1. Introduction
Highly motivated by the study of the Johnson homomorphisms of the mapping class groups of surfaces by pioneering works of Johnson [Reference Johnson22], Morita [Reference Morita27], and Hain [Reference Hain17] in the 1980s and 1990s, that of the automorphism groups of free groups was initiated by several authors including Kawazumi [Reference Kawazumi23] in the early 2000s. Over the past two decades, good progress was made in the study of the Johnson homomorphisms of the automorphism groups of free groups through the works of many authors. In particular, the stable cokernels of the Johnson homomorphisms of the automorphism groups of free groups have been completely determined due to Satoh [Reference Satoh30, Reference Satoh34] and Darné [Reference Darné12]. Enomoto-Satoh [Reference Enomoto and Satoh14] also gave a combinatorial description of the GL-decomposition of the stable rational cokernels of the Johnson homomorphisms. As is well known due to a classical work of Artin, the automorphism group of a free group contains the braid group of a plane (see also Section 1.4 in [Reference Birman7]). Hence, we have natural problems to determine the images and the cokernels of Johnson homomorphisms of the braid groups. However, in contrast to the case of the mapping class group of a surface, there are few studies for them. In general, it seems to be a difficult problem to attack this problem directly from a combinatorial group theoretic and a representation theoretic viewpoints. In the present article, we focus on the basis-conjugating automorphism groups of free groups that contain the pure braid groups as subgroups and study the Johnson homomorphisms of them.
The article broadly deals with three main topics. After definitions and basic properties of the Johnson homomorphisms and the basis-conjugating automorphism groups are confirmed in Sections from 3 to 5, first we consider the trace maps to determine the Johnson cokernels of the basis-conjugating automorphism groups of free groups in Sections from 6 to 8. The second topic is the Andreadakis problem for the basis-conjugating automorphism groups of free groups, which is discussed in Section 9. We also give a slight application of it to the second cohomology groups of the basis-conjugating automorphism groups in Section 10. Finally, we consider twisted first cohomology groups of the braid-permutation groups of free groups in Section 11. The details for the results of the article in each topics are as follows.
1.1. Traces and Johnson cokernels
First, let us fix some notations. For any
$n \geq 1$
, let
$F_n$
be the free group of rank
$n$
with basis
$x_1, \ldots , x_n$
, and
$\mathrm{Aut}\,F_n$
the automorphism group of
$F_n$
. Set
$H\,:\!=H_1(F_n,\mathbf{Z})$
and
$H^* \,:\!= \mathrm{Hom}_{\mathbf{Z}}(H,\mathbf{Z})$
. Denote by
$\mathcal{L}_n=\bigoplus _{k \geq 1} \mathcal{L}_n(k)$
the free Lie algebra generated by
$H$
. Let
$\mathcal{A}_n(1) \supset \mathcal{A}_n(2) \supset \cdots$
be the Andreadakis–Johnson filtration of
$\mathrm{Aut}\,F_n$
. Then for each
$k \geq 1$
, the
$k$
-th Johnson homomorphism
is defined. Each
$\tau _k$
is an injective
$\mathrm{GL}(n,\mathbf{Z})$
-equivariant homomorphism. (See Section 4 for details.) Let
be the quotient module of
$H^{\otimes k}$
by the permutation action of the cyclic group
$C_k$
of degree
$k$
on the components. By combining results by Satoh [Reference Satoh30, Reference Satoh34] and by Darné [Reference Darné12], it is known that the cokernel of
$\tau _k$
is isomorphic to
$\mathcal{C}_n(k)$
for
$n \geq k+2$
. In order to describe the cokernel of
$\tau _k$
, we used the trace map
defined as the compositions of maps including a contraction. This is a generalization of the Morita trace defined in [Reference Morita27]. (See Section 4 for details.) Then we have an exact sequence
for
$n \geq k+2$
. Furthermore, Enomoto-Satoh [Reference Enomoto and Satoh14] gave a combinatorial description of the GL-decomposition of
$\mathcal{C}_n^{\mathbf{Q}}(k) \,:\!= \mathcal{C}_n(k) \otimes _{\mathbf{Z}} \mathbf{Q}$
. In the article, we consider the basis-conjugating automorphism group as an analogue of these works.
An automorphism
$\sigma$
of
$F_n$
such that
$x_i^{\sigma }$
is conjugate to
$x_i$
for each
$1 \leq i \leq n$
is called a basis-conjugating automorphism of
$F_n$
. Let
$\mathrm{P}\Sigma _n$
be the subgroup of
$\mathrm{Aut}\,F_n$
consisting of all basis-conjugating automorphisms of
$F_n$
. The group
$\mathrm{P}\Sigma _n$
is called the basis-conjugating automorphism group of
$F_n$
. Since McCool [Reference McCool25] gave the first finite presentation for
$\mathrm{P}\Sigma _n$
, it is also called the McCool group. So far,
$\mathrm{P}\Sigma _n$
has been studied by many authors from several viewpoints.
For any
$k \geq 1$
, set
$\mathcal{P}_n(k)\,:\!= \mathrm{P}\Sigma _n \cap \mathcal{A}_n(k)$
. We have an injective
$\mathfrak{S}_n$
-equivariant homomorphism
where
$\mathfrak{p}_n(k)$
is a certain submodule of
$H^* \otimes _{\mathbf{Z}} \mathcal{L}_n(k+1)$
(See Section 3 for details). From a veiwpoint of the study of the Johnson homomorphisms of
$\mathrm{P}\Sigma _n$
, we consider the Lie algebra
$\mathfrak{p}_n\,:\!=\bigoplus _{k \geq 1} \mathfrak{p}_n(k)$
in [Reference Satoh36]. But we should remark that
$\mathfrak{p}_n$
was introduced as the Lie algebra of tangential derivations by Alekseev and Torossian in [Reference Alekseev and Torossian1] for their study for the Kashiwara–Vergne problem. The homomorphism
$\tau _k^P$
is
$\mathfrak{S}_n$
-equivariant and is called the
$k$
-th Johnson homomorphism of
$\mathrm{P}\Sigma _n$
. Here
$\mathfrak{S}_n$
is the symmetric group of degree
$n$
and is considered as the subgroup of
$\mathrm{GL}(n,\mathbf{Z})$
consisting of all of permutation matrices. (See also Section 3.) We should remark that in this article, the target of
$\tau _k^P$
is always understood to be
$\mathfrak{p}_n(k)$
, not
$H^* \otimes _{\mathbf{Z}} \mathcal{L}_n(k+1)$
. Hence, the cokernel
$\mathrm{Coker}(\tau _k^P)$
of
$\tau _k^P$
means the quotient module of
$\mathfrak{p}_n(k)$
by the image of
$\tau _k^P$
. In [Reference Satoh36], we showed that
$\tau _1^P$
is surjective and the abelianization of
$\mathrm{P}\Sigma _n$
. Ibrahim [Reference Ibrahim20] determined the structure of
$\mathrm{gr}^2(\mathcal{P}_n)$
and
$\mathrm{gr}^3(\mathcal{P}_3)$
. In particular, he obtained the ranks of them.
Compared with the case of
$\tau _k$
, to describe the cokernel of
$\tau _k^P$
for
$k \geq 2$
is much more complicated. Let
$\mathrm{Tr}_k^P\,:\,\mathfrak{p}_n(k) \rightarrow \mathcal{C}_n(k)$
be the restriction of
$\mathrm{Tr}_k$
to
$\mathfrak{p}_n(k)$
. By the definition of
$\mathcal{P}_n(k)$
, it is easy to see that for any
$k \geq 2$
,
$\langle x_1^k, \ldots , x_n^k \rangle \cap \mathrm{Im}(\mathrm{Tr}_k^P) = \{ 0 \}$
. Let
$\overline {\mathrm{Tr}}_k^P\,:\,\mathfrak{p}_n(k) \rightarrow \overline {\mathcal{C}}_n(k)$
be the composition of
$\mathrm{Tr}_k^P$
and the natural projection
$\mathcal{C}_n(k) \rightarrow \overline {\mathcal{C}}_n(k) \,:\!= \mathcal{C}_n(k)/\langle x_1^k, \ldots , x_n^k \rangle$
. Then we have
Theorem 1 (Propositions 7.1 and 7.4, and Corollary 7.9). For any
$n \geq 3$
, we have an
$\mathfrak{S}_n$
-equivariant exact sequences
for
$2 \leq k \leq 3$
, and
where
$Q$
is isomorphic to a free abelian group of rank
$n(n-1)/2$
as an
$\mathfrak{S}_n$
-module.
This shows that
$\mathrm{Im}(\tau _k^P) = \mathrm{Ker}(\overline {\mathrm{Tr}}_k^P)$
for
$k \leq 4$
and the trace map
$\overline {\mathrm{Tr}}_k^P$
is not surjective in general.
Problem 1.
In order to describe the image of
$\tau _k^P$
, there are the following basic problems. For any
$k \geq 5$
,
-
(1) Determine the image of
$\overline {\mathrm{Tr}}_k^P$
. -
(2) Determine the gap at the inclusion
$\mathrm{Im}(\tau _k^P) \subset \mathrm{Ker}(\overline {\mathrm{Tr}}_k^P)$
.
In general, it seems to be difficult to determine whether or not
$\mathrm{Im}(\tau _k^P)=\mathrm{Ker}(\overline {\mathrm{Tr}}_k^P)$
. In this article, we show that a certain
$\mathfrak{S}_n$
-invariant subspace of
$\mathrm{Ker}(\overline {\mathrm{Tr}}_k^P)$
is contained in
$\mathrm{Im}(\tau _k^P)$
. More precisely, for any
$\alpha =(\alpha _1,\alpha _2, \ldots ,\alpha _n) \in \mathbb{Z}_{\ge 0}^n$
such that
$\alpha _1+\cdots +\alpha _n=k$
, denote by
$\mathfrak{p}_n(k,\alpha )$
the subspace of
$\mathfrak{p}_n(k)$
generated by all
$x_i^* \otimes [x_{i_1},x_{i_2}, \ldots ,x_{i_k}, x_i]$
such that
$(i_1,i_2, \ldots , i_k) \in p(\alpha )$
, where
$p(\alpha )$
is the set of all permutations of
$(1^{\alpha _1}, \ldots ,n^{\alpha _n})$
.
Theorem 2 (=Theorem 8.5) For any
$n \geq 3$
,
$k \geq 1$
and any
$\alpha =(\alpha _1,\alpha _2, \ldots ,\alpha _n) \in \mathbb{Z}_{\ge 0}^n$
such that
$\alpha _1+ \alpha _2+ \cdots +\alpha _n=k$
and
$\alpha _j=1$
for some
$1 \leq j \leq n$
, we have
$\mathrm{Ker}(\overline {\mathrm{Tr}}_k^P|_{\mathfrak{p}_n(k,\alpha )}) \subset \mathrm{Im}(\tau _k^P)$
.
To consider the above problems, we introduce a variant
$\widetilde {\phantom{\,}\mathrm{Tr}\phantom{\,}}_{\!k}^{\!P}$
of the trace map
$\overline {\mathrm{Tr}}_k^P$
. For any
$k \geq 2$
, let
$N(k)$
be the
$\mathfrak{S}_n$
-invariant submodule of
$\mathcal{C}_n(k)$
generated by
$x_{j_1} x_{j_2} \cdots x_{j_k}$
for all
$1 \leq\,j_1, \ldots , j_k \leq n$
such that each
$j_l$
$(1 \leq l \leq k)$
appears at least twice in
$j_1, j_2, \ldots , j_k$
. Let
$\widetilde {\phantom{\,}\mathrm{Tr}\phantom{\,}}_{\!k}^{\!P}\,:\,\mathfrak{p}_n(k) \rightarrow \widetilde {\mathcal{C}}_n(k)\,:\!= \mathcal{C}_n(k)/N(k)$
be the composition of
$\mathrm{Tr}_k^P$
and the natural projection
$\mathcal{C}_n(k) \rightarrow \widetilde {\mathcal{C}}_n(k)$
. Then we have
Theorem 3 (Theorem 6.2). For any
$n \geq 2$
and
$k \geq 2$
, the map
$\widetilde {\phantom{\,}\mathrm{Tr}\phantom{\,}}_{\!k}^{\!P}$
is surjective. We give some observations for Problem 1 in Section 8. First, we find the explicit dimensions of
$\mathrm{Im}(\overline {\mathrm{Tr}}_k^P)$
and
$\mathrm{Ker}(\overline {\mathrm{Tr}}_k^P)$
for
$5 \leq k \leq 9$
and general
$n$
. Second, we also give the explicit dimensions of the Johnson images
$\mathrm{Im}(\tau _k^P)$
for
$5 \leq k \leq 8$
and
$n=3$
. We will see some gaps at the inclusion
$\mathrm{Im}(\tau _k^P) \subsetneq \mathrm{Ker}(\overline {\mathrm{Tr}}_k^P)$
for
$k=7$
and
$8$
and
$n=3$
.
