a proof of Theorem 1.3.
Proof of Theorem 1.3
We split our analysis into two cases. If the mod
$2$
representations are not isomorphic, then mod
$2$
already distinguishes the traces. Define
by
$\bar {\rho }_2(x) = (\bar {\rho }_{E,2}(x), \bar {\rho }_{E',2}(x))$
. Let
$G_2 = \bar {\rho }_2(G_{\mathbb {Q}}) \subset \operatorname {GL}_2(\mathbb {Z}/2\mathbb {Z}) \times \operatorname {GL}_2(\mathbb {Z}/2\mathbb {Z})$
be the image of the map
$\bar {\rho }_2$
. Let
Apply Proposition 2.7 to the field
$L = \mathbb {Q}(E[2],E'[2])$
, whose Galois group is
$G_2$
, the conjugacy class
$C_2$
given in (5.7), and
$m = \operatorname {\mathrm {rad}}(N_{E} N_{E'})$
, so that we get a prime p unramified in L and
$p \nmid m$
such that
$a_p(E) \not \equiv a_p(E') \ (\mathrm {mod}\ 2)$
(implying
$a_p(E) \neq a_p(E')$
) and satisfying
$$ \begin{align} p & \leq \max((\bar{a} \log |d_{\tilde{L}}| + \bar b n_{\tilde{L}} + \bar{c})^2, p_0(n_{\tilde{L}})) \nonumber\\ & \le \left( 1.755 \left( (2 n_L-1)\log\operatorname{\mathrm{rad}}(d_{\tilde{L}}) + 2 n_L\log(2 n_L) \right) + 0.23 \cdot 2 n_L + 6.8 \right). \end{align} $$
Taking
$[L:\mathbb {Q}] \leq |\operatorname {GL}_2(\mathbb {F}_2)|^2 = 6^2 = 36$
gives us
$$ \begin{align} p & \leq \left( 1.745 \left( 71 \log\operatorname{\mathrm{rad}}(d_{\tilde{L}}) + 72 \log 72 \right) + 72 \cdot 0.23 + 6.8 \right)^2 \nonumber\\ & \leq \left( 124 \log\operatorname{\mathrm{rad}}(2N_E N_{E'}) + 561 \right)^2. \end{align} $$
Next, assume that the mod 2 representations
$\rho _1 = \bar {\rho }_{E,2}$
and
$\rho _2 = \bar {\rho }_{E',2}$
are isomorphic and absolutely irreducible. Apply Proposition 5.1, and replace
$\delta (G)$
with
$\varphi (G)$
(since the mod 2 representations are isomorphic and absolutely irreducible) to get a prime p such that
$a_p(E) \neq a_p(E')$
and satisfying
From (3.2) and Lemma 3.8, we have for any
$g \in G$
,
$$ \begin{align} \det(\rho_2(g)) & = \det((I_2+2^\beta\theta(g))\rho_1(g)) \nonumber\\ & = (1+2^{\beta}\operatorname{\mathrm{tr}}(\theta(g)) + O(2^{2\beta}))\det(\rho_1(g)). \end{align} $$
As we have
$\det \rho _1 = \det \rho _2$
being the cyclotomic character, so the above can be rewritten as
$0 = 2^{\beta }\operatorname {\mathrm {tr}}(\theta (g))+O(2^{2\beta })$
, which, after multiplying through by
$2^{-\beta }$
implies
In particular, the map
$\varphi $
from Proposition 3.6 takes values in
$M_2^0(\mathbb {F}_2) \rtimes \operatorname {GL}_2(\mathbb {F}_2)$
, where
$M_2^0(\mathbb {F}_2)$
denotes the matrices with trace
$0$
with entries in
$\mathbb {F}_2$
. Therefore, we have
$|\varphi (G)| \leq |M_2^0(\mathbb {F}_2) \rtimes \operatorname {GL}_2(\mathbb {F}_2)| = 8 \cdot 6 = 48$
. We find from Proposition 2.7 that
$$ \begin{align} p & \leq (1.745(95\log\operatorname{\mathrm{rad}}(2N_E N_{E'}) + 96\log(96)) +96 \cdot 0.23 + 6.8)^2 \nonumber\\ & \leq (166 \log\operatorname{\mathrm{rad}}(2N_E N_{E'}) + 794)^2. \end{align} $$
We now improve the bound in (5.11) by using the following two results.
Proposition 5.2 Let G be a group and
$\rho _1, \rho _2 {\kern-1pt}:{\kern-1pt} G {\kern-1pt}\rightarrow{\kern-1pt} \operatorname {GL}_2(\mathbb {Z}_2)$
be a group homomorphism, and suppose the mod 2 representations
$\bar {\rho }_1, \bar {\rho }_2$
are isomorphic. Let
$\Xi $
be the elements
$g \in G$
such that the characteristic polynomials of
$\rho _1(g)$
and
$\rho _2(g)$
coincide. Then, for
$g \in \Xi $
, the order of
$\delta (g)$
in
$\delta (G)$
is
$\le 3$
.
