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A sharpened form of Adams-type inequalities on higher-order Sobolev spaces $W^{m,\frac {n}{m}}(\mathbb {R}^n)$: a simple approach

Published online by Cambridge University Press:  15 December 2021

Lu Chen
Affiliation:
School of Mathematics and Statistics, Beijing Institute of Technology, Beijing 100081, P. R. China e-mail: chenlu5818804@163.com
Guozhen Lu*
Affiliation:
Department of Mathematics, University of Connecticut Storrs, CT 06269, USA
Maocun Zhu
Affiliation:
Faculty of Science, Jiangsu University, Zhenjiang 212013, P. R. China e-mail: zhumaochun2006@126.com
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Abstract

In this paper, we develop an extremely simple method to establish the sharpened Adams-type inequalities on higher-order Sobolev spaces $W^{m,\frac {n}{m}}(\mathbb {R}^n)$ in the entire space $\mathbb {R}^n$, which can be stated as follows: Given $\Phi \left ( t\right ) =e^{t}-\underset {j=0}{\overset {n-2}{\sum }} \frac {t^{j}}{j!}$ and the Adams sharp constant $\beta _{n,m}$. Then,

$$ \begin{align*}\sup_{\|\nabla^mu\|_{\frac{n}{m}}^{\frac{n}{m}}+\|u\|_{\frac{n}{m}}^{\frac{n}{m}}\leq1}\int_{\mathbb{R}^n}\Phi\Big(\beta_{n,m} (1+\alpha \|u\|_{\frac{n}{m}}^{\frac{n}{m}} )^{\frac{m}{n-m}}|u|^{\frac{n}{n-m}}\Big)dx<\infty, \end{align*} $$
for any $0<\alpha <1$. Furthermore, we construct a proper test function sequence to derive the sharpness of the exponent $\alpha $ of the above Adams inequalities. Namely, we will show that if $\alpha \ge 1$, then the above supremum is infinite.

Our argument avoids applying the complicated blow-up analysis often used in the literature to deal with such sharpened inequalities.

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Type
Article
Copyright
© Canadian Mathematical Society, 2021