1.2. The Andreadakis conjecture
The study of the Johnson homomorphisms gives us several applications. We apply it to the Andreadakis problem for
$\mathrm{P}\Sigma _n$
. Let
$\mathrm{P}\Sigma _n=\mathrm{P}\Sigma _n{(1)} \supset \mathrm{P}\Sigma _n{(2)} \supset \cdots$
be the lower central series of
$\mathrm{P}\Sigma _n$
. We have
$\mathrm{P}\Sigma _n{(k)} \subset \mathcal{P}_n(k)$
for any
$k \geq 1$
. The Andreadakis problem for
$\mathrm{P}\Sigma _n$
asks whether
$\mathrm{P}\Sigma _n{(k)} = \mathcal{P}_n(k)$
or not. In general, except for some low degree or unstable cases, the Andreadakis problems for
$\mathrm{P}\Sigma _n$
and
$\mathrm{Aut}\,F_n$
are still open. Satoh [Reference Satoh35] showed that
$\mathrm{P}\Sigma _n{(k)} = \mathcal{P}_n(k)$
for
$k \leq 3$
. By using the third Johnson homomorphisms, we obtain the following.
Theorem 4 (Corollary 9.2). For
$n \geq 3$
, we have
$\mathcal{P}_n(4)=\mathrm{P}\Sigma _n(4)$
.
This shows that Ibrahim’s conjecture (see Conjecture A.1. in [Reference Ibrahim20]) holds for any
$n \geq 3$
and
$k=3$
.
We remark that by using the results above, we can reobtain results for the second homology and cohomology groups of
$\mathrm{P}\Sigma _n$
obtained by Brownstein and Lee [Reference Brownstein and Lee8], and Jensen, McCammond, and Meiyer [Reference Jensen, McCammond and Meier21]. The first and the second integral homology groups of
$\mathrm{P}\Sigma _n$
are determined by Brownstein and Lee [Reference Brownstein and Lee8], and the integral cohomology ring of
$\mathrm{P}\Sigma _n$
is determined by Jensen, McCammond, and Meiyer [Reference Jensen, McCammond and Meier21]. By using the second Johnson homomorphism and the McCool presentation for
$\mathrm{P}\Sigma _n$
, in Propositions 10.1 and 10.2, we obtain the following. For
$n \geq 3$
,
-
(1)
$H_2(\mathrm{P}\Sigma _n,\mathbf{Z}) \cong \mathbf{Z}^{\frac {1}{2}n^2(n-1)(n-2)}$
. -
(2) The cup product map
$\cup\,:\,\wedge ^2 H^1(\mathrm{P}\Sigma _n, \mathbf{Z}) \rightarrow H^2(\mathrm{P}\Sigma _n, \mathbf{Z})$
is surjective.
1.3. Twisted first cohomology groups
Finally, we consider twisted first cohomology groups of the braid-permutation automorphism groups of free groups. An element
$\sigma \in \mathrm{Aut}\,F_n$
is a braid-permutation automorphism of
$F_n$
if there exists some
$\mu \in \mathfrak{S}_n$
and some
$a_i \in F_n$
for any
$1 \leq i \leq n$
such that
Let
$\mathrm{BP}_n$
be the subgroup of
$\mathrm{Aut}\,F_n$
consisting of all braid-permutation automorphisms of
$F_n$
. According to [Reference Fenn, Rimányi and Rourke16], we call
$\mathrm{BP}_n$
the braid-permutation automorphism group of
$F_n$
. We remark that
$\mathrm{BP}_n$
is isomorphic to the loop braid group on
$n$
components. (For details, see Sections 3 and 4 in [Reference Damiani11] for example.) We see
$\mathrm{BP}_n \cap \mathcal{A}_n(1) = \mathrm{P}\Sigma _n$
.
By considering the Lyndon–Hochshild–Serre spectral sequence of the group extension
we can see the twisted first cohomology group
$H^1(\mathrm{BP}_n, H_1(\mathrm{P}\Sigma _n,\mathbf{Z}))$
is nontrivial. So we are interested in twisted first cohomology groups of
$\mathrm{BP}_n$
with coefficients in an
$\mathfrak{S}_n$
-equivariant submodule of
$H_1(\mathrm{P}\Sigma _n,\mathbf{Z})$
. As is the cases for the mapping class groups and the automorphism groups of free groups, see Motira [Reference Morita26] and Satoh [Reference Satoh29], respectively, one of fundamental modules is the standard irreducible representation of
$\mathfrak{S}_n$
, denoted by
$V$
. By observing the decomposition of the image of
$\tau _{1, \mathbf{Q}}^P$
, we see that
$V$
appears in the decomposition of
$H_1(\mathrm{P}\Sigma _n, \mathbf{Q})$
. By using a finite presentation for
$\mathrm{BP}_n$
obtained by Fenn–Rimányi–Rourke [Reference Fenn, Rimányi and Rourke16], as an analogue of calculations of twisted first cohomology groups of
$\mathrm{Aut}\,F_n$
in [Reference Satoh29], we obtain the following.
Theorem 5 (Theorem 11.1). For
$n \geq 3$
,
$H^1(\mathrm{BP}_n, V) \cong \mathbf{Z}^{\oplus 2} \oplus \mathbf{Z}/4\mathbf{Z}$
.
Let
$B_n$
be Artin’s braid group of
$n$
strands. Due to a classical work of Artin, it is known that
$B_n$
can be regard as a subgroup of
$\mathrm{Aut}\,F_n$
. From this viewpoint, by observing the calculations in the proof of Theorem 5, we can see that for
$n \geq 3$
,
2. Notation and conventions
In this section, we fix notation and conventions. In this article, a group means a multiplicative group if otherwise noted. Let
$G$
be a group.
-
• The abelianization of
$G$
is denoted by
$G^{\mathrm{ab}}$
if otherwise noted. -
• The automorphism group
$\mathrm{Aut}\,G$
acts on
$G$
from the right. For any
$\sigma \in \mathrm{Aut}\,G$
and
$x \in G$
, the action of
$\sigma$
on
$x$
is denoted by
$x^{\sigma }$
. -
• For a normal subgroup
$N$
, we often denote the coset class of an element
$g \in G$
by the same
$g$
in the quotient group
$G/N$
if there is no confusion. -
• For elements
$x$
and
$y$
of
$G$
, the commutator bracket
$[x,y]$
of
$x$
and
$y$
is defined to be
$[x,y]\,:\!=xyx^{-1}y^{-1}$
. Then for any
$x, y, z \in G$
, we have(1)and
\begin{equation} [xy,z] =[x,[y,z]][y,z][x,z], \hspace {1em} [x,yz] = [x,y][x,z][[z,x],y] \end{equation}
(2)
\begin{equation} [x^{-1},z]=[[x^{-1}, z],x][x,z]^{-1}, \hspace {1em} [x,y^{-1}] = [x,y]^{-1} [y,[y^{-1}, x]]. \end{equation}
-
• For subgroups
$H$
and
$K$
of
$G$
, we denote by
$[H,K]$
the commutator subgroup of
$G$
generated by
$[h, k]$
for all
$h \in H$
and
$k \in K$
. -
• For elements
$g_1, \ldots , g_k \in G$
, a left-normed commutatorof weight
\begin{equation*} [[ \cdots [[ g_{1},g_{2}],g_{3}], \cdots ], g_{k}] \in G \end{equation*}
$k$
is denoted by
$[g_{1},g_{2}, \cdots , g_{k}]$
.
-
• For any
$\mathbf{Z}$
-module
$A$
, we denote the
$\mathbf{Q}$
-vector space
$A \otimes _{\mathbf{Z}} \mathbf{Q}$
by the symbol obtained by attaching a subscript or superscript
$\mathbf{Q}$
to
$A$
, like
$A_{\mathbf{Q}}$
or
$A^{\mathbf{Q}}$
. Similarly, for any
$\mathbf{Z}$
-linear map
$f\,:\, A \rightarrow B$
, the induced
$\mathbf{Q}$
-linear map
$A_{\mathbf{Q}} \rightarrow B_{\mathbf{Q}}$
is denoted by
$f_{\mathbf{Q}}$
or
$f^{\mathbf{Q}}$
.
3. Free Lie algebras and their derivation algebras
In this section, we review free Lie algebras and their derivation algebras. Furthermore, we consider a certain Lie subalgebra of the derivation algebra of the free Lie algebra.
For
$n \geq 1$
, let
$F_n$
be the free group of rank
$n$
with basis
$x_1, \ldots , x_n$
. Let
$\Gamma _n(1) \supset \Gamma _n(2) \supset \cdots$
be the lower central series of
$F_n$
defined by
We denote by
$\mathcal{L}_n(k) \,:\!= \Gamma _n(k)/\Gamma _n(k+1)$
the
$k$
-th graded quotient of the lower central series of
$F_n$
, and by
$\mathcal{L}_n \,:\!= {\bigoplus }_{k \geq 1} \mathcal{L}_n(k)$
the associated graded sum. For each
$k \geq 1$
, we consider
$\mathcal{L}_n(k)$
as an additive group. For example, for any
$x, y, z \in F_n$
we have
in
$\mathcal{L}_n(1)$
from (1) and (2). The graded sum
$\mathcal{L}_n$
has the Lie algebra structure with the Lie bracket induced from the commutator bracket of
$F_n$
. It is known that the Lie algebra
$\mathcal{L}_n$
is isomorphic to the free Lie algebra generated by
$\mathcal{L}_n(1)$
by a classical work of Magnus. (For details, see [Reference Magnus, Karras and Solitar24] and [Reference Reutenauer28] for example.) Thus, each of
$\mathcal{L}_n(k)$
is a free abelian group of finite rank. Witt [Reference Witt39] gave a formula for the rank of
$\mathcal{L}_n(k)$
as
where
$\mu$
is the Möbius function, and
$d$
runs over all positive divisors of
$k$
. Hall [Reference Hall18] constructed an explicit basis of
$\mathcal{L}_n(k)$
with basic commutators of weight
$k$
. For example, basic commutators of weight less than five are listed below.

Here
$(i,j) \gt (l,m)$
means the lexicographic order on
$\mathbf{N} \times \mathbf{N}$
. (For details, see [Reference Hall19] and [Reference Reutenauer28] e.g.,.)
For simplicity, we denote by
$H$
the abelianization
$F_n^{\mathrm{ab}}=H_1(F_n,\mathbf{Z})$
of
$F_n$
. The basis
$x_1, \ldots , x_n$
of
$F_n$
induces a basis of
$H$
as a free abelian group. We also denote it by the same letters
$x_1, \ldots , x_n$
by abuse of language. By fixing this basis of
$H$
, we identify the automorphism group
$\mathrm{Aut}\,H$
with the general linear group
$\mathrm{GL}(n,\mathbf{Z})$
. Then
$\mathrm{GL}(n,\mathbf{Z})$
naturally acts on each of
$\mathcal{L}_n(k)$
. For example, as a
$\mathrm{GL}(n,\mathbf{Z})$
-module, we have
$\mathcal{L}_n(1) = H$
and
$\mathcal{L}_n(2) = \wedge ^2 H$
. Furthermore,
$\mathrm{GL}(n,\mathbf{Q})$
naturally acts on each of
$\mathcal{L}_n^{\mathbf{Q}}(k)$
. The irreducible decompositions of
$\mathcal{L}_n^{\mathbf{Q}}(k)$
for
$1 \leq k \leq 4$
are given as follows.

Here
$[\lambda ]$
means the irreducible polynomial representation of
$\mathrm{GL}(n,\mathbf{Q})$
associated to the Young tableau
$\lambda$
.
The universal enveloping algebra of
$\mathcal{L}_n$
is the tensor algebra
of
$H$
over
$\mathbf{Z}$
. From Poincaré–Birkhoff–Witt’s theorem, the natural map
$\iota\,:\,\mathcal{L}_n \rightarrow T(H)$
is injective. We denote by
$\iota _k\,:\,\mathcal{L}_n(k) \rightarrow H^{\otimes k}$
the homomorphism of degree
$k$
part of
$\iota$
and consider
$\mathcal{L}_n(k)$
as a
$\mathrm{GL}(n,\mathbf{Z})$
-submodule
$H^{\otimes k}$
through
$\iota _k$
. Similarly, we consider
$\mathcal{L}_n^{\mathbf{Q}}(k)$
as a
$\mathrm{GL}(n,\mathbf{Q})$
-submodule
$H_{\mathbf{Q}}^{\otimes k}$
through
$\iota _k^{\mathbf{Q}}$
.