Proof See [Reference Chênevert5, Proposition 5.5.6].
Corollary 5.3 Let G be a group and
$\rho _1, \rho _2 : G \rightarrow \operatorname {GL}_2(\mathbb {Z}_2)$
be a group homomorphism, and suppose the mod 2 representations
$\bar {\rho }_1, \bar {\rho }_2$
are isomorphic. Let
${\pi : \delta (G) \twoheadrightarrow \bar G}$
be a quotient having a conjugacy class
$C \subseteq \bar G$
of order
$> 3$
. If
$g \in G$
is such that
${\pi (\delta (g)) \in C}$
, then
$g \not \in \Xi $
.
From (5.1) and (5.2), the possible sizes of
$\delta (G)$
are
As the possible orders are small, it is possible to enumerate in Magma all isomorphism classes of groups of these sizes. The group
$\delta (G)$
therefore lies in an explicit finite list which can be computed.
By Corollary 5.3, if
$\delta (G)$
has a quotient
$\bar G$
with an element of order
$>3$
, then we may replace
$\delta (G)$
by
$\bar G$
. We check this in Magma for each value of
$|\delta (G)|$
and find that either
$\delta (G)$
has such a quotient with strictly smaller size in the given list of (5.12) or it is in a small list of problematic groups. We list for each size
$|\delta (G)|$
, the Magma labels of the isomorphism classes of the problematic groups of that order.
Consider the homomorphism
$\varphi : \delta (G) \rightarrow M_2^0(\mathbb {F}_2) \rtimes \operatorname {GL}_2(\mathbb {F}_2)$
. The possible orders of the image are:
Using Magma, we check if
$|\delta (G)| \ge 32$
, there is no homomorphism from a problematic group to a subgroup of order
$24$
or
$48$
in the codomain of
$\varphi $
. Hence, either
$|\delta (G)| \le 24$
or the image of
$\varphi $
is
$\le 16$
. In either case, we can replace
$\delta (G)$
by a quotient of order
$\le 24$
. Thus, we obtain the same bound as in (5.9) using Proposition 2.7.
6 The results of Rouse and Zureick–Brown on
$2$
-adic images
The
$2$
-adic representation
$\rho _{E,2} : G_{\mathbb {Q}} \rightarrow \operatorname {GL}_2({\mathbb {Z}}_2)$
of an elliptic curve E over
${\mathbb {Q}}$
has open image in
$\operatorname {GL}_2({\mathbb {Z}}_2)$
and the properties that
$\det \rho _{E,2} : G_ {\mathbb {Q}} \rightarrow {\mathbb {Z}}_2^\times $
is surjective and
$\rho _{E,2}(c)$
is an element with determinant
$-$
1 and trace
$0$
for a complex conjugation. With this in mind, the authors in [Reference Rouse and Zureick-Brown13] make the following definition.
Definition 6.1 An open subgroup
$H \subseteq \operatorname {GL}_2({\mathbb {Z}}_2)$
is arithmetically maximal if:
-
(1)
$\det : H \rightarrow {\mathbb {Z}}_2^\times $
is surjective; -
(2) there is an element of H with determinant
$-1$
and trace
$0$
; and -
(3) there is no subgroup K satisfying (1) and (2) with
$H \subsetneq K$
and so that the genus of
$X_K$
is
$\ge 2$
.
The idea behind this definition is that arithmetically maximal subgroups
${H \subseteq \operatorname {GL}_2(\mathbb {Z}_2)}$
are maximal among the subgroups H satisfying (1) and (2), except possibly when H is contained in a subgroup K such that
$X_K$
has genus
$\le 1$
. For instance, if
$H \subsetneq K$
and
$X_K$
has genus
$\ge 2$
, it would be easier and sufficient to determine the
$\mathbb {Q}$
-rationals point
$X_K$
rather than
$X_H$
.
For an arithmetically maximal subgroup H, either
$X_H$
has infinitely many
$\mathbb {Q}$
-rational points (hence has genus
$\le 1$
) or
$X_H$
has finitely many
$\mathbb {Q}$
-rational points. The union of the latter cases leads to a finite list of j-invariants.
In [Reference Rouse and Zureick-Brown13], it is shown there are
$727$
arithmetically maximal subgroups
$H \subseteq \operatorname {GL}_2(\mathbb {Z}_2)$
up to conjugation such that
$-I \in H$
. Among these, there are
$408$
which have genus
$\le 1$
and
$202$
of these are such that
$X_H$
has infinitely many
$\mathbb {Q}$
-rational points.
