1. Introduction
Let
$\mathbb{D}= \{z\in \mathbb{C} \, : \, |z|\lt 1\}$
and
$\mathbb{T} = \{z\in \mathbb{C} \, : \, |z|=1\}$
. A pair
$(J,a)$
is called admissible if
$J=\{\, j_k\}_{k=1}^\infty$
,
$j_k \in \mathbb{N}$
,
$j_{k+1}/ j_k \ge 3$
and
$a=\{a_k\}_{k=1}^\infty$
,
$a_k\in \mathbb{D}\cup \mathbb{T}$
. Given an admissible pair
$(J, a)$
, the classical Riesz product
$\mu (J,a)$
is defined by
where the product converges in the weak* sense (see [Reference Riesz11]). By Zygmund’s theorem ([Reference Zygmund14], see also [Reference Zygmund15]), if
$(J,a)$
is an admissible pair with
$a\notin \ell ^2$
, then
$\mu (J,a)$
is singular with respect to Lebesgue measure on
$\mathbb{T}$
. Therefore, Riesz products are useful as examples of singular measures with special properties. In particular, such examples are related to singular measures with sufficiently small Fourier coefficients (see, e.g., [Reference Brown and Hewitt5]) and symmetric singular measures (see [Reference Aleksandrov, Anderson and Nicolau2]).
This paper is motivated by results about the mutual absolute continuity for the classical Riesz products
$\mu (J, a)$
on the unit circle
$\mathbb{T}$
; see, for example, [Reference Brown and Moran6, Reference Kilmer and Saeki9, Reference Peyrière10].
In the present work, we consider analogues of Riesz products on the unit sphere
$S_n = \{\zeta{ \in} \mathbb{C}^n \, : \, |\zeta | {=} 1\}$
,
$n \ge 2$
, with monomials
$z^{\, j_k}$
replaced by appropriate homogeneous holomorphic polynomials.
First of all, recall the definition of
$H(\, p,q)$
spaces,
$(\, p,q)\in \mathbb{Z}_+^2$
.
1.1. Complex spherical harmonics
Let
$\mathcal{U}(n)$
denote the group of unitary operators on the Hilbert space
$\mathbb{C}^n$
,
$n\ge 2$
. Observe that
$S_n$
is identifiable with
$\mathcal{U}(n)/\mathcal{U}(n-1)$
; hence,
$S_n$
is a homogeneous space. General constructions of the abstract harmonic analysis are explicitly realized on the sphere
$S_n$
in terms of the spaces
$H(\, p,q)$
,
$(\, p,q)\in \mathbb{Z}_+^2$
.
Definition 1.
Fix a dimension
$n$
,
$n\ge 2$
. Let
$H(p, q)= H(p,q; \, n)$
denote the vector space of all homogeneous harmonic polynomials of
$n$
complex variables and of bidegree
$(p, q) \in \mathbb{Z}_+^2$
. By definition, this means that the polynomials under consideration have degree
$p$
in variables
$z_1, z_2, \dots , z_n$
, have degree
$q$
in variables
$\overline {z}_1, \overline {z}_2, \dots , \overline {z}_n$
and have total degree
$p+q$
.
The restriction of the space
$H(p, q)$
to the sphere
$S_n$
is denoted by the same symbol. The elements of
$H(p, q)$
are often called
$\text{complex}$
spherical harmonics.
1.2. Riesz products on the sphere
We say that
$\{R_j\}_{j=1}^\infty$
is a Ryll–Wojtaszczyk sequence with a constant
$\delta \in (0, 1)$
provided that
-
•
$R_j \in H(\, j, 0)$
, that is,
$R_j$
is a homogeneous holomorphic polynomial of degree
$j$
, -
•
$\|R_j\|_{L^\infty (S_n)} = 1$
, -
•
$\|R_j\|_{L^2(S_n)} \ge \delta$
for all
$j =1,2,\dots$
.
The existence of such polynomials is proved in [Reference Ryll and Wojtaszczyk13].
Definition 2.
Let
$R = \{R_j\}_{j=1}^\infty$
be a Ryll–Wojtaszczyk sequence,
$J = \{\, j_k\}_{k=1}^\infty$
,
$j_k\in \mathbb{N}$
,
$j_{k+1}/j_k \ge 3$
and
$a = \{a_k\}_{k=1}^\infty$
,
$a_k\in \mathbb{D} \cup \mathbb{T}$
. Then,
$(R,J,a)$
is called a Riesz triple.
