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Non-uniformly hyperbolic endomorphisms

Published online by Cambridge University Press:  01 September 2025

Martin Andersson
Affiliation:
Universidade Federal Fluminense, Departamento de Matemática aplicada, Rua Professor Marcos Waldemar de Freitas Reis, 24210-201, Niterói, RJ, Brazil nilsmartin@id.uff.br
Pablo D. Carrasco
Affiliation:
Universidade Federal de Minas Gerais, ICEx-UFMG, Av. Pres. Antônio Carlos, 6627 - 31270-901, Belo Horizonte, MG, Brazil pdcarrasco@gmail.com
Radu Saghin
Affiliation:
Pontificia Universidad Católica de Valparaíso, Instituto de Matemática, Blanco Viel 596, 2350050, Cerro Barón, Valparaíso, Chile rsaghin@gmail.com
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Abstract

We show the existence of large $\mathcal C^1$ open sets of area-preserving endomorphisms of the two-torus which have no dominated splitting and are non-uniformly hyperbolic, meaning that Lebesgue almost every point has a positive and a negative Lyapunov exponent. The integrated Lyapunov exponents vary continuously with the dynamics in the $\mathcal C^1$ topology and can be taken as far away from zero as desired. Explicit real analytic examples are obtained by deforming linear endomorphisms, including expanding ones. The technique works in nearly every homotopy class, and the examples are stably ergodic (in fact Bernoulli), provided that the linear map has no eigenvalue of modulus one.

Information

Type
Research Article
Copyright
© The Author(s), 2025. The publishing rights in this article are licensed to Foundation Compositio Mathematica under an exclusive licence
Figure 0

Figure 1 Panel (a) shows the $25$ pre-images of a randomly chosen point $x = (0.594, 0.287)$ under the map $E_k$ when $k=2$, together with the cones $E_k^{-1} \Delta _\alpha ^v$ with $\alpha = 2$. Panel (b) shows the pre-images of these points under the map $S_t^{-1} = S_{-t}$ for $t=1.5$, together with the corresponding cones. (Taking a bigger $t$ would make some of the cones hard to see because they would be too thin.) In this example we see that $(Df_{y})^{-1} \Delta _\alpha ^v \subset \Delta _\alpha ^v$ for $20$ choices of $y \in f^{-1}(x)$. At one of the points $y$ (say $y_0$) for which this fails, the illustration shows the horizontal cone $\Delta _\alpha ^h$ instead of $(Df_{y_0})^{-1}\Delta _\alpha ^v$. The horizontal cone at $y_0$ is divided into two parts, reflecting the quadrant to which it is mapped under $E^{-1}$. The pre-images of this horizontal cone are shown in panel (c). Finally, in panel (d) we see $(Df_z)^{-1}\Delta _\alpha ^h$ for every $z \in f^{-1}(y_0)$. For $10$ choices of $z$, vectors in $\Delta _\alpha ^h$ which lie in the second and fourth quadrant get mapped into $\Delta _\alpha ^v$ while, for $10$ other choices, vectors in the first and third quadrant get mapped into $\Delta _\alpha ^v$.