1 Introduction
This article is a further contribution to the topic of generation in the algebra of
$n\times n$
matrices over the complex number field
$\mathbb {C}$
, as in earlier articles [Reference Laffey, Markova and Šmigoc1, Reference Longstaff2, Reference Longstaff3]. We recall that, for arbitrary subsets
$S_i\subset \mathrm {Mat}_n(\mathbb {C})$
, the set product
$S_1 \cdots S_k$
is the family of all matrices
$s_1 \cdots s_k$
with
$s_i\in S_i$
. We write
$S^t$
to denote the t-fold product
$S \cdots S$
, as above, and
$S^0$
is
$\{I\}$
, where I is the identity matrix. We define
$S\,\mathbb {C}$
to be the
$\mathbb {C}$
-linear span of S. The length
$\ell (S)$
is the smallest integer l for which
$S^0\,\mathbb {C}+S^1\,\mathbb {C}+\cdots +S^l\,\mathbb {C}$
is the full algebra generated by S. A family
$S\subset \mathrm {Mat}_n(\mathbb {C})$
is called irreducible if S generates
$\mathrm {Mat}_n(\mathbb {C})$
as an algebra over
$\mathbb {C}$
.
2 Lengths of families of rank-one matrices
One recent article of Longstaff [Reference Longstaff2] is mostly devoted to the following question.
Question 2.1 (See [Reference Longstaff2, pages 229 and 232])
What can the length of an irreducible, linearly independent family F of
$n\times n$
rank-one matrices be?
Theorem 3.5 of [Reference Longstaff2] shows
$\ell (F)\leqslant n$
. Longstaff gives examples with
$\ell (F)\in \{1,2\}$
and
$\ell (F)\in \{n-1,n\}$
, and also
$\ell (F)=k+1$
, for any positive integer k dividing
$n-1$
(see [Reference Longstaff2]). Despite considerable attention and citations to the work [Reference Longstaff2], no further progress seems to have been made, and Question 2.1 was unsolved.
The solution is as follows. As in the article of Longstaff [Reference Longstaff2], we focus on families consisting of matrix units
$e_{ij}$
(that is, each
$e_{ij}$
is the matrix having
$1$
at the position
$(i,j)$
and zeros everywhere else). We recall that a simple graph G has finite sets of vertices V and edges E, and each edge is a two-element subset of V. A path between
$v_1,v_2\in V$
is a list of edges
$(e_1,e_2,\ldots ,e_k)$
with
$v_1\in e_1$
and
$v_2\in e_k$
, and also
$|e_i\cap e_{i+1}|=1$
, for all
$i\in \{1,2,\ldots ,k-1\}$
. A graph is connected if any pair of vertices
$u\neq v$
allows a path between them, and the distance between u and v is the length of the shortest path. The diameter of a connected graph G is the largest possible distance between any two distinct vertices in G (see [Reference Ore5]).
Claim 2.2. For a connected graph
$G=(\{1,\ldots ,n\},E)$
, we define
$F(G)$
as the family of
$n\times n$
matrices consisting of those
$e_{ij}$
for which either
$i=j$
or
$\{i,j\}\in E$
. Then,
$F(G)$
is irreducible if and only if G is connected and
$\ell (F(G))$
is the diameter of G.
Proof. For all
$k\geqslant 1$
, the set
$F(G)^k$
consists of all diagonal units
$e_{ii}$
and those
$e_{ij}$
for which there exists a path of length at most k containing vertices i and j.
The set
$F=\{(1,2),\ldots ,(n-1,n),(n,1)\}$
has
$\ell (F)=n$
, as in [Reference Longstaff2], and graphs with n vertices and diameters
$1,2,\ldots ,n-1$
are straightforward (see Figure 1 and [Reference Ore5]).
Complete graphs with at least two vertices have diameter one. The right graph has n vertices and diameter
$d\geqslant 2$
.

Therefore, the set of all possible values of
$\ell (F)$
in Question 2.1 is
$\{1,2,\ldots ,n\}$
for all
$n\neq 1$
, giving a complete answer to Question 2.1.
3 Lower bounds on slot length
The article [Reference Longstaff3] is devoted to the concept of slot lengths of matrix families.