Next, we consider the derivation algebra of the free Lie algebra. We denote the Lie algebra of derivations of
$\mathcal{L}_n$
by
The Lie algebra
$\mathrm{Der}(\mathcal{L}_n)$
is a graded Lie algebra. For
$k \geq 0$
, the degree
$k$
part of
$\mathrm{Der}(\mathcal{L}_n)$
is defined to be
For
$k \geq 1$
, by considering the universality of the free Lie algebra, we indentify
$\mathrm{Der}(\mathcal{L}_n)(k)$
with
$\mathrm{Hom}_{\mathbf{Z}}(H,\mathcal{L}_n(k+1)) = H^* {\otimes }_{\mathbf{Z}} \mathcal{L}_n(k+1)$
as a
$\mathrm{GL}(n,\mathbf{Z})$
-module. Let
$x_1^*, \ldots , x_n^*$
be the dual basis of
$x_1, \ldots , x_n \in H$
. Then
$\mathrm{Der}(\mathcal{L}_n)(k)$
is generated by
$x_i^* \otimes [x_{j_1}, x_{j_2}, \ldots , x_{j_{k+1}}]$
for all
$1 \leq i, j_1, \ldots , j_{k+1} \leq n$
as a
$\mathbf{Z}$
-module. Let
$\mathrm{Der}^+(\mathcal{L}_n)$
be the graded Lie subalgebra of
$\mathrm{Der}(\mathcal{L}_n)$
with positive degree. Similarly, we define the graded Lie algebra
$\mathrm{Der}^+(\mathcal{L}_{n}^{\mathbf{Q}})$
. Then, we have
$\mathrm{Der}^+(\mathcal{L}_{n}^{\mathbf{Q}}) = \mathrm{Der}^+(\mathcal{L}_n) \otimes _{\mathbf{Z}} \mathbf{Q}$
, and
$\mathrm{Der}(\mathcal{L}_n^{\mathbf{Q}})(k)=H_{\mathbf{Q}}^* {\otimes }_{\mathbf{Q}} \mathcal{L}_n^{\mathbf{Q}}(k+1)$
for any
$k \geq 1$
.
Definition 3.1.
For any
$k \geq 1$
, let
$\mathfrak{p}_n(k)$
be the
$\mathbf{Z}$
-submodule of
$\mathrm{Der}(\mathcal{L}_n)(k)$
generated by elements
for all
$1 \leq i, j_1, \ldots , j_k \leq n$
. Let
$\mathfrak{p}_n$
be the graded sum
$\bigoplus _{k \geq 1} \mathfrak{p}_n(k)$
.
Alekseev and Torossian [Reference Alekseev and Torossian1] showed that
$\mathfrak{p}_n$
is a Lie subalgebra of
$\mathrm{Der}^+(\mathcal{L}_n)$
. (See also Satoh [Reference Satoh36].) We remark that
$x_i^* \otimes [x_j, x_i]$
for any
$1 \leq i \neq j \leq n$
form a basis of
$\mathfrak{p}_n(1)$
, and
$\mathfrak{p}_n(k)$
is isomorphic to
$H \otimes _{\mathbf{Z}} \mathcal{L}_n(k)$
as an
$\mathfrak{S}_n$
-module. Hence, we have
$\mathrm{rank}_{\mathbf{Z}}(\mathfrak{p}_n(k)) = nr_n(k)$
for any
$k \geq 2$
.
4. Johnson homomorphisms
Here we recall the Andreadakis–Johnson filtrations and the Johnson homomorphisms of the automorphism groups of free groups. For each
$k \geq 1$
, the action of
$\mathrm{Aut}\,F_n$
on the nilpotent quotient group
$F_n/\Gamma _n(k+1)$
of
$F_n$
induces the homomorphism
We denote its kernel by
$\mathcal{A}_n(k)$
. Then the groups
$\mathcal{A}_n(k)$
define the descending filtration
of
$\mathrm{Aut}\,F_n$
. This filtration is called the Andreadakis–Johnson filtration of
$\mathrm{Aut}\,F_n$
, and the first term is called the IA-automorphism group of
$F_n$
, denoted by
$\mathrm{IA}_n$
. Historically, the Andreadakis–Johnson filtration was originally introduced by Andreadakis [Reference Andreadakis2] in the 1960s. He showed that
Theorem 4.1 (Andreadakis [Reference Andreadakis2]).
-
(1) For any
$k$
,
$l \geq 1$
,
$\sigma \in \mathcal{A}_n(k)$
and
$x \in \Gamma _n(l)$
,
$x^{-1} x^{\sigma } \in \Gamma _n(k+l)$
. -
(2) For any
$k$
and
$l \geq 1$
,
$[\mathcal{A}_n(k), \mathcal{A}_n(l)] \subset \mathcal{A}_n(k+l)$
. -
(3)
$\displaystyle \bigcap _{k \geq 1} \mathcal{A}_n(k) =\{ 1 \}$
.
For each
$k \geq 1$
, the group
$\mathrm{Aut}\,F_n$
acts on
$\mathcal{A}_n(k)$
by conjugation, and this action naturally induces the action of
$\mathrm{GL}(n,\mathbf{Z})=\mathrm{Aut}\,F_n/\mathrm{IA}_n$
on the graded quotients
$\mathrm{gr}^k (\mathcal{A}_n) \,:\!= \mathcal{A}_n(k)/\mathcal{A}_n(k+1)$
by Part (2) of Theorem 4.1.
In order to study the
$\mathrm{GL}(n,\mathbf{Z})$
-module structure of
${\mathrm{gr}}^k (\mathcal{A}_n)$
, we consider the Johnson homomorphisms. For each
$k \geq 1$
, define the homomorphism
$\tilde {\tau }_k\,:\,\mathcal{A}_n(k) \rightarrow \mathrm{Hom}_{\mathbf{Z}}(H, {\mathcal{L}}_n(k+1))$
by
The kernel of
$\tilde {\tau }_k$
is
$\mathcal{A}_n(k+1)$
. Hence, it induces the injective homomorphism
The homomorphisms
$\tilde {\tau }_k$
and
${\tau }_{k}$
are called the
$k$
-th Johnson homomorphisms of
$\mathrm{Aut}\,F_n$
. Each of
${\tau }_{k}$
is
$\mathrm{GL}(n,\mathbf{Z})$
-equivariant. The graded sum
$\mathrm{gr}(\mathcal{A}_n) \,:\!= \bigoplus _{k \geq 1} \mathrm{gr}^k (\mathcal{A}_n)$
has the Lie algebra structure with the Lie bracket induced from the commutator bracket on
$\mathrm{IA}_n$
. Furthermore, the graded sum
$\tau \,:\!= \bigoplus _{k \geq 1} \tau _k\,:\,\mathrm{gr}(\mathcal{A}_n) \rightarrow \mathrm{Der}^+(\mathcal{L}_n)$
is a Lie algebra homomorphism.
Here we remark on the cokernels of the Johnson homomorphisms. For
$k \geq 1$
, let
${\varphi }^{k}\,:\,H^* {\otimes }_{\mathbf{Z}} H^{\otimes (k+1)} \rightarrow H^{\otimes k}$
be the contraction map defined by
For the natural embedding
${\iota }_{k+1}\,:\,\mathcal{L}_n(k+1) \rightarrow H^{\otimes (k+1)}$
, we obtain the
$\mathrm{GL}(n,\mathbf{Z})$
-equivariant homomorphism
We also call
$\Phi ^k$
the contraction map of degree
$k$
. From Lemma 3.1 in [Reference Satoh30], we have the following.
Lemma 4.2.
For any
$1 \leq i, i_1, \ldots , i_{k} \leq n$
such that
$i_1 \neq i$
, not required
$i_1, \ldots , i_k$
are distinct, we have
\begin{align*} \begin{split} \Phi ^k(x_i^* \otimes & [x_i, x_{i_1}, \ldots , x_{i_{k}}]) \\ & = x_{i_1} \otimes \cdots \otimes x_{i_{k}} - \sum _{l=2}^k \delta _{i, i_l} [x_i, x_{i_1}, \ldots , x_{i_{l-1}}] \otimes x_{i_{l+1}} \otimes \cdots \otimes x_{i_k}. \end{split} \end{align*}
Let
$\mathcal{C}_n(k)$
be the quotient module of
$H^{\otimes k}$
by the action of the cyclic group
$C_k$
of order
$k$
on the components. Namely,
Let
$\varpi ^k\,:\,H^{\otimes k} \rightarrow \mathcal{C}_n(k)$
be the natural projection. For any
$1 \leq j_1, \ldots , j_k \leq n$
, we write the image of
$x_{j_1} \otimes \cdots \otimes x_{j_k} \in H^{\otimes k}$
by the map
$\varpi ^k$
as
$x_{j_1} x_{j_2} \cdots x_{j_k} \in \mathcal{C}_n(k)$
. Thus, we have
$x_{j_1} x_{j_2} \cdots x_{j_k}=x_{j_2} \cdots x_{j_k} x_{j_1}$
in
$\mathcal{C}_n(k)$
. By [Reference Reutenauer28], it is known that
$\mathcal{C}_n(k)$
is a free abelian group, and the necklaces among
$x_1, \ldots , x_n$
of length
$k$
form a basis of
$\mathcal{C}_n(k)$
. Hence, we have
where
$\varphi\,:\,\mathbf{N} \rightarrow \mathbf{N}$
is the Euler function, and
$d$
runs over all positive divisors of
$k$
.
Set
$\mathrm{Tr}_k \,:\!= \varpi ^k \circ \Phi ^k\,:\,H^* {\otimes }_{\mathbf{Z}} \mathcal{L}_n(k+1) \rightarrow \mathcal{C}_n(k)$
. We call
$\mathrm{Tr}^k$
the trace map of degree
$k$
. By combining the results by Satoh [Reference Satoh30, Reference Satoh34] and Darne [Reference Darné12], we see that for any
$k \geq 2$
and
$n \geq k+2$
, the sequence
is a
$\mathrm{GL}(n,\mathbf{Z})$
-equivariant exact sequence. Furthermore, Enomoto-Satoh [Reference Enomoto and Satoh14] gave a combinatorial description of the
$\mathrm{GL}(n,\mathbf{Q})$
-irreducible decomposition of the stable rational cokernel
$\mathcal{C}_n^{\mathbf{Q}}(k)$
of the Johnson homomorphism
$\tau _{k,\mathbf{Q}}$
. For
$1 \leq k \leq 5$
, the decompositions are given as follows.

Here we remark that for any
$k \geq 2$
, the irreducible component
$[k]$
, which is the symmetric product of
$H_{\mathbf{Q}}$
of degree
$k$
, appears in
$\mathcal{C}_n^{\mathbf{Q}}(k)$
with multiplicity one. This result was originally obtained by Morita [Reference Morita27]. Enomoto-Satoh [Reference Enomoto and Satoh14] showed that
$[1^k]$
for any odd
$k \geq 3$
and
$n \geq k+2$
and
$[2,1^{k-2}]$
for even
$k \geq 4$
and
$n \geq k+2$
appear in
$\mathcal{C}_n^{\mathbf{Q}}(k)$
with multiplicity one.
Here we remark the Andreadakis problem on
$\mathrm{Aut}\,F_n$
. Let
$\mathrm{IA}_n = \mathcal{A}_n'(1) \supset \mathcal{A}_n'(2) \supset \cdots$
be the lower central series of
$\mathrm{IA}_n$
, Since the Andreadakis–Johnson filtration is a central filtration of
$\mathrm{IA}_n$
, we see
$\mathcal{A}_n'(k) \subset \mathcal{A}_n(k)$
for any
$k \geq 1$
.
Conjecture 4.3 (The Andreadakis conjecture). For any
$n \geq 3$
and
$k \geq 1$
,
$\mathcal{A}_n'(k) = \mathcal{A}_n(k)$
.
Andreadakis showed that the above conjecture is true for
$n=2$
and any
$k \geq 2$
and
$n=3$
and
$k \leq 3$
. It is known that
$\mathcal{A}_n'(2) = \mathcal{A}_n(2)$
for any
$n \geq 2$
due to Bachmuth [Reference Bachmuth4]. This result is also obtained from the fact that the first Johnson homomorphism is the abelianization of
$\mathrm{IA}_n$
by independent works of Cohen-Pakianathan [Reference Cohen and Pakianathan9, Reference Cohen and Pakianathan10], Farb [Reference Farb15], and Kawazumi [Reference Kawazumi23]. Satoh [Reference Satoh37] showed that
$\mathcal{A}_n'(3) = \mathcal{A}_n(3)$
for
$n \geq 3$
. Bartholdi [Reference Bartholdi5, Reference Bartholdi6] showed that this conjecture is not true in general. In particular, he showed that
$\mathcal{A}_3(4)/\mathcal{A}_3'(4) \cong (\mathbf{Z}/2\mathbf{Z})^{\oplus 14} \oplus (\mathbf{Z}/3\mathbf{Z})^{\oplus 9}$
and
$\mathcal{A}_3(5)/\mathcal{A}_3'(5) \otimes _{\mathbf{Z}} \mathbf{Q} \cong \mathbf{Q}^{\oplus 3}$
. In the stable range, the Andreadakis conjecture is still open problem. We remark that Darné [Reference Darné12] gave affirmative answers for the Andreadakis problems restricted to certain subgroups of
$\mathrm{Aut}\,F_n$
.