Every Riesz triple
$(R, J, a)$
generates a standard Riesz product
$\Pi (R, J, a)$
by the formal equality:
where the product converges in the weak* sense. Indeed, consider the partial products
Fix a polynomial
$\mathcal{P}$
on
$S_n$
. Since
$j_{k+1}/j_k \ge 3$
, we have
provided that
$\varkappa$
is sufficiently large. Also, we have
$\Pi _\varkappa \ge 0$
; thus,
since
$(0,0)\notin \textrm {spec}(\Pi _\varkappa -1)$
by the multiplication rule for spherical harmonics and property
$j_{k+1}/j_k \ge 3$
. Therefore, the partial products
$\Pi _\varkappa (R, J, a)$
converge weakly* as
$\varkappa \to \infty$
to a probability measure.
For the problem about the mutual singularity of classical Riesz products, the following criterion is known.
Proposition 1.1 (Peyrière [Reference Peyrière10]). Let
$(J, a)$
and
$(J, b)$
be admissible Riesz pairs. If
$a-b \notin \ell ^2$
, then
$\mu (J,a)$
and
$\mu (J,b)$
are mutually singular.
The following analogue of the above result is known on the sphere
$S_n$
,
$n\ge 2$
.
Proposition 1.2 ([Reference Doubtsov8, Theorem 1.2]). Let
$(R, J, a)$
and
$(R, J, b)$
be Riesz triples on
$S_n$
,
$n\ge 2$
, such that
$a-b \notin \ell ^2$
. Then there exists a sequence
$U=\{U_j\}_{j=1}^\infty$
,
$U_j \in \mathcal{U}(n)$
, such that the products
$\Pi (R\circ U, J, a)$
and
$\Pi (R\circ U, J, b)$
are mutually singular.
In particular, for
$n\ge 2$
, there exists a sufficiently large set of Riesz products singular with respect to Lebesgue measure on the sphere
$S_n$
.
In this paper, first, we obtain a condition sufficient for the mutual absolute continuity (i.e., for the equivalence) of two standard Riesz products.
Theorem 1.1.
Let
$(R, J, a)$
and
$(R, H, b)$
be Riesz triples on
$S_n$
,
$n\ge 2$
. Assume that
Then
$\Pi (R, J, a)$
and
$\Pi (R, H, b)$
are mutually absolutely continuous.
Second, we consider an analogous problem for pluriharmonic products (see Theorem4.1).
1.3. Notation
If
$\mu$
is absolutely continuous with respect to
$\nu$
, then we use the brief notation
$\mu \ll \nu$
. If
$\mu \ll \nu$
and
$\nu \ll \mu$
, then we write
$\mu \approx \nu$
and we say that
$\mu$
and
$\nu$
are equivalent.
1.4. Organization of the paper
Auxiliary results, including definitions and basic facts of the harmonic analysis on the sphere
$S_n$
, are presented in Section 2. Theorem1.1 is proved in Section 3. The problem about the mutual absolute continuity of pluriharmonic Riesz products is studied in Section 4.
2. Auxiliary results
2.1. Equivalence of classical Riesz products
Proposition 2.1 ([Reference Kilmer and Saeki9, Theorem 1]). Let
$\mu (J, a)$
and
$\mu (H, b)$
be classical Riesz products on the unit circle. Assume that
Then,
$\mu (J, a)\approx \mu (H, b)$
.
The main results of the present paper, Theorems1.1 and 4.1, extend the above mutual absolute continuity criterion to the standard and pluriharmonic Riesz products on the unit sphere.
2.2. Basic facts of the harmonic analysis on the sphere
$S_n$
Let
$\sigma _n$
denote the normalized Lebesgue measure on
$S_n$
. Observe that
Specifics of the harmonic analysis on the sphere
$S_n$
are suitably illustrated by the multiplication rule for spherical harmonics: if
$f \in H(p, q)$
and
$g \in H(r, s)$
, then
where
$L = \min (p, s) + \min (q, r)$
, and
$f$
and
$g$
are restricted to
$S_n$
. Proofs of the above facts and further results are presented in Chapter 12 of the monograph [Reference Rudin12].