Definition 3.1 [Reference Longstaff3, page 260]
The slot length of a family
$S\subset \mathrm {Mat}_n(\mathbb {C})$
is the smallest integer k such that the algebra generated by S is spanned by the elements
involving arbitrary elements
$s_i\in S$
taken to arbitrary powers
$\varepsilon _i\geqslant 0$
.
Longstaff shows that the slot length of an irreducible pair
$\{A, B\}\subset \mathrm {Mat}_n(\mathbb {C})$
is at most
$n-1$
, provided that A is a Jordan cell and
$n\geqslant 5$
, (see [Reference Longstaff3, Theorem 2.7]). The following potential generalisation was proposed in further discussion in [Reference Longstaff3].
Conjecture 3.2 [Reference Longstaff3, Conjecture 2.9]
If
$n\geqslant 5$
, then every irreducible pair of
$n\times n$
complex matrices has slot length at most
$n-1$
.
However, this conjecture is false. Indeed, let
$n=2k+1$
be an odd number and J the nilpotent Jordan cell of order n. We take
with
$J^{\top }$
being the transpose of J. We immediately have
and
$\operatorname {rank} A^2=1$
, which shows that, for all matrices
$U, V, W\in \mathrm {Mat}_n(\mathbb {C})$
,
Finally, we recall that Laffey, Markova and Šmigoc [Reference Laffey, Markova and Šmigoc1, Theorem 2.12] proved that
and that
$\{A, B\}$
is irreducible [Reference Laffey, Markova and Šmigoc1, Theorem 2.10]. If the slot length of
$\{A, B\}$
is less than
$2n-3$
, then the algebra
$\mathrm {Mat}_n(\mathbb {C})$
is spanned by products of the forms
with any exponents
$\varepsilon _i\geqslant 0$
, as in Definition 3.1. By the conditions (3.1) and (3.2), the algebra
$\mathrm {Mat}_n(\mathbb {C})$
is now spanned by products of A and B of lengths not exceeding
$2n-3$
, which is a contradiction to (3.3). Therefore, the slot length of
$\{A,B\}$
cannot be less than
$2n-3$
, providing a counterexample to Conjecture 3.2.
4 Irreducible sets of three square-zero matrices
This section is a remark on one other result in [Reference Longstaff4]. Following [Reference Longstaff4], a square matrix A is called a square-zero matrix if
$A^2=0$
. In [Reference Longstaff4, Proposition 2.3], Longstaff gives a quite complicated demonstration of the following fact.
Observation 4.1. For any integer
$n\geqslant 3$
, there is a set of three square-zero matrices that is irreducible in
$\mathrm {Mat}_n(\mathbb {C})$
.
However, this is easy to see. Indeed, for
$\chi \in \{0,1\}$
, one can define
$M_\chi $
as the sum of matrix units
$e_{i\,i+1}$
over all those indices
$i\in \{1,2,\ldots ,n-1\}$
which are of the same parity as
$\chi $
. As the sum
$M_0+M_1$
is the nilpotent Jordan cell J, we can show that the family of three square-zero matrices
$\{M_0,M_1,e_{n1}\}$
is irreducible. Indeed,
is an expression of all matrix units (see also [Reference Laffey, Markova and Šmigoc1, Theorem 2.10]).
5 Upper bounds on
$1$
-minimum spanning lengths
Let
$S\subset \mathrm {Mat}_n(\mathbb {C})$
be a finite set and
$x=(x_1,x_2,\ldots ,x_t)$
a word with
$x_i\in S$
. This word is said to have height one if, in each consecutive pair, the two letters are different, that is,
$x_i\neq x_{i+1}$
for
$i\in \{1,2,\ldots ,t-1\}$
(see [Reference Longstaff4, page 78]). If, for some integer k, the set of all products of nonempty height-one words,
with
$t\leqslant k$
, spans the full matrix algebra
$\mathrm {Mat}_n(\mathbb {C})$
, Longstaff defines the
$1$
-minimum spanning length
$\operatorname {msl}_1(S)$
as the smallest k with this property [Reference Longstaff4, page 78].
Remark 5.1. In [Reference Longstaff4], the notation
$1$
-
$\operatorname {msl}(S)$
is used instead of
$\operatorname {msl}_1(S)$
. We prefer the latter to avoid a possible confusion of the hyphen and the arithmetical sign.
Finally, the minimum spanning length
$\operatorname {msl}(S)$
is defined in the same way as
$\operatorname {msl}_1(S)$
, except that the words (5.1) are not required to have height one [Reference Longstaff4, page 78].