5. The basis-conjugating automorphism groups
Here we recall the basis-conjugating automorphisms of
$F_n$
. Let
$\mathrm{P}\Sigma _n$
be the subgroup of
$\mathrm{Aut}\,F_n$
consisting of all basis-conjugating automorphisms of
$F_n$
. The group
$\mathrm{P}\Sigma _n$
is a subgroup of
$\mathrm{IA}_n$
. For any
$1 \leq i \neq j \leq n$
, let
$K_{ij}$
be the basis-conjugating automorphism of
$F_n$
defined by
\begin{align*} x_t \mapsto \begin{cases} {x_j}^{-1} x_i x_j & t=i, \\ x_t & t \neq i. \end{cases} \end{align*}
McCool gave a finite presentation for
$\mathrm{P}\Sigma _n$
as follows.
Theorem 5.1 (McCool [Reference McCool25]). The group
$\mathrm{P}\Sigma _n$
is generated by
$K_{ij}$
for
$1 \leq i \neq j \leq n$
subject to relations:
-
(P1) :
$[K_{ij},K_{kj}]=1$
for
$(i,j) \lt (k,j)$
, -
(P2) :
$[K_{ij}, K_{kl}]=1$
for
$(i,j)\lt (k,l)$
, -
(P3) :
$[K_{ik}, K_{ij} K_{kj}]=1$
where in each relation, the indeces
$i$
,
$j$
,
$k$
,
$l$
are distinct.
We construct a group extension of
$\mathrm{P}\Sigma _n$
by
$\mathfrak{S}_n$
as follows. Let
$B_n$
be Artin’s braid group of
$n$
-strands. Artin [Reference Artin3] obtained the first finite presentation
Moreover, Artin constructed a faithful representation of
$B_n$
into
$\mathrm{Aut}\,F_n$
. For any
$1 \leq i \leq n-1$
, the image of
$\sigma _i$
by this representation is given by
\begin{align*} x_t \mapsto \begin{cases} x_i^{-1} x_{i+1} x_i & t=i, \\ x_i & t=i+1, \\ x_t & t \neq i, i+1. \end{cases} \end{align*}
We also denote this automorphism of
$F_n$
by
$\sigma _i$
and consider
$B_n$
as a subgroup of
$\mathrm{Aut}\,F_n$
. The subgroup
$B_n \cap \mathrm{IA}_n$
of
$B_n$
is the pure braid group of
$n$
-strands and is denoted by
$P_n$
. (For details, see [Reference Birman7] for example.)
According to [Reference Fenn, Rimányi and Rourke16], we call an element
$\sigma \in \mathrm{Aut}\,F_n$
a braid-permutation automorphism of
$F_n$
if there exists some
$\mu \in \mathfrak{S}_n$
and some
$a_i \in F_n$
for any
$1 \leq i \leq n$
such that
Let
$\mathrm{BP}_n$
be the subgroup of
$\mathrm{Aut}\,F_n$
consisting of all braid-permutation automorphisms of
$F_n$
. The group
$\mathrm{BP}_n$
is called the braid-permutation automorphism group of
$F_n$
. The subgroup
$\mathrm{BP}_n \cap \mathrm{IA}_n$
of
$\mathrm{BP}_n$
is the basis-conjugating automorphism group
$\mathrm{P}\Sigma _n$
. For any
$1 \leq i \leq n-1$
, let
$s_i$
be the automorphism of
$F_n$
which permutates
$x_i$
and
$x_{i+1}$
, and fixes the other generators of the basis of
$F_n$
. Clearly, the subgroup of
$\mathrm{Aut}\,F_n$
generated by
$s_i$
for all
$1 \leq i \leq n-1$
is isomorphic to
$\mathfrak{S}_n$
. Fenn–Rimányi–Rourke gave a finite presentation for
$\mathrm{BP}_n$
as follows.
Theorem 5.2 (Fenn–Rimányi–Rourke [Reference Fenn, Rimányi and Rourke16]). The group
$BP_n$
generated by
$\sigma _i$
and
$s_i$
for
$1 \leq i \leq n-1$
subject to relations:
-
(B1) :
$\sigma _i \sigma _{i+1} \sigma _i = \sigma _{i+1} \sigma _{i} \sigma _{i+1}$
for
$1 \leq i \leq n-2$
, -
(B2) :
$[\sigma _i, \sigma _j]=1$
for
$|i-j| \geq 2$
, -
(SY1) :
$s_i^2=1$
for
$1 \leq i \leq n-1$
, -
(SY2) :
$s_i s_{i+1} s_i = s_{i+1} s_i s_{i+1}$
for
$1 \leq i \leq n-2$
, -
(SY3) :
$[s_i, s_j]=1$
for
$|i-j| \geq 2$
, -
(BP1) :
$\sigma _i s_j = s_j \sigma _i$
for
$|i-j| \geq 2$
, -
(BP2) :
$s_i s_{i+1} \sigma _i = \sigma _{i+1} s_i s_{i+1}$
for
$1 \leq i \leq n-2$
, -
(BP3) :
$\sigma _i \sigma _{i+1} s_i = s_{i+1} \sigma _i \sigma _{i+1}$
for
$1 \leq i \leq n-2$
.
Then we have the following commutative diagram whose three rows are group extensions, and whose all vertical maps are injective.

Here
$\rho\,:\,\mathrm{Aut}\,F_n \rightarrow \mathrm{GL}(n,\mathbf{Z})$
is the homomorphism induced from the abelianization of
$F_n$
.
For any
$k \geq 1$
, set
$\mathcal{P}_n(k)\,:\!= \mathrm{P}\Sigma _n \cap \mathcal{A}_n(k)$
. The filtration
$\mathrm{P}\Sigma _n = \mathcal{P}_n(1) \supset \mathcal{P}_n(2) \supset \cdots$
is a descending central filtration of
$\mathrm{P}\Sigma _n$
. Set
$\mathrm{gr}^k(\mathcal{P}_n)\,:\!= \mathcal{P}_n(k)/\mathcal{P}_n(k+1)$
. In Proposition 3.5 in [Reference Satoh36], Satoh showed that for any
$n \geq 2$
and
$k \geq 1$
, the image of the restriction of
$\tilde {\tau }_k\,:\,\mathcal{A}_n(k) \rightarrow H^* \otimes _{\mathbf{Z}} \mathcal{L}_n(k+1)$
to
$\mathcal{P}_n(k)$
is contained in
$\mathfrak{p}_n(k)$
.
Definition 5.3. We call the induced injective homomorphism
from
$\tilde {\tau }_k|_{\mathcal{P}_n(k)}$
the
$k$
-th Johnson homomorphism of
$\mathrm{P}\Sigma _n$
.
It is known that for each
$k \geq 1$
, the Johnson homomorphism
$\tau _k^P$
is
$\mathrm{BP}_n/\mathrm{P}\Sigma _n = \mathfrak{S}_n$
-equvariant. and that
$\tau _1^P$
induces the abelianization of
$\mathrm{P}\Sigma _n$
. The graded sum
$\mathrm{gr}(\mathcal{P}_n) \,:\!= \oplus _{k \geq 1} \mathrm{gr}^k(\mathcal{P}_n)$
is considered as the Lie subalgebra of
$\mathrm{gr}(\mathcal{A}_n)$
, and the graded sum
$\tau ^P \,:\!= \oplus _{k \geq 1} \tau _k^P\,:\,\mathrm{gr}(\mathcal{P}_n) \rightarrow \mathfrak{p}_n$
is a Lie algebra homomorphism.
Let
$\mathrm{P}\Sigma _n=\mathrm{P}\Sigma _n{(1)} \supset \mathrm{P}\Sigma _n{(2)} \supset \cdots$
be the lower central series of
$\mathrm{P}\Sigma _n$
. We have
$\mathrm{P}\Sigma _n{(k)} \subset \mathcal{P}_n(k)$
for any
$k \geq 1$
. Satoh [Reference Satoh35] showed that
$\mathrm{P}\Sigma _n{(k)} = \mathcal{P}_n(k)$
for
$k \leq 3$
. In general, it is not known whether
$\mathrm{P}\Sigma _n{(k)}$
coincides with
$\mathcal{P}_n(k)$
or not for any
$n \geq 3$
and
$k \geq 4$
. Let
$\mathrm{P}\Sigma _n^+$
be the subgroup of
$\mathrm{P}\Sigma _n$
generated by
$K_{ij}$
for all
$1 \leq j \lt i \leq n$
. We remark that Darné [Reference Darné13] proved that
$\mathrm{P}\Sigma _n^+ \cap \mathcal{A}_n(k)$
coincides with the
$k$
-the subgroup of the lower central series of
$\mathrm{P}\Sigma _n^+$
for any
$k \geq 1$
.
6. Trace maps
Here we consider the trace maps and its variants to detect the cokernel of
$\tau _k^P$
for any
$k \geq 1$
. Let
$\mathrm{Tr}_k^P\,:\,\mathfrak{p}_n(k) \rightarrow \mathcal{C}_n(k)$
be the restriction of
$\mathrm{Tr}_k$
to
$\mathfrak{p}_n(k)$
. From [Reference Satoh30] and Darné [Reference Darné12], we have
$\mathrm{Im}(\tau _k) \subset \mathrm{Ker}(\mathrm{Tr}_k)$
for any
$n \geq 2$
and
$k \geq 2$
. From this we see
$\mathrm{Im}(\tau _k^P) \subset \mathrm{Ker}(\mathrm{Tr}_k^P)$
. Hence, in order to study
$\mathrm{Coker}(\tau _k^P)$
, it is interesting problem to determine the image of the trace map
$\mathrm{Tr}_k^P$
.
It is easy to see that for any
$k \geq 2$
,
$\langle x_1^k, \ldots , x_n^k \rangle \cap \mathrm{Im}(\mathrm{Tr}_k^P) = \{ 0 \}$
. (See also Proposition 3.7 in [Reference Satoh36].) Set
$\overline {\mathcal{C}}_n(k) \,:\!= \mathcal{C}_n(k)/\langle x_1^k, \ldots , x_n^k \rangle$
. By compositing
$\mathrm{Tr}_k^P$
and the natural projection
$\mathcal{C}_n(k) \rightarrow \overline {\mathcal{C}}_n(k)$
, we obtain the map
$\overline {\mathrm{Tr}}_k^P\,:\,\mathfrak{p}_n(k) \rightarrow \overline {\mathcal{C}}_n(k)$
. As we will mention in Section 7, the map
$\overline {\mathrm{Tr}}_k^P$
is surjective for
$k \leq 3$
. Hence, we can describe the rational Johnson cokernel by using
$\overline {\mathrm{Tr}}_k^P$
in these cases. In general, however,
$\overline {\mathrm{Tr}}_k^P$
is not surjective, and it seems a difficult problem to determine its image. Here we consider some reduced versions of
$\overline {\mathrm{Tr}}_k^P$
. In [Reference Satoh36], one of such reduced versions of
$\mathrm{Tr}_k^P$
was studied. More precisely, consider the quotient
$\mathfrak{S}_n$
-module
$\overline {S}^k(H)\,:\!=S^k(H)/\langle x_1^k, \ldots , x_n^k \rangle$
and the natural projection
$\lambda _k\,:\,\mathcal{C}_n(k) \rightarrow \overline {S}^k(H)$
. In Proposition 3.7 in [Reference Satoh36], Satoh showed that the map
$\lambda _k \circ \mathrm{Tr}_k^P$
is surjective for
$n \geq 2$
and
$k \geq 2$
.
Here we introduce the other trace maps that detect different components other than
$\overline {S}^k(H_{\mathbf{Q}})$
in
$\mathrm{Coker}(\tau _{k,\mathbf{Q}}^P)$
.
Definition 6.1.
For any
$k \geq 2$
, let
$N(k)$
be the
$\mathfrak{S}_n$
-invariant submodule of
$\mathcal{C}_n(k)$
generated by
$x_{j_1} x_{j_2} \cdots x_{j_k}$
for all
$1 \leq j_1, \ldots , j_k \leq n$
such that each
$j_l$
$(1 \leq l \leq k)$
appears at least twice in
$j_1, j_2, \ldots , j_k$
.
For example, basis of
$N(k)$
for
$2 \leq k \leq 4$
are given as follows.

Set
$\widetilde {\mathcal{C}}_n(k) \,:\!= \mathcal{C}_n(k)/N(k)$
. Let
$\mu _k\,:\,\mathcal{C}_n(k) \rightarrow \widetilde {\mathcal{C}}_n(k)$
be the natural projection and set
$\widetilde {\phantom{\,}\mathrm{Tr}\phantom{\,}}_{\!k}^{\!P}\,:\!= \mu _k \circ \mathrm{Tr}_k^P\,:\,\mathfrak{p}_n(k) \rightarrow \widetilde {\mathcal{C}}_n(k)$
. Then we have
Theorem 6.2.