Let
$M(S_n)$
denote the space of all complex Borel measures on the sphere
$S_n$
. Let
$K_{p,q}(z, \zeta )$
denote the reproducing kernel for the Hilbert space
$H(p, q) \subset L^2(S_n)$
. The polynomial
is called the
$H(p, q)$
-projection of the measure
$\mu \in M(S_n)$
. Given
$\mu \in M(S_n)$
, the spectrum
$\textrm {spec}(\mu )$
in terms of
$H(\, p,q)$
is defined by the equality
2.3. Decomposable measures
For
$f\in C(S_n)$
, it is well known that
where
$f_\zeta (\lambda ) = f(\lambda \zeta )$
,
$\lambda \in \mathbb{T}$
and
$\zeta \in S_n$
. This property of
$\sigma _n$
motivates the following definition.
Definition 3 (cf. [Reference Aleksandrov and Doubtsov3, Definition 2]). A measure
$\mu \in M(S_n)$
is called
$\text{decomposable}$
if, for
$\sigma _n$
-a.e.
$\zeta \in S_n$
, there exists a measure
$\mu _\zeta \in M(\mathbb{T})$
such that
and
in the following weak sense:
for all
$f\in C(S_n)$
.
2.3.1. Standard Riesz products are decomposable
For
$\zeta \in S_n$
, the slice-product
is a classical Riesz product defined by the formula:
\begin{equation} \prod _{k=1}^\infty \left ( \frac {\overline {a}_k \overline {R}_{j_k} (\zeta )\overline {\lambda }^{\, j_{k}}}{2} + 1 + \frac {{a}_k R_{j_k}(\zeta ) {\lambda }^{\, j_{k}}}{2} \right )\!, \quad \lambda \in \mathbb{T}. \end{equation}
In particular,
$\Pi _\zeta (R, J, a)$
is a probability measure.
Proposition 2.2 ([Reference Doubtsov8, Lemma 1]). Let
$(R, J, a)$
be a Riesz triple on the sphere
$S_n$
,
$n\ge 2$
. Then
for all
$f\in C(S_n)$
. Therefore,
$\Pi (R, J, a)$
is decomposable in terms of its slice-measures.
2.3.2. Positive pluriharmonic measures are decomposable
Let
$B_n = \{z\in \mathbb{C}^n \, : \, |z|\lt 1\}$
. By definition, a measure
$\mu \in M(S_n)$
is called pluriharmonic if its Poisson integral
is a pluriharmonic function. Observe that
$\mu$
is pluriharmonic if and only if
Now, let
$\mu$
be a positive pluriharmonic measure. Put
$u = P[\mu ]$
. For
$\zeta \in S_n$
, the slice-function
$u_\zeta$
is defined by
$u_\zeta (z) =u(z\zeta )$
,
$z\in \mathbb{D}$
. Since
$u$
is pluriharmonic,
$u_\zeta$
is a positive harmonic function for all
$\zeta \in S_n$
. Hence, for every
$\zeta \in S_n$
, there exists a measure
$\mu _\zeta \in M(\mathbb{T})$
such that
We say that
$\mu _\zeta$
is a slice-measure. Also, observe that
$\|\mu _\zeta \| = \|\mu \|$
.
Proposition 2.3 ([Reference Aleksandrov and Doubtsov3, Proposition 2.1]). Let
$\mu \in M(S_n)$
be a positive pluriharmonic measure. Then
for all
$f \in C(S_n)$
. Therefore,
$\mu$
is decomposable in terms of its slice-measures.
3. Equivalent Riesz products
We need the following result on decomposable measures.
Proposition 3.1 (see [Reference Aleksandrov and Doubtsov3, Theorem 2.8]). Let
$\mu \in M(S_n)$
be a decomposable measure such that (
2.2
) holds. Then
for all bounded measurable functions
$g$
defined on the sphere
$S_n$
.
Lemma 3.1.
Let
$\mu ^{(1)}, \mu ^{(2)} \in M(S_n)$
be positive decomposable measures. Suppose that
Then,
$\mu ^{(1)}\ll \mu ^{(2)}$
.
Proof. Assume that
$E\subset S_n$
is a measurable set such that
$\mu ^{(2)}(E) =0$
. We have to prove that
$\mu ^{(1)} {(E) = 0}$
.
Since
$\mu ^{(1)}, \mu ^{(2)}$
are decomposable, Proposition3.1 guarantees that
where
$E_\zeta =\{\lambda \in \mathbb{T} \, : \, \lambda \zeta \in E \}$
. We have
$\mu ^{(2)}(E)=0$
; hence,
$\mu ^{(2)}_\zeta (E_\zeta )=0$
for
$\sigma _n$
-a.e.