From [Reference Rouse and Zureick-Brown13, Theorem 1.1], we may determine the possible images of
$\rho _{E,2}$
when the image of
$\rho _{E,2}$
contains
$-I$
as follows.
Theorem 6.2 Let
$H \subseteq \operatorname {GL}_2(\mathbb {Z}_2)$
be a subgroup containing
$-I$
and let
$E/\mathbb {Q}$
be an elliptic curve such that the image of
$\rho _{E,2}$
is contained in a conjugate of H. Then, one of the following holds:
-
(1) The modular curve
$X_H$
has infinitely many
$\mathbb {Q}$
-rational points (hence has genus
$\le 1$
). -
(2) The elliptic curve E has complex multiplication.
-
(3) The j-invariant of E is one of
(6.1)
$$ \begin{align} & 2^{11}, 2^4 \cdot 17^3, 4097^3/2^4, 257^3/2^8, -857985^3/62^8, 919425^3/496^4, \\ \notag & -3 \cdot 18249920^3/17^{16}, 7 \cdot 1723187806080^3/79^{16}. \end{align} $$
We rephrase the above theorem for the purposes of proving the main results of this article.
Theorem 6.3 Let
$E/\mathbb {Q}$
be an elliptic curve without complex multiplication. Suppose the image of
$\rho _{E,2}$
contains
$-$
I. Then,
$\rho _{E,2}(G)$
is one of
$202$
arithmetically maximal groups listed in [Reference Rouse and Zureick-Brown13] which have infinitely many
$\mathbb {Q}$
-rational points, or the j-invariant of E appears in (6.1).
7 Improved bounds for Serre’s Open Image Theorem
In Theorem 1.3, there is a hypothesis that
${\bar {\rho }}_{E,2} \simeq {\bar {\rho }}_{E',2}$
is absolutely irreducible. While we do not have an argument to remove this condition and achieve better bounds than Theorem 1.2, we are able to do so in the case when E and
$E'$
are quadratic twists of each other and do not have complex multiplication.
Proof of Theorem 1.5
Suppose
$E'$
is a twist of E by a quadratic character
$\chi $
associated with the extension
$\mathbb {Q}(\sqrt {d})$
. Then,
$\rho _{E',2} = \rho _{E,2} \otimes \chi $
. Since E does not have complex multiplication, E and
$E'$
are not
$\mathbb {Q}$
-isogenous.
If
${\bar {\rho }}_{E,2}$
is absolutely irreducible, the result follows from Theorem 5. Assume from here on that
$\rho _{E,2}$
is not absolutely irreducible but irreducible.
If
$\mathbb {Q}(\sqrt {d})$
is not a subfield of
$L = \mathbb {Q}(E[2^\infty ])$
, then
$L(\sqrt {d})$
is a degree
$2$
extension of L. Hence, the identity automorphism of L extends to an automorphism
$\sigma $
of
$L(\sqrt {d})$
such that
$\chi (\sigma ) = -1$
. It follows that
$\rho _{E,2}(\sigma ) = I$
and
$\rho _{E',2}(\sigma ) = -I$
, where I is the identity element. This means that
$\alpha = \beta = 1$
so we may apply the proofs of Theorem 1.3 and Proposition 4.4 (no need for Theorem 4.3) to get the desired conclusion.
Otherwise
$\mathbb {Q}(\sqrt {d})$
lies in the field L. In [Reference Rouse and Zureick-Brown13] (see Theorem 6.3), the possible
$2$
-adic images
$\rho _{E,2}(G)$
of an elliptic curve
$E/\mathbb {Q}$
are determined up to conjugacy. Every such image contains the principal congruence subgroup of level
$32$
and can be regarded as a subgroup of
$\operatorname {GL}_2(\mathbb {Z}/2^t\mathbb {Z})$
for
$0 \le t \le 5$
. In order to apply [Reference Rouse and Zureick-Brown13, Lemma 3.3], without loss of generality we take
$t \ge 2$
.
Let
$\Gamma = I + 2^{t+1} M_2(\mathbb {Z}_2) \subseteq N = I + 2^t M_2(\mathbb {Z}_2)$
. The character
$\chi $
corresponds to a subgroup H of index
$2$
inside
$\rho _{E,2}(G)$
. Either
$\Gamma \subseteq N \subseteq H$
or
so
$N/N \cap H$
has order
$2$
. In the latter case,
$N \cap H$
is a maximal subgroup of N, hence by [Reference Rouse and Zureick-Brown13, Lemma 3.3], we obtain again that
$\Gamma \subseteq N \cap H \subseteq H$
.