For any
$n \geq 2$
and
$k \geq 2$
, the map
$\widetilde {\phantom{\,}\mathrm{Tr}\phantom{\,}}_{\!k}^{\!P}$
is surjective.
Proof.
As a
$\mathbf{Z}$
-module,
$\widetilde {\mathcal{C}}_n(k)$
is generated by elements
$x_{j_1} x_{j_2} \cdots x_{j_k} \in \widetilde {\mathcal{C}}_n(k)$
such that there exists some
$1 \leq l \leq k$
such that
$j_l \neq j_m$
for all
$m \neq l$
. By using Lemma 4.2, we have
Since
$\mathcal{L}_n(k) \subset \mathrm{Ker}(\varpi _k)$
, we see that
Thus,
$\widetilde {\phantom{\,}\mathrm{Tr}\phantom{\,}}_{\!k}^{\!P}$
is surjective.
Corollary 6.3.
For any
$n \geq 2$
and
$k \geq 2$
, the module
$\widetilde {\mathcal{C}}_n^{\mathbf{Q}}(k)$
injects into
$\mathrm{Coker}(\tau _{k,\mathbf{Q}}^P)$
There is the natural surjective homomorphism
$\widetilde {\mathcal{C}}_n(k) \rightarrow \overline {S}^k(H)$
. Hence, in the case where
$k=2$
and
$3$
, Proposition 3.7 in [Reference Satoh36] is a corollary of Theorem 6.2.
Corollary 6.4.
For any odd
$k \geq 3$
and
$n \geq k$
, we have the natural surjective homomorphism
$\widetilde {\mathcal{C}}_n(k) \rightarrow \wedge ^k H$
. Therefore, after tensoring with
$\mathbf{Q}$
, we see that the module
$\wedge ^k H_{\mathbf{Q}}$
injects into
$\mathrm{Coker}(\tau _{k,\mathbf{Q}}^P)$
.
7. The Johnson cokernels in the case where
$k \leq 4$
In this section, we determine the images and the cokernels of
$\tau _k^P$
for
$1 \leq k \leq 4$
by using the trace maps considered in Section 6. First, we recall some results in [Reference Satoh35].
For
$k=1$
, the first Johnson homomorphism
$\tau _1^P\,:\,\mathrm{gr}^1(\mathcal{P}_n) \rightarrow \mathfrak{p}_n(1)$
is an isomorphism, and
$\mathrm{Im}(\tau _1^P)$
is a free abelian group of rank
$n(n-1)$
with a basis
$\{x_i^* \otimes [x_j, x_i] \,|\, 1 \leq i \neq j \leq n \}$
. From Lemma 2.3 in [Reference Satoh35], we see that
$\mathrm{Im}(\tau _2^P)$
is a free abelian group of rank
$\frac {n(n-1)^2}{2}$
with a basis
for
$n \geq 3$
.
Proposition 7.1.
For
$n \geq 3$
, we have
-
(1)
$\overline {\mathrm{Tr}}_2^P=\widetilde {\mathrm{Tr}}_2^P$
is surjective.
-
(2)
$\mathrm{Im}(\tau _2^P)=\mathrm{Ker}(\overline {\mathrm{Tr}}_2^P)$
.
Proof.
(1) By definition, we see
$\overline {\mathrm{Tr}}_2^P=\widetilde {\mathrm{Tr}}_2^P$
. For any generator
$x_i x_j$
(
$i \neq j$
) of
$\overline {\mathcal{C}}_n(2)$
, we have
Hence,
$\overline {\mathrm{Tr}}_2^P$
is surjective.
(2) It suffices to show
$\mathrm{Im}(\tau _2^P) \supset \mathrm{Ker}(\overline {\mathrm{Tr}}_2^P)$
. Take any
\begin{equation*} x \,:\!= \sum _{\substack {1 \leq i \leq n\\[1pt] 1 \leq j_2 \lt j_1 \leq n}} a_{j_1, j_2}^i x_i^* \otimes [x_{j_1}, x_{j_2}, x_i] \in \mathrm{Ker}(\overline {\mathrm{Tr}}_2^P). \end{equation*}
Since
$\mathrm{Im}(\tau _2^P) \subset \mathrm{Ker}(\overline {\mathrm{Tr}}_2^P)$
, we show that we can add elements in the Johnson image to
$x$
until we get zero. Namely, by adding elements in (5) to
$x$
if necessary, we may assume
Then we obtain
and hence
$a_{i, j}^i=0$
for any
$i\lt j$
. Thus,
$x=0$
.
Corollary 7.2.
For
$n \geq 3$
,
is
$\mathfrak{S}_n$
-equivariant exact.
Next, we consider the case where
$k=3$
. We prepare the following lemma.
Lemma 7.3.
For any
$k \geq 3$
and any
$1 \leq i \leq n$
, if
$1 \leq j_1, \ldots , j_k \leq n$
and
$i \neq j_1, \ldots , j_k$
, then
$x_i^* \otimes [x_{j_1}, \ldots , x_{j_k}, x_i] \in \mathrm{Im}(\tau _k^P)$
.
Proof.
We prove this lemma by induction on
$k \geq 2$
. For
$k=2$
, it is clear from (5). Assume
$k \geq 3$
. By the inductive hypothesis, we see
If we write
$x_i^* \otimes [x_{j_1}, \ldots , x_{j_k-1}, x_i]$
as
$\tau _{k-1}^P(\sigma )$
for
$\sigma \in \mathcal{P}_n(k-1)$
, then we have
\begin{align*} \begin{split} \tau _k^P([\sigma , K_{i, j_k}]) &= [\tau _{k-1}^P(\sigma ), \tau _1^P(K_{i, j_k})] \\ &=[x_i^* \otimes [x_{j_1}, \ldots , x_{j_k-1}, x_i], x_i^* \otimes [x_i, x_{j_k}] ] \\ &=x_i^* \otimes [x_{j_1}, \ldots , x_{j_k-1}, [x_i, x_{j_k}] ] - x_i^* \otimes [x_{j_1}, \ldots , x_{j_k-1}, x_i, x_{j_k}] \\ &= - x_i^* \otimes [x_{j_1}, \ldots , x_{j_k}, x_i]. \end{split} \end{align*}
At the last equation, we use the Jacobi identity. Hence, the induction proceeds.
Proposition 7.4.
For
$n \geq 3$
, we have
-
(1)
$\overline {\mathrm{Tr}}_3^P=\widetilde {\mathrm{Tr}}_3^P$
is surjective.
-
(2)
$\mathrm{Im}(\tau _3^P)=\mathrm{Ker}(\overline {\mathrm{Tr}}_3^P)$
. -
(3)
$\mathrm{Im}(\tau _3^P)$
is a free abelian group with a basis
\begin{equation} \begin{split} \{ x_i^* & \otimes [x_{j_1}, x_{j_2}, x_{j_3}, x_i] \,|\, j_1 \gt j_2 \leq j_3, \hspace {0.5em} i \neq j_1, j_2, j_3 \} \\ & \cup \{ x_i^* \otimes [x_i, x_j, x_i, x_i] - x_j^* \otimes [x_j, x_i, x_i, x_j] \,|\, 1 \leq i \neq j \leq n \} \\ & \cup \{ x_i^* \otimes [x_i, x_j, x_l, x_i] - x_j^* \otimes [x_j, x_l, x_i, x_j] \,|\, l \neq i \gt j \neq l \} \end{split} \end{equation}
Proof.
(1) By definition, we see
$\overline {\mathrm{Tr}}_3^P=\widetilde {\mathrm{Tr}}_3^P$
.
$\overline {\mathcal{C}}_n(3)$
is generated by
$x_ix_jx_l$
and
$x_i^2x_j$
for all distinct
$1 \leq i, j, l \leq n$
. Since
\begin{align*} \begin{split} \overline {\mathrm{Tr}}_3^P(x_i^* \otimes [x_i, x_j, x_l, x_i]) & = x_jx_lx_i=x_ix_jx_l, \\ \overline {\mathrm{Tr}}_3^P(x_i^* \otimes [x_i, x_j, x_i, x_i]) & = x_jx_i^2=x_i^2x_j,\end{split} \end{align*}
we see that
$\overline {\mathrm{Tr}}_3^P$
is surjective.
(2) It suffices to show
$\mathrm{Im}(\tau _3^P) \supset \mathrm{Ker}(\overline {\mathrm{Tr}}_3^P)$
. Take any
\begin{equation*} x \,:\!= \sum _{\substack {1 \leq i \leq n\\[1pt] j_1\gt j_2 \leq j_3}} a_{j_1, j_2, j_3}^i x_i^* \otimes [x_{j_1}, x_{j_2}, x_{j_3}, x_i] \in \mathrm{Ker}(\overline {\mathrm{Tr}}_3^P). \end{equation*}
Observe
for any
$1 \leq i, j, j_1, j_2 \leq n$
. Remark that
by the Jacobi identity. Since
$\mathrm{Im}(\tau _3^P) \subset \mathrm{Ker}(\overline {\mathrm{Tr}}_3^P)$
, and from Lemma 7.3 and (7), we may assume
\begin{equation*} x=\sum _{\substack {1 \leq i, j, l \leq n\\[1pt] j, l \neq i}} a_{i, j, l}^i x_i^* \otimes [x_i, x_j, x_l, x_i]. \end{equation*}
Furthermore, by observing
for any distinct
$i, j$
and
$l$
, we may also assume
\begin{equation*} x=\sum _{\substack {i\lt j, l\\[1pt] j \neq l}} a_{i, j, l}^i x_i^* \otimes [x_i, x_j, x_l, x_i] + \sum _{1 \leq i \neq j \leq n} a_{i, j, j}^i x_i^* \otimes [x_i, x_j, x_j, x_i]. \end{equation*}
Then we obtain
\begin{equation*} 0=\tau _3^P(x)=\sum _{\substack {i\lt j, l\\[1pt] j \neq l}} a_{i, j, l}^i x_ix_jx_l + \sum _{1 \leq i \neq j \leq n} a_{i, j, j}^i x_ix_j^2, \end{equation*}
and hence
$a_{i, j, l}^i=0$
for any
$i, j$
and
$l$
. Thus,
$x=0$
. (3) From Part (2), we see that
$\mathrm{Im}(\tau _3^P)$
is generated by
\begin{align*} \begin{cases} x_i^* \otimes [x_{j_1}, x_{j_2}, x_{j_3}, x_i] \hspace {1em} & i \neq j_1, j_2, j_3, \\ x_i^* \otimes [x_i, x_j, x_i, x_i] - x_j^* \otimes [x_j, x_i, x_i, x_j] & i \neq j, \\ x_i^* \otimes [x_i, x_j, x_l, x_i] - x_j^* \otimes [x_j, x_l, x_i, x_j] & i \neq j \neq l \neq i \end{cases} \end{align*}
as a
$\mathbf{Z}$
-module.
Corollary 7.5.
For
$n \geq 3$
,
is
$\mathfrak{S}_n$
-equivariant exact.
In [Reference Enomoto and Satoh14], we showed that
$\mathcal{C}_n^{\mathbf{Q}}(3)$
is isomorphic to
$S^3 H_{\mathbf{Q}} \oplus \wedge ^3 H_{\mathbf{Q}}$
. From this fact and Corollary 7.5, we have the
$\mathfrak{S}_n$
-equivariant exact sequence
for
$n \geq 3$
.
Finally, we consider the case where
$k=4$
. At first, we prepare a few lemmas.
Lemma 7.6.
For any
$n \geq 3$
, the module
$\mathfrak{p}_n(4)$
is generated by all
\begin{equation} \begin{cases} x_i^* \otimes [x_{j_1}, x_{j_2}, x_{j_3}, x_{j_4}, x_i] \hspace {1em} & i \neq j_1, j_2, j_3, j_4, \\ x_i^* \otimes [x_i, x_{j_2}, x_{j_3}, x_{j_4}, x_i] & i \neq j_2, j_3, j_4, \\ x_i^* \otimes [x_i, x_{j_2}, x_{i}, x_{j_4}, x_i] & i \neq j_2, j_4, \\ x_i^* \otimes [x_i, x_{j_2}, x_{j_3}, x_i, x_i] & i \neq j_2, j_3, \\ x_i^* \otimes [x_i, x_{j_2}, x_i, x_i, x_i] & i \neq j_2 \\ \end{cases} \end{equation}
for
$1 \leq i, j_1, j_2, j_3, j_4 \leq n$
as a
$\mathbf{Z}$
-module.
Proof.