$\zeta \in S_n$
by (3.1) with
$j=2$
. By the hypothesis of the lemma,
$\mu ^{(1)}_\zeta \ll \mu ^{(2)}_\zeta$
for
$\sigma _n$
-a.e.
$\zeta \in S_n$
; therefore,
$\mu ^{(1)}_\zeta (E_\zeta )=0$
for
$\sigma _n$
-a.e.
$\zeta \in S_n$
. Thus, (3.1) with
$j=1$
guarantees that
$\mu ^{(1)}(E)=0$
, as required.
Proof of Theorem
1.1. For
$\zeta \in S_n$
, consider the slice-products
$\Pi _\zeta (R, J, a)$
and
$\Pi _\zeta (R, H, b)$
. Since
$\|R_j\|_\infty \le 1$
, Proposition2.1 guarantees that
$\Pi _\zeta (R, J, a) \approx \Pi _\zeta (R, H, b)$
. Therefore, we obtain
$\Pi (R, J, a) \approx \Pi (R, H, b)$
by Proposition2.2 and Lemma3.1.
4. Pluriharmonic Riesz products
In this section, we consider pluriharmonic Riesz products based on the Ryll–Wojtaszczyk polynomials and a Hankel operator compactness property (see, e.g., [Reference Doubtsov7]). The corresponding construction is motivated by Aleksandrov’s abstract inner function construction [Reference Aleksandrov1]; see also [Reference Bourgain4], where similar products are based on a bounded orthonormal basis in the Hardy space
$H^2(S_n)$
.
4.1. Pluriharmonic projection
Let
$PLH^2(S_n)$
denote the space of those
$f \in L^2(S_n)$
, for which the Poisson integral
is pluriharmonic in the unit ball
$B_n$
. Consider the orthogonal projector
Then every function
$\varphi \in L^\infty (S_n)$
generates a Hankel type operator by the formula:
Now, assume that
$\varphi$
is a polynomial. Then the operator
$H_\varphi \, : \, C(S_n) \to C(S_n)$
is compact (see, e.g., [Reference Rudin12, Theorem 6.5.4]), hence,
The above property is crucial for the transition from the standard Riesz products to the pluriharmonic ones.
4.2. Pluriharmonic Riesz products
Let
$(R, a)$
be a Riesz pair, that is,
$R$
is a Ryll–Wojtaszczyk sequence and
$a = \{a_k\}_{k=1}^\infty$
,
$a_k \in \mathbb{D}$
. Note that in this case, the set of indices
$J$
is not fixed.
By induction, we construct a sequence of pluriharmonic polynomials
$\varphi _k$
,
$\varphi _k \gt 0$
on
$S_n$
, and an index set
$J = \{\, j_k\}_{k=1}^\infty$
,
$j_{k+1}/j_k \ge 3$
. As the base of induction, we fix
$j_1 \in \mathbb{N}$
and define
Step
$k + 1$
By the induction assumption, we have a strictly positive pluriharmonic polynomial
$\varphi _k$
on
$S_n$
. Put
Using property (4.1), we select
$j_{k+1}$
so large that
$\varphi _{k+1} \gt 0$
on
$S_n$
. Also, the lacunas in the sequence
$J$
and the multiplication rule for spherical harmonics guarantee that the new spectrum
$\textrm {spec}(\varphi _{k+1} - \varphi _k)$
does not intersect a square
$[0,M]^2$
such that
$[0,M]^2\supset \textrm {spec}(\varphi _k)$
.
Recall that
$\sigma _n$
denotes the normalized Lebesgue measure on the sphere
$S_n$
. The above restrictions imply that the sequence
$\varphi _k \sigma _n$
weakly* converges to a probability pluriharmonic measure. This limit measure
$\pi = \pi (R, J, a)$
is called a pluriharmonic Riesz product.
4.3. Equivalence of pluriharmonic Riesz products
Theorem 4.1.
Let
$(R, a^{(d)})$
,
$d=1,2$
, be Riesz pairs. Suppose that
$a^{(1)}- a^{(2)} \in \ell ^1$
. Then, for all sufficiently lacunary index sets
$J=\{\, j_k\}_{k=1}^\infty$
, we have
Proof. Fix a sequence
$\{\varepsilon _k\}_{k=1}^\infty \in \ell ^1$
such that
$\varepsilon _k \gt 0$
. Below, we simultaneously construct two products
$\pi (R, J, a^{(1)})$
and
$\pi (R, J, a^{(2)})$
, imposing additional restrictions.