In [Reference Longstaff4, Remark 2.4], Longstaff conjectures the inequality
$\operatorname {msl}_1(\{A,B\})\leqslant 4n-7$
for any irreducible pair
$\{A,B\}\subset \mathrm {Mat}_n(\mathbb {C})$
with
$n\geqslant 2$
. As also noted in [Reference Longstaff4, page 80], the Cayley–Hamilton theorem does not allow the height-one words in A and B to span a subspace of dimension greater than
$4n-2$
. This number is less than
$n^2$
whenever
$n\geqslant 4$
, and then the conjecture becomes void. In the context of [Reference Longstaff4, Remark 2.4 and Proposition 2.5], a possible intended meaning could have been that
for irreducible pairs
$\{A,B\}\subset \mathrm {Mat}_n(\mathbb {C})$
. Indeed, [Reference Longstaff4, Remark 2.4] gives a weaker version of (5.2), with
$4n-7$
replaced by
$4n-5$
. Another approach to (5.2) is [Reference Longstaff4, Proposition 2.5], but it involves an additional assumption on
$\{A,B\}$
, as follows:
where
$V_j(A, B)$
is the linear span of the nonempty products of length at most j of
$\{A, B\}$
, and
$W(A, B)$
is the span of all products of those words of length
$2n-2$
that are different from both
$A^{n-1}\,B^{n-1}$
and
$B^{n-1}\,A^{n-1}$
.
Lemma 5.2 [Reference Longstaff4, Proposition 2.5]
Assume
$n\geqslant 2$
and let
$\{A,B\}\subset \mathrm {Mat}_n(\mathbb {C})$
be an irreducible pair of matrices that satisfies (5.3). Then, we have (5.2).
For
$n=2$
, the conjecture (5.2) can be refuted with the irreducible pair
$\{e_{12}, e_{21}\}$
and easy calculation. However, it turns out that the conjecture is always true with
$n\geqslant 3$
. In other words, the requirement of (5.3) is not necessary in Lemma 5.2.
Lemma 5.3. Let
$A,B\in \mathrm {Mat}_n(\mathbb {C})$
be arbitrary matrices with
$n\geqslant 3$
. Then, the matrix
$A^{n-1}B$
belongs to
$V_{n-1}(A, B)+W'(A, B)+I\,\mathbb {C}$
, where
$W'(A, B)$
is the set of products of all words of length n except for
$A^{n-1}B$
, and
$V_j$
is defined previously.
Proof. Apply the Cayley–Hamilton theorem to the matrix
$A+B$
.
Now, arguments similar to [Reference Longstaff4, Proposition 2.5] complete the proof of (5.2).
Theorem 5.4. Let
$n\geqslant 3$
. If
$\operatorname {msl}(\{A,B\})\leqslant 2n-2$
for irreducible
$\{A,B\}\subset \mathrm {Mat}_n(\mathbb {C})$
, then
$\operatorname {msl}_1(\{I,A,B\})\leqslant 4n-7$
.
Proof. Let
$\mathcal {B}$
be a basis of
$\mathrm {Mat}_n(\mathbb {C})$
consisting of products of lengths at most
$2n-2$
. Using the Cayley–Hamilton theorem, we can assume that no product of
$\mathcal {B}$
has n consecutive appearances of either A or B. Further, if
then we insert the multiplication by the identity I between every pair of consecutive equal letters in the words of
$\mathcal {B}$
. This results in a basis of height-one words at the cost of adding at most
$2n-5$
letters in each word, and hence,
$\operatorname {msl}_1(\{I,A,B\})\leqslant 4n-7$
. If (5.4) is false, then either
$A^{n-1}\,B^{n-1}\in \mathcal {B}$
or
$B^{n-1}\,A^{n-1}\in \mathcal {B}$
. Now, we write
to further replace the
$A^{n-1}B$
and
$B^{n-1}A$
parts by words of
$V_{n-1}(A, B)$
,
$W'(A, B)$
and
$W'(B, A)$
in Lemma 5.3. Thus, each of the resulting words is in the linear span of
$V_{2n-3}(A, B)$
and those products of length
$2n-2$
that have at least two pairs of distinct consecutive letters, which reduces the situation to the known case (5.4).
Acknowledgement
This article incorporates several corrections which arose from the peer review and the editing stages.