By the definition,
$\mathfrak{p}_n(4)$
is generated by elements
$x_i^* \otimes [x_{j_1}, x_{j_2}, x_{j_3}, x_{j_4}, x_i]$
for all
$1 \leq i, j_1, j_2, j_3, j_4 \leq n$
as a
$\mathbf{Z}$
-module. Set
$\omega \,:\!= x_i^* \otimes [x_{j_1}, x_{j_2}, x_{j_3}, x_{j_4}, x_i]$
. If
$j_1, \ldots , j_4 \neq i$
, then
$\omega$
is an element of first type. If
$j_1, j_2 \neq i$
and
$j_3=i$
, then by
from the Jacobi identity, we see that
$\omega$
can be written as a sum of elements the form in (8). If
$j_1, j_2, j_3 \neq i$
and
$j_4=i$
, then we can show by an argument similar to that in case where
$j_1, j_2 \neq i$
and
$j_3=i$
. If
$j_1=i$
and
$j_2 \neq i$
, or if
$j_2=i$
and
$j_1 \neq i$
, then we see that
$\omega$
is an element of the above form.
Lemma 7.7.
For any
$n \geq 3$
, the map
$\overline {\mathrm{Tr}}_4^P$
is not surjective, and its cokernel is a free abelian group of rank
$n(n-1)/2$
.
Proof.
A basis of
$\overline {\mathcal{C}}_n(4)$
is given by as follows:
-
•
$x_ax_bx_cx_d$
for any distinct
$a, b, c, d$
such that
$a\lt b, c, d$
, -
•
$x_a^2 x_bx_c$
for any distinct
$a, b, c$
, -
•
$x_a x_b x_a x_c$
for any distinct
$a, b, c$
such that
$b\lt c$
, -
•
$x_a^2 x_b^2$
for any
$a \lt b$
, -
•
$x_ax_bx_ax_b$
for any
$a \lt b$
, -
•
$x_a^3 x_b$
for any
$a \neq b$
.
On the other hand, the images of the generators of
$\mathfrak{p}_n(4)$
shown in (8) by
$\overline {\mathrm{Tr}}_4^P$
are given by
\begin{align*} \begin{cases} \overline {\mathrm{Tr}}_4^P(x_i^* \otimes [x_{j_1}, x_{j_2}, x_{j_3}, x_{j_4}, x_i])=0 \hspace {1em} & i \neq j_1, j_2, j_3, j_4, \\ \overline {\mathrm{Tr}}_4^P(x_i^* \otimes [x_i, x_{j_2}, x_{j_3}, x_{j_4}, x_i])= x_{j_2}x_{j_3}x_{j_4}x_i & i \neq j_2, j_3, j_4, \\ \overline {\mathrm{Tr}}_4^P(x_i^* \otimes [x_i, x_{j_2}, x_{i}, x_{j_4}, x_i])=2x_{j_2}x_ix_{j_4}x_i - x_{j_2}x_{j_4}x_i^2 & i \neq j_2, j_4, \\ \overline {\mathrm{Tr}}_4^P(x_i^* \otimes [x_i, x_{j_2}, x_{j_3}, x_i, x_i])=2x_{j_2}x_ix_{j_3}x_i - x_{j_2}x_{j_3}x_i^2 & i \neq j_2, j_3, \\ \overline {\mathrm{Tr}}_4^P(x_i^* \otimes [x_i, x_{j_2}, x_i, x_i, x_i])=x_{j_2}x_i^3 & i \neq j_2. \\ \end{cases} \end{align*}
Hence, the elements of the basis types of
$x_ax_bx_cx_d$
,
$x_a^2 x_bx_c$
,
$x_a x_b x_a x_c$
, and
$x_a^3 x_b$
are in
$\mathrm{Im}(\overline {\mathrm{Tr}}_4^P)$
. Indeed, for example,
Therefore, we see that
$\mathrm{Coker}(\overline {\mathrm{Tr}}_4^P)$
is isomorphic to the quotient module of the free
$\mathbf{Z}$
-module with basis
$x_a^2 x_b^2$
and
$x_ax_bx_ax_b$
for all
$a \lt b$
divided by the submodule generated by
$2x_ax_bx_ax_b - x_a^2x_b^2$
for all
$a \lt b$
. This completes the proof.
Proposition 7.8.
For
$n \geq 3$
, we have
$\mathrm{Im}(\tau _4^P)=\mathrm{Ker}(\overline {\mathrm{Tr}}_4^P)$
.
Proof.
It suffices to show
$\mathrm{Im}(\tau _4^P) \supset \mathrm{Ker}(\overline {\mathrm{Tr}}_4^P)$
. Take any
$x \in \mathrm{Ker}(\overline {\mathrm{Tr}}_4^P)$
. For distinct
$1 \leq i, j, l \leq n$
, set
Since
$D_1 \in \mathrm{Ker}(\overline {\mathrm{Tr}}_3^P) = \mathrm{Im}(\tau _3^P)$
, there exists some
$L_1 \in \mathcal{P}_n(3)$
such that
$\tau _3^P(L_1)=D_1$
. From Lemma 7.3 and
\begin{equation} \begin{split} \tau _4^P([K_{ij},K_{ji}, K_{ji}, K_{ji}]) &= x_i^* \otimes [x_i, x_j, x_i, x_i, x_i] - x_j^* \otimes [x_j, x_i, x_i, x_i, x_j], \\ \tau _4^P([K_{ij},K_{ji}, K_{ji}, K_{ij}]) &= x_i^* \otimes [x_i, x_j, x_j, x_i, x_i] - x_j^* \otimes [x_j, x_i, x_j, x_i, x_j], \\ \tau _4^P([K_{ji}, L_1]) &= x_i^* \otimes [x_i, x_j, x_l, x_i, x_i] - 2 x_j^* \otimes [x_j, x_i, x_l, x_i, x_j] \\ & \hspace {2em} + x_j^* \otimes [x_j, x_i, x_i, x_l, x_j], \\ \end{split} \end{equation}
for any distinct
$1 \leq i, j, l \leq n$
, by reducing the generators shown in (8) by using these elements, we may assume
For distinct
$1 \leq i, j, l \leq n$
, set
Since
$D_2 \in \mathrm{Ker}(\overline {\mathrm{Tr}}_3^P) = \mathrm{Im}(\tau _3^P)$
, there exists some
$L_2 \in \mathcal{P}_n(3)$
such that
$\tau _3^P(L_2)=D_2$
. Thus, we have
Moreover, by the Jacobi identity, we have
and hence from the second equation of (9), we may assume
$\beta _{j, m}^i=0$
if
$j \neq m$
, or
$j=m$
and
$i\gt j$
.
On the other hand, consider the following equations.
for
$1 \leq a, b, c, d \leq n$
such that
$c \neq d$
and
$b \neq c$
.
for
$1 \leq a, b, c, d \leq n$
such that
$b \neq c$
.
for
$1 \leq a, b, c, d \leq n$
such that
$b, c \neq d$
. Then from (12) for the case where
$b=c$
, we see that we may assume
$\alpha _{j,l,l}^i=0$
. Similarly, from (10) for the case where
$b=d$
, we see that we may assume
$\alpha _{j,l,j}^i=0$
if
$i\gt j$
. Furthermore, for distinct
$i, j, l, m$
, by using (10), (11) and (12), we may assume
$\alpha _{j, l, m}^i=0$
for the case other than
$i\lt j, l, m$
. Therefore,
$x$
can be written as
\begin{align*} \begin{split} x &=\sum _{\substack {i\lt j, l, m \\[1pt] j, l, m\,:\,\text{distinct}}} \alpha _{j, l, m}^i x_i^* \otimes [x_i, x_j, x_l, x_m, x_i] + \sum _{\substack {i\lt l \\[1pt] j \neq i, l}} \alpha _{j, l, j}^i x_i^* \otimes [x_i, x_j, x_l, x_j, x_i] \\ & + \sum _{i, j, l\,:\,\text{distinct}} \alpha _{j, j, l}^i x_i^* \otimes [x_i, x_j, x_j, x_l, x_i] + \sum _{i \neq j} \alpha _{j, j, j}^i x_i^* \otimes [x_i, x_j, x_j, x_j, x_i] \\ &+ \sum _{i\lt j} \beta _{j, j}^i x_i^* \otimes [x_i, x_j, x_i, x_j, x_i]. \end{split} \end{align*}
By observing
\begin{align*} \begin{split} 0=\overline {\mathrm{Tr}}_4^P(x) &=\sum _{\substack {i\lt j, l, m \\[1pt] j, l, m\,:\,\text{distinct}}} \alpha _{j, l, m}^i x_j x_l x_m x_i + \sum _{\substack {i\lt l \\[1pt] j \neq i, l}} \alpha _{j, l, j}^i x_j x_l x_j x_i \\ & + \sum _{i, j, l\,:\,\text{distinct}} \alpha _{j, j, l}^i x_j^2 x_l x_i + \sum _{i \neq j} \alpha _{j, j, j}^i x_j^3 x_i \\ &+ \sum _{i\lt j} \beta _{j, j}^i (2x_i x_j x_i x_j - x_i^2x_j^2), \end{split} \end{align*}
we obtain that all of the coefficients in the above equation is
$0$
, and hence
$x=0$
.
Corollary 7.9.
For
$n \geq 3$
,
is
$\mathfrak{S}_n$
-equivariant exact. In particular,
$\mathrm{Im}(\tau _4^P)$
is a free abelian group of rank
$\frac {1}{4}n^2(n-1)^2(n+1)$
.
We remark that for any
$1 \leq a \lt b \leq n$
, since
from the above calculation, we see
$\mathrm{Ker}(\overline {\mathrm{Tr}}_4^P) \subsetneq \mathrm{Ker}(\widetilde {\mathrm{Tr}}_4^P)$
. In general, we have the following.
Lemma 7.10.
For any
$k \geq 4$
,
$\mathrm{Ker}(\overline {\mathrm{Tr}}_k^P) \subsetneq \mathrm{Ker}(\widetilde {\phantom{\,}\mathrm{Tr}\phantom{\,}}_{\!k}^{\!P})$
. Namely, we cannot detect all
$\mathfrak{S}_n$
-components in
$\mathrm{Coker}(\tau _{k,\mathbf{Q}}^P)$
by
$\widetilde {\phantom{\,}\mathrm{Tr}\phantom{\,}}_{\!k}^{\!P}$
for any
$k \geq 4$
.
Proof.
For any distinct
$1 \leq i, j \leq n$
, consider an element
$x_i^* \otimes [x_i, x_j, x_i, x_j, \ldots , x_j, x_i] \in \mathfrak{p}_n(k)$
. Then we have
This shows
$\mathrm{Ker}(\overline {\mathrm{Tr}}_k^P) \subsetneq \mathrm{Ker}(\widetilde {\phantom{\,}\mathrm{Tr}\phantom{\,}}_{\!k}^{\!P})$
.
On the other hand, for
$k=4$
, the
$\mathfrak{S}_n$
-irreducible component in
$\mathrm{Coker}(\tau _4^P)$
which cannot detect
$\widetilde {\mathrm{Tr}}_4^P$
is the module
This component can be detected as follows. Let
$J$
be the quotient module of
$\wedge ^2 H \otimes \wedge ^2 H$
by the submodule generated by
-
•
$(v \wedge w) \otimes (x \wedge y) - (x \wedge y) \otimes (v \wedge w)$
, -
•
$(v \wedge w) \otimes (x \wedge y) - (x \wedge w) \otimes (v \wedge y) - (v \wedge x) \otimes (w \wedge y)$
for any
$v, w, x, y \in H$
. Then
$J$
is a free abelian group of rank
$n^2(n^2-1)/12$
. As a
$\mathrm{GL}(n,\mathbf{Q})$
-module,
$J_{\mathbf{Q}}$
is irreducible and isomorphic to
$[2,2]$
. In [Reference Satoh33], we construct a trace map which detect
$J_{\mathbf{Q}}$
in the cokernel of
$\tau _{4,\mathbf{Q}}$
. For
$i=1, 2$
, let
$f_i\,:\,H^{\otimes 4} \rightarrow J$
be the projection defined by
\begin{align*} f_i(v \otimes w \otimes x \otimes y) = \begin{cases} (v \wedge x) \cdot (w \wedge y), \hspace {1em} & i=1, \\ (v \wedge y) \cdot (w \wedge x), \hspace {1em} & i=2. \\ \end{cases} \end{align*}
Set
By Proposition 4.2 in [Reference Satoh33] and Darné’s result in [Reference Darné12], we have
$\mathrm{Im}(\tau _4) \subset \mathrm{Ker}(\mathrm{Tr}_J)$
. Denote by
$\mathrm{Tr}_J^P\,:\,\mathfrak{p}_n(4) \rightarrow J$
the restriction of
$\mathrm{Tr}_J$
to
$\mathfrak{p}_n(4)$
. Since we see
we see that
$\mathrm{Tr}_J$
detects
$A$
.
Here we give the list of the rank of the free abelian groups
$\mathrm{gr}^k(\mathcal{P}_n)$
,
$\mathfrak{p}_n(k)$
,
$\mathcal{C}_n(k)$
and
$\mathrm{Coker}(\overline {\mathrm{Tr}}_k^P)$
for
$n \geq 3$
and
$1 \leq k \leq 4$
.