So, on Step
$k+1$
of the induction procedure, we assume that positive pluriharmonic polynomials
$\varphi ^{(1)}_k$
and
$\varphi ^{(2)}_k$
are constructed on
$S_n$
.
(1) Conditions to guarantee correct definitions.
For
$d=1,2$
, put
By (4.1), we have
$\varphi ^{(d)}_{k+1}(\ell ) \ge \mathrm{const}(k) \gt 0$
on
$S_n$
,
$d=1,2$
, for all sufficiently large
$\ell \in \mathbb{N}$
.
(2) Conditions to guarantee equivalence of slices.
For
$d = 1, 2$
, we have
$\varphi ^{(d)}_{k+1}(\ell ) \ge \mathrm{const}(k) \gt 0$
on
$S_n$
; hence, by (4.1), for all sufficiently large
$\ell \in \mathbb{N}$
, we have
\begin{eqnarray} \left \|\frac {\varphi _{k+1}^{(d)}(\ell )} {\varphi _k^{(d)}\left ( 1 + \mathrm{Re}\, \left(a_{k+1}^{(d)} R_\ell \right)\right )} -1 \right \|_{C(S_n)} &\lt & \varepsilon _k; \\[-20pt] \nonumber \end{eqnarray}
\begin{eqnarray} \left \|\frac {\varphi _k^{(d)}\left ( 1 + \mathrm{Re}\, \left(a_{k+1}^{(d)} R_\ell \right)\right )} {\varphi _{k+1}^{(d)}(\ell )} -1 \right \|_{C(S_n)} &\lt & \varepsilon _k \\[8pt] \nonumber \end{eqnarray}
for
$d = 1, 2$
.
(3) Final choice of
$j_{k+1}$
.
We select so large
$\ell$
that
$\ell \ge 3{j_k}$
and all above conditions hold. Put
$j_{k+1} = \ell$
. Finally, define
$\varphi ^{(d)}_{k+1} = \varphi ^{(d)}_{k+1}(\ell )$
for
$d = 1, 2$
. The induction Step
$k + 1$
is finished. Observe that the standard products
$\Pi (R, J, a^{(d)})$
,
$d=1,2$
, are automatically defined.
(4) Verification of the properties for the products
$\pi ^{(d)} = \pi (R, J, a^{(d)})$
.
The arguments below do not depend on the index
$d$
; thus, we omit it. We introduce auxiliary functions
and consider the partial products
$\Pi _p = \prod _{k=1}^p f_k$
. Then, by estimate (4.2), we have
\begin{equation*} \left \|\frac {\varphi _{k+1}}{\Pi _{k+1}}\right \|_{C(S_n)} = \left \| \frac {\prod ^{k}_{j=1} \varphi _{j+1}}{\prod ^k_{j=1} \varphi _{j} \, f_{j+1}} \right \|_{C(S_n)} \le \prod ^k_{j=1} (1 + \varepsilon _j). \end{equation*}
In other words, the sequence
$\{(\varphi _k)_\zeta /(\Pi _k)_\zeta \}_{k=1}^\infty$
is bounded in the space
$L^\infty (\Pi _\zeta )$
for every point
$\zeta \in S_n$
. Observe that
weakly* in the space
$M(\mathbb{T})$
as
$k \to \infty$
. Hence, we obtain
$\pi _\zeta \ll \Pi _\zeta$
. The arguments for the property
$\Pi _\zeta \ll \pi _\zeta$
proceed similarly with the help of estimate (4.3). Therefore,
Observe that
$\Pi _\zeta (R, J, a^{(1)}) \approx \Pi _\zeta (R, J, a^{(2)})$
for all
$\zeta \in S_n$
by Proposition2.1. Hence,
Since
$\pi (R, J, a^{(d)})$
,
$d=1,2$
, are pluriharmonic measures, they are decomposable in terms of their slices
$\pi _\zeta (R, J, a^{(d)})$
,
$\zeta \in S_n$
, by Proposition2.3. Thus, (4.4) and Lemma3.1 imply the required property
$\pi (R, J, a^{(1)}) \approx \pi (R, J, a^{(2)})$
.
Acknowledgements
The author is grateful to the anonymous referee for helpful remarks and suggestions.
Competing interests
None.