It follows that
$\chi $
factors through
Consider the product representation
We note that
$$ \begin{align} \rho_{E',2}(g) = \begin{cases} \rho_{E,2}(g) & \text{ if } \rho_{E,2}(g) \in H \\ -\rho_{E,2}(g) & \text{ if } \rho_{E,2}(g) \notin H. \end{cases} \end{align} $$
Let
$\theta $
be defined as:
$$ \begin{align} \theta : \rho_{E,2}(G) & \rightarrow \rho_{E',2}(G) \\ \notag \rho_{E,2}(g) & \mapsto \begin{cases} \rho_{E,2}(g) & \text{ if } \rho_{E,2}(g) \in H \\ -\rho_{E,2}(g) & \text{ if } \rho_{E,2}(g) \notin H. \end{cases} \end{align} $$
The map
$\theta $
is an isomorphism which is the identity when restricted to
$\Gamma \subseteq H$
and
is the subgroup of
$\operatorname {GL}_2(\mathbb {Z}_2) \times \operatorname {GL}_2(\mathbb {Z}_2)$
given by the graph of
$\theta $
, namely,
Hence, it follows that the inclusion
$$ \begin{align} \iota: \rho_{E,2}(G) & \rightarrow \rho(G) \nonumber\\ \rho_{E,2}(g) & \mapsto (\rho_{E,2}(g), \theta(\rho_{E,2}(g))) \end{align} $$
is an isomorphism. Composing with the homomorphism
$\rho _2(G) \rightarrow (M/2M)^\times $
, we obtain a homomorphism
Since
$\rho _{E,2}(G) \supseteq 1 + 2^t M_2(\mathbb {Z}_2)$
, we see that
$M = \mathbb {Z}_2[\rho _2(G)] \supseteq 2^t \Delta (M_2(\mathbb {Z}_2))$
, where
$\Delta : M_2(\mathbb {Z}_2) \rightarrow M_2(\mathbb {Z}_2) \times M_2(\mathbb {Z}_2)$
is the diagonal homomorphism. Thus,
$2M \supseteq 2^{t+1} \Delta (M_2(\mathbb {Z}_2))$
. Thus, we see that the kernel of the map
$\phi $
contains
${\Gamma = 1 + 2^{t+1} M_2(\mathbb {Z}_2)}$
and hence
$\phi $
factors through
Using Magma, we check that each one of the
$202$
possibilities for
$\rho _{E,2}(G)$
does not have a quotient which factors through
$\rho _{E,2}(G)/\Gamma $
and is isomorphic to one of the problematic groups in Table 2. In the computation, we do not need to check the cases when
${\bar {\rho }}_{E,2}$
is absolutely irreducible or reducible by our previous assumption.
List of problematic groups.

We conclude that it is possible to replace
$\delta (G)$
with a quotient of order
$\le 24$
. It is also checked that the elliptic curves E over
$\mathbb {Q}$
with j-invariant in the finite list of Theorem 6.2 (3) have
$C_E \le 2$
. Thus, we obtain the same bound as in (5.9) using Proposition 2.7.
Let
$E^F$
be the twist of an elliptic curve
$E/\mathbb {Q}$
by a quadratic extension
$F/\mathbb {Q}$
. The splitting fields of the m-division polynomials of E and
$E^F$
are equal to a common field
$L_m = L_{E,m} = L_{E^F,m}$
.
Proof of Theorem 1.7
Let
$F/\mathbb {Q}$
be chosen so that F is not contained in the fields
$L_{E,2^n}$
for all
$n \ge 1$
. This is possible as the fields
$L_{2^n}$
are unramified outside of
$2 N_E$
. If
$-I \notin \rho _{E,2}(G)$
, then
$-I \notin {\bar {\rho }}_{E,2^n}(G)$
for all
$n \ge 1$
. By [Reference Sutherland18, Corollary 5.25(b)] we have that
$-I \in {\bar {\rho }}_{E^F,2^n}(G)$
for all
$n \ge 1,$
and hence
$-I \in \rho _{E^F,2}(G)$
. Hence, up to replacing E by the quadratic twist
$E^F$
, we may assume that
$-I \in \rho _{E,2}(G)$
as the set of primes
$\ell> 13$
for which
${\bar {\rho }}_{E^F,\ell }$
is non-surjective is the same as that for
${\bar {\rho }}_{E,\ell }$
by [Reference Zywina19, Lemma 3.1].
Furthermore, by [Reference Lemos9, Theorem 1.1] we may assume
${\bar {\rho }}_{E,2}$
is irreducible otherwise
${\bar {\rho }}_{E,\ell }$
is surjective for
$\ell> 37$
.
We now combine Theorems 1.3 and 1.5 with the arguments in [Reference Mayle and Wang10].
Acknowledgments
We thank the anonymous referee for useful comments and suggestions which improved the constants in Theorem 1.7 and computational efficiency of the verifications.