8. Observations of the Johnson images and cokernels for
$k \geq 5$
In this section, we give some observations of the dimensions of the Johnson images and cokernels for the case of
$k \geq 5$
based on some direct computer calculations. We will use the following notations. For an
$\alpha =(\alpha _1,\alpha _2, \ldots ,\alpha _n) \in \mathbb{Z}_{\ge 0}^n$
such that
$\alpha _1+ \alpha _2+ \cdots +\alpha _n=k$
, let
$p(\alpha )$
be the set of all permutations of
$(1^{\alpha _1},2^{\alpha _2}, \cdots ,n^{\alpha _n})$
. We denote
$\mathcal{L}_n(k,\alpha )$
by the subspace of
$\mathcal{L}_n(k)$
generated by all left-normed elements
$[x_{i_1},x_{i_2}, \ldots ,x_{i_k}]$
such that
$(i_1,i_2, \ldots ,i_k) \in p(\alpha )$
. Notice that
$\alpha _j=\sharp \{1 \leq u \leq k \ | \ i_u=j\} \ (1 \leq j \leq n)$
. We also note that
$\dim _{\mathbf{Q}}\mathcal{L}_n^{\mathbf{Q}}(k,\alpha )=0$
for
$\alpha =(k)$
. Similarly, let
$\overline {\mathcal{C}}_n(k,\alpha )$
be the subspace of
$\overline {\mathcal{C}}_n(k)$
generated by all cosets (necklace) of
$x_{i_1}x_{i_2} \cdots x_{i_k}$
for
$(i_1,i_2, \ldots ,i_k) \in p(\alpha )$
.
For an element
$[x_{i_1}, \ldots ,x_{i_k}] \in \mathcal{L}_n(k,\alpha )$
, through the natural embedding
$\mathcal{L}_n(k)$
into
$H^{\otimes k}$
, we consider
$[x_{i_1}, \ldots ,x_{i_k}] \in H^{\otimes k}$
, and take the expression
$[x_{i_1}, \ldots ,x_{i_k}]=\sum _{j=1}^{n}x_j \otimes b_j(i_1,\ldots ,i_k)$
, where
$b_j(i_1,\ldots ,i_k) \in H^{\otimes {k-1}}$
. Since
$\varpi ^k([x_{i_1}, \ldots ,x_{i_k}])=0$
, we have
\begin{align*} &\overline {\mathrm{Tr}}_k^P(x_i^* \otimes [x_{i_1}, \ldots ,x_{i_k},x_i])= \overline {\mathrm{Tr}}_k^P(x_i^* \otimes ([x_{i_1}, \ldots ,x_{i_k}] \otimes x_i-x_i \otimes [x_{i_1}, \ldots ,x_{i_k}]))\\ & =\overline {\varpi }^k(b_i(i_1, \ldots ,i_k) \otimes x_i-[x_{i_1},\ldots ,x_{i_k}]) =\overline {\varpi }^k(b_i(i_1, \ldots ,i_k) \otimes x_i) \in \overline {\mathcal{C}}_n(k,\alpha ), \end{align*}
where
$\overline {\varpi }^k\,:\,H^{\otimes {k}} \to \overline {\mathcal{C}}_n(k)$
is the composition of
$\varpi ^k$
and the natural projection
$\mathcal{C}_n(k) \to \overline {\mathcal{C}}_n(k)$
. Moreover,
is invariant under the left (variable permutation) action of
$\mathfrak{S}_n$
on
$\alpha$
. Thus, we may consider the case where
$\alpha _1 \geq \alpha _2 \geq \cdots \geq \alpha _n$
. We obtain the following proposition.
Proposition 8.1.
The dimension of the image of
$\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P$
is given by the following formula;
where
$|\mathfrak{S}_n \cdot \alpha |$
is the order of
$\mathfrak{S}_n$
-orbit of
$\alpha$
.
When
$\alpha$
contains
$1$
, we can detect all cosets in
$\overline {\mathcal{C}}_n(k,\alpha )$
as in the image of
$\overline {\mathrm{Tr}}_k^P$
by the surjectivity of
$\widetilde {\phantom{\,}\mathrm{Tr}\phantom{\,}}_{\!k}^{\!P}$
from Theorem 6.2. In this case we have
$c_\alpha =\dim _{\mathbf{Q}}\overline {\mathcal{C}}_n^{\mathbf{Q}}(k,\alpha )=\dim _{\mathbf{Q}}\mathcal{L}_n^{\mathbf{Q}}(k,\alpha )$
, since in this case all necklaces in
$\overline {\mathcal{C}}_n(k,\alpha )$
have the period
$k$
(i.e., primitive). Therefore, in order to compute the dimension of
$\mathrm{Im}(\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P)$
, it suffices to consider the case where all positive parts of
$\alpha$
are greater than or equal to
$2$
.
For
$5 \leq k \leq 9$
, we obtain the following tables of
$c_\alpha$
and the difference
$d_\alpha \,:\!=c_\alpha -\dim _{\mathbf{Q}}\mathcal{L}_n^{\mathbf{Q}}(k,\alpha )$
by computer calculations.
\begin{align*} \begin{array}{cccc} k & \alpha & c_\alpha & d_\alpha \\ \hline \hline 5 & (3,2) & 1 & 0 \\ \hline 6 & (4,2) & 2 & 0 \\ & (3,3) & 3 & 0 \\ & (2^3) & 15 & 1 \\ \hline 7 & (5,2) & 3 & 0 \\ & (4,3) & 5 & 0 \\ & (3,2^2) & 30 & 0 \\ \end{array} \quad \quad \begin{array}{cccc} k & \alpha & c_\alpha & d_\alpha \\ \hline \hline 8 & (6,2) & 2 & -1 \\ & (5,3) & 6 & -1 \\ & (4,4) & 7 & -1 \\ & (4,2^2) & 52 & 1 \\ & (3^2,2) & 69 & -1 \\ & (2^4) & 316 & 4\\ & \quad & & \end{array} \quad \quad \begin{array}{cccc} k & \alpha & c_\alpha & d_\alpha \\ \hline \hline 9 & (7,2) & 4 & 0 \\ & (6,3) & 9 & 0 \\ & (5,4) & 14 & 0 \\ & (5,2^2) & 84 & 0 \\ & (4,3,2) & 140 & 0 \\ & (3^3) & 188 & 2 \\ & (3,2^3) & 840 & 0 \end{array} \end{align*}
Using (13), for
$n \ge 3$
, we have
\begin{align*} &\dim _{\mathbf{Q}}\mathrm{Im}(\overline {\mathrm{Tr}}_{5,\mathbf{Q}}^P)=r_n(5), \quad \dim _{\mathbf{Q}}\mathrm{Im}(\overline {\mathrm{Tr}}_{6,\mathbf{Q}}^P)=r_n(6)+\tbinom {n}{3}, \quad \dim _{\mathbf{Q}}\mathrm{Im}(\overline {\mathrm{Tr}}_{7,\mathbf{Q}}^P)=r_n(7), \\ &\dim _{\mathbf{Q}}\mathrm{Im}(\overline {\mathrm{Tr}}_{8,\mathbf{Q}}^P)=r_n(8)-2n(n-1)-\tbinom {n}{2}+4\tbinom {n}{4} \delta _{n \geq 4}, \\ &\dim _{\mathbf{Q}}\mathrm{Im}(\overline {\mathrm{Tr}}_{9,\mathbf{Q}}^P)=r_n(9)+2\tbinom {n}{3}, \end{align*}
where we recall that
$r_n(k)$
is the rank of
$\mathcal{L}_n(k)$
. For example, when
$k=5$
, the suitable
$\alpha$
is only
$(3,2)$
. Moreover,
$c_{(3,2)}=\dim _{\mathbf{Q}}\mathcal{L}^{\mathbf{Q}}_n(5,(3,2))$
. Therefore,
$\dim _{\mathbf{Q}}\overline {C}_n^{\mathbf{Q}}(5,\alpha )=\dim _{\mathbf{Q}}\mathcal{L}_n^{\mathbf{Q}}(5,\alpha )$
for all
$\alpha$
. Hence, we have
$\dim _{\mathbf{Q}}\mathrm{Im}(\overline {\mathrm{Tr}}_{5,\mathbf{Q}}^P)=r_n(5)$
by (13). When
$k=6$
, we have
$\dim _{\mathbf{Q}}\overline {C}_n^{\mathbf{Q}}(6,(2,2,2))=\dim _{\mathbf{Q}}{}\mathcal{L}_n^{\mathbf{Q}}(6,(2,2,2))+1$
. Thus, we obtain
$\dim _{\mathbf{Q}}\mathrm{Im}(\overline {\mathrm{Tr}}_{6,\mathbf{Q}}^P)=r_n(6)+\binom {n}{3}$
by (13) since
$|\mathfrak{S}_n \cdot (2,2,2)|=\binom {n}{3}$
.
Corollary 8.2.
For
$k=5$
or
$7$
, and
$n \ge 3$
,
$\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P$
is surjective. For
$k=11$
, and
$n \ge 2$
,
$\overline {\mathrm{Tr}}_{11, \mathbf{Q}}^P$
is not surjective.
Proof.
We note that, for prime
$k$
,
$\dim _{\mathbf{Q}}\overline {\mathcal{C}}_n^{\mathbf{Q}}(k)=r_n(k)$
. We obtain that
$\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P$
is surjective since
$\dim _{\mathbf{Q}}\mathrm{Im}(\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P)=r_n(k)$
for
$k=5$
and
$7$
. On the other hand, for
$k=11$
, we can also calculate that
$d_\alpha =-1,-2$
for
$\alpha =(8,3),(7,4)$
, respectively, by computer. Therefore,
$\overline {\mathrm{Tr}}_{11, \mathbf{Q}}^P$
is not surjective.
Let us proceed to the observations of the Johnson images. By fixing
$n$
, we can directly calculate the dimension of the submodule
generated by the degree
$1$
part by using a computer. We obtain the following proposition for the gaps of
$\mathrm{Im}(\tau _k^P)_1$
and
$\mathrm{Ker}(\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P)$
.
Proposition 8.3.
-
(1) For
$n=2$
, we have
$\mathrm{Im}(\tau _{11,\mathbf{Q}}^P) \subsetneq \mathrm{Ker}(\overline {\mathrm{Tr}}_{11,\mathbf{Q}}^P)$
. -
(2) For
$n=3$
, we have
$\mathrm{Im}(\tau _{k,\mathbf{Q}}^P)_1 =\mathrm{Ker}(\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P)$
for
$1 \leq k \leq 6$
and
$\mathrm{Im}(\tau _{k,\mathbf{Q}}^P)_1 \subsetneq \mathrm{Ker}(\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P)$
for
$k=7$
. Moreover the module
$\mathrm{Ker}(\overline {\mathrm{Tr}}_{7,\mathbf{Q}}^P)/\mathrm{Im}(\tau _{7,\mathbf{Q}}^P)_1$
is isomorphic to the regular representation of
$\mathfrak{S}_3$
.
Proof.
(1) In the case of
$n=2$
, we have
$\mathcal{P}_2(k)=\mathcal{A}_2(k)$
for any
$k \geq 1$
, and see that the filtration
$\mathcal{P}_2(1) \supset \mathcal{P}_2(2) \supset \cdots$
is the lower central series of the inner automorphism group
$\mathrm{Inn}\,F_2$
. Hence,
$\mathrm{Im}(\tau _k^P) \cong \mathcal{L}_2(k)$
for any
$k \geq 1$
. As in the proof of Corollary 8.2, we have
$r_2(11)-\dim _{\mathbf{Q}}\mathrm{Im}(\overline {\mathrm{Tr}}_{11,\mathbf{Q}}^{P})\gt 0$
by considering the cases of
$\alpha =(8,3),(7,4)$
. Since
$\dim _{\mathbf{Q}}\mathrm{Ker}(\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P)=n r_n(k)- \dim _{\mathbf{Q}}\mathrm{Im}(\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P)$
, we obtain
$r_2(11)=\mathrm{dim}_{\mathbf{Q}} \mathcal{L}^{\mathbf{Q}}_2(11) \lt \mathrm{dim}_{\mathbf{Q}} \mathrm{Ker}(\overline {\mathrm{Tr}}_{11,\mathbf{Q}}^P)$
. Therefore
$\mathrm{Im}(\tau _{11,\mathbf{Q}}^P)_1 \subsetneq \mathrm{Ker}(\overline {\mathrm{Tr}}_{11,\mathbf{Q}}^P)$
.
(2) In the case of
$n=3$
, we have the following table on the dimensions of
$\mathrm{Im}(\tau _{k,\mathbf{Q}}^P)_1$
and the kernels of
$\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P$
by computer calculations.
\begin{align*} \begin{array}{c||cccccccc} k &\,\,\, 1 &\,\,\, 2 &\,\,\, 3 &\,\,\, 4 &\,\,\, 5 &\,\,\, 6 &\,\,\, 7 &\,\,\, 8 \\ \dim _{\mathbf{Q}}\mathrm{Im}(\tau _{k,\mathbf{Q}}^P)_1 &\,\,\, 6 &\,\,\, 6 &\,\,\, 16 &\,\,\, 36 &\,\,\, 96 &\,\,\, 231 &\,\,\, 618 &\,\,\, 1596 \\ \dim _{\mathbf{Q}}\mathrm{Ker}(\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P) &\,\,\, 6 &\,\,\, 6 &\,\,\, 16 &\,\,\, 36 &\,\,\, 96 &\,\,\, 231 &\,\,\, 624 &\,\,\, 1635 \end{array} \end{align*}
We find a gap at the incusion
$\mathrm{Im}(\tau _{k,\mathbf{Q}}^P)_1 \subsetneq \mathrm{Ker}(\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P)$
for
$k=7$
. By computer calculations, we can also see that this gap appears only the subspace for
$(j_1,\ldots ,j_7) \in \mathfrak{S}_3 \cdot (1^3,2^2,3^2)$
. Moreover, we can compute the character of the module
$\mathrm{Ker}(\overline {\mathrm{Tr}}_{7,\mathbf{Q}}^P)/\mathrm{Im}(\tau _{7,\mathbf{Q}}^P)_1$
directly. From this, it turns out that it is isomorphic to the regular representation of
$\mathfrak{S}_3$
.
Remark 8.4.
By (2) of the above proposition, we have
$\mathrm{Im}(\tau _{k,\mathbf{Q}}^P) =\mathrm{Ker}(\overline {\mathrm{Tr}}_{k,\mathbf{Q}}^P)$
for
$1 \leq k \leq 6$
. This shows that the natural homomorphism
$\nu\,:\,\mathrm{P}\Sigma _3(k)/\mathrm{P}\Sigma _3(k+1) \rightarrow \mathrm{gr}^k(\mathcal{P}_3)$
induced by the inclusion
$\mathrm{P}\Sigma _3(k) \hookrightarrow \mathcal{P}_3(k)$
is surjective for
$1 \leq k \leq 6$
after tensoring with
$\mathbf{Q}$
.
In general, it seems to be difficult to determine whether or not
$\mathrm{Im}(\tau _k^P)=\mathrm{Ker}(\overline {\mathrm{Tr}}_k^P)$
. Here we give a partial answer to this problem. For any
$\alpha =(\alpha _1,\alpha _2, \ldots ,\alpha _n) \in \mathbb{Z}_{\ge 0}^n$
such that
$\alpha _1+ \alpha _2+ \cdots +\alpha _n=k$
, denote by
$\mathfrak{p}_n(k,\alpha )$
the subspace of
$\mathfrak{p}_n(k)$
generated by all
$x_i^* \otimes [x_{i_1},x_{i_2}, \ldots ,x_{i_k}, x_i]$
such that
$(i_1,i_2, \ldots , i_k) \in p(\alpha )$
.
Theorem 8.5.
For any
$n \geq 3$
,
$k \geq 1$
and any
$\alpha =(\alpha _1,\alpha _2, \ldots ,\alpha _n) \in \mathbb{Z}_{\ge 0}^n$
such that
$\alpha _1+ \alpha _2+ \cdots +\alpha _n=k$
and
$\alpha _j=1$
for some
$1 \leq j \leq n$
, we have
$\mathrm{Ker}(\overline {\mathrm{Tr}}_k^P|_{\mathfrak{p}_n(k,\alpha )}) \subset \mathrm{Im}(\tau _k^P)$
.
Proof.
For any
$X \in \mathrm{Ker}(\overline {\mathrm{Tr}}_k^P|_{\mathfrak{p}_n(k,\alpha )})$
, set
for some
$a_{i, i_1, \ldots , i_k} \in \mathbf{Z}$
.
Step 1. We show that
$x_i^* \otimes [x_{i_1}, \ldots , x_{i_k}, x_i] \in \mathrm{Im}(\tau _k^P)$
if
$i_1, \ldots , i_k \neq i$
by the induction on
$k \geq 1$
. For
$k =1$
, it is trivial since
$\tau _1^P$
is surjective. Assume
$k \geq 2$
. By the inductive hypothesis, there exist some
$\sigma \in \mathcal{P}_n(k-1)$
and
$\tau \in \mathcal{P}_n(1)$
such that
Then we have
$\tau _k^P([\sigma , \tau ])=x_i^* \otimes [x_{i_1},x_{i_2}, \ldots , x_{i_k}, x_i]$
, and hence the induction proceeds. Since
$\mathrm{Im}(\tau _k^P) \subset \mathrm{Ker}(\overline {\mathrm{Tr}}_k^P)$
, this shows that we may assume that
$X$
is a linear combination of
$x_i^* \otimes [x_{i_1}, \ldots , x_{i_k}, x_i]$
such that there exists some
$1 \leq l \leq k$
such that
$i_l=i$
. Furthermore, if we use the Jacobi identity repeatedly, we have
\begin{align*} \begin{split} x_i^* & \otimes [x_{i_1}, \ldots x_{i_{l-1}}, x_i, x_{i_{l+1}}, \ldots , x_{i_k}, x_i] \\ & =- x_i^* \otimes [x_i, [x_{i_1}, \ldots x_{i_{l-1}}], x_{i_{l+1}}, \ldots , x_{i_k}, x_i], \\ & =- x_i^* \otimes [x_i, [x_{i_1}, \ldots x_{i_{l-2}}], x_{i_{l-1}}, x_{i_{l+1}}, \ldots , x_{i_k}, x_i] + x_i^* \otimes [x_i, x_{i_{l-1}}, [x_{i_1}, \ldots x_{i_{l-2}}], x_{i_{l+1}}, \ldots , x_{i_k}, x_i] \\ & = \cdots . \end{split} \end{align*}
Thus, we may assume that
$X$
is a linear combination of elements of type
$x_i^* \otimes [x_i, x_{i_2}, \ldots , x_{i_k}, x_i]$
.
Step 2. We consider elements
$x_i^* \otimes [x_i, x_{i_2}, \ldots , x_{i_k}, x_i]$
such that
$i_p=i$
for some
$2 \leq p \leq k$
. By the hypothesis of the proposition for
$\alpha$
, there exists some
$2 \leq l \leq k$
such that
$i_l$
appears only one time in
$i, i_2, \ldots , i_k$
. We see
$i_l \neq i$
. We show that
$x_i^* \otimes [x_i, x_{i_2}, \ldots , x_{i_k}, x_i]$
is a linear combination of elements of type
modulo
$\mathrm{Im}(\tau _k^P)$
by the induction on
$k \geq 2$
. For
$k=2$
, we consider
$x_i^* \otimes [x_i, x_{i_2}, x_i]$
for
$i_2 \neq i$
. We see that the claim hold in this case by
Assume
$k \geq 3$
. First, we consider the case where
$i_{l+1}, \ldots , i_k \neq i$
. From the argument is Step 1, we see
\begin{align*} \begin{split} \mathrm{Im}(\tau _k^P) \ni & [x_i^* \otimes [x_{i_l}, x_{i_{l+1}}, \ldots , x_{i_k}, x_i], x_{i_l}^* \otimes [x_i, x_{i_2}, \ldots , x_{i_{l-1}}, x_{i_l}]] \\ & = x_i^* \otimes [x_i, x_{i_2}, \ldots , x_{i_k}, x_i] - x_{i_l}^* \otimes [x_{i_l}, x_{i_{l+1}}, \ldots , x_{i_k}, x_i, x_{i_2}, \ldots , x_{i_l}] \\ & \hspace {0.5em} - \sum _{\substack {2 \leq m \leq l\\[1pt] i_m=i}} x_{i_l}^* \otimes [x_{i}, x_{i_2}, \ldots , x_{i_{m-1}}, [x_{i_l}, \ldots , x_{i_k}, x_i], x_{i_{m+1}}, \ldots , x_{i_l}], \end{split} \end{align*}
and see that the claim holds by using the Jacobi identity. Next we consider the case where
$i_m=i$
for some
$l+1 \leq m \leq k$
. By the inductive hypothesis, an element
can be written as a linear combination of elements of type
$x_{i_l}^* \otimes [x_{i_l}, x_{j_2}, \ldots , x_{j_{k-l+1}}, x_{i_l}]$
for
$j_2, \ldots , j_{k-l+1} \neq i_l$
modulo
$\mathrm{Im}(\tau _{k-l+1}^P)$
. On the other hand, we see
\begin{align*} \begin{split} [x_{i_l}^* \otimes [x_{i_l}, & x_{j_2}, \ldots , x_{j_{k-l+1}}, x_{i_l}], x_{i_l}^* \otimes [x_i, x_{i_2}, \ldots , x_{i_{l-1}}, x_{i_l}]] \\ & = x_{i_l}^* \otimes [x_i, x_{i_2}, \ldots , x_{i_{l-1}}, x_{i_l}, x_{j_2}, \ldots , x_{j_{k-l+1}}, x_{i_l}] \\ & \hspace {1em} + x_{i_l}^* \otimes [x_{i_l}, x_{j_2}, \ldots , x_{j_{k-l+1}}, [x_i, x_{i_2}, \ldots , x_{i_{l-1}}, x_{i_l}]] \\ & \hspace {1em} - x_{i_l}^* \otimes [x_i, x_{i_2}, \ldots , x_{i_{l-1}}, [x_{i_l}, x_{j_2}, \ldots , x_{j_{k-l+1}}, x_{i_l}]] \\ & = x_{i_l}^* \otimes [x_i, x_{i_2}, \ldots , x_{i_{l-1}}, x_{i_l}, x_{j_2}, \ldots , x_{j_{k-l+1}}, x_{i_l}] \\ & \hspace {1em} + x_{i_l}^* \otimes [x_{i_l}, x_{j_2}, \ldots , x_{j_{k-l+1}}, [x_i, x_{i_2}, \ldots , x_{i_{l-1}}], x_{i_l}]. \end{split} \end{align*}
Therefore, by the same arguments as the previous case, we see that the claim holds by using the Jacobi identity. Thus, the induction proceeds. we may assume that
$X$
is a linear combination of elements of type
$x_i^* \otimes [x_i, x_{i_2}, \ldots , x_{i_k}, x_i]$
for
$i_2, \ldots , i_k \neq i$
.
Step 3. Consider an element
$x_i^* \otimes [x_i, x_{i_2}, \ldots , x_{i_k}, x_i]$
for
$i_2, \ldots , i_k \neq i$
. If there exists another
$2 \leq l \leq k$
such that
$i_l$
appears only one time in
$i, i_2, \ldots , i_k$
, from the argument in Step 1, we have some
$\sigma \in \mathcal{P}_n(k-l+1)$
and
$\tau \in \mathcal{P}_n(l)$
such that
and
This shows that we may assume that
$X$
is a linear combination of elements of type
$x_i^* \otimes [x_i, x_{i_2}, \ldots , x_{i_k}, x_i]$
for
$i_2, \ldots , i_k \neq i$
such that
$i$
is the minimum element in
$i, i_2, \ldots , i_k$
, which appears only one time in
$i, i_2, \ldots , i_k$
. Set
where the sum runs over all
$(i, i_2, \ldots , i_k)$
such that
$i_2, \ldots , i_k \neq i$
and
$i$
is the minimum element in
$i, i_2, \ldots , i_k$
, which appears only one time in
$i, i_2, \ldots , i_k$
. Then we have
Since elements
$x_i x_{i_2} \cdots x_{i_k}$
are linearly independent in
$\overline {\mathcal{C}}_n(k)$
, we obtain
$a_{i, i_2, \ldots , i_k}=0$
for all
$(i, i_2, \ldots , i_k)$
. This completes the proof of Theorem 8.5.
9. The Andreadakis conjecture for
$\mathcal{P}_n(4)$
In this section, as an application of Proposition 7.4, we show that
$\mathcal{P}_n(4)=\mathrm{P}\Sigma _n(4)$
. First, we give the strategy to show it, which is the same way as the proof of
$\mathcal{P}_n(3)=\mathrm{P}\Sigma _n(3)$
given in [Reference Satoh35]. Since the natural map
is surjective, and
$\mathrm{P}\Sigma _n(4) \subset \mathcal{P}_n(4)$
, if the injectivity of
$\nu$
is proved then
$\nu$
is an isomorphism, and hence we obtain
$\mathrm{P}\Sigma _n(4) = \mathcal{P}_n(4)$
. Since
$\mathrm{gr}^3(\mathcal{P}_n)$
is a free abelian group of rank
$n(n-1)^2(n+1)/3$
, see the table at the end of Section 7, if we show that
then there exists a section
$\mathrm{gr}^3(\mathcal{P}_n) \rightarrow \mathrm{P}\Sigma _n(3)/\mathrm{P}\Sigma _n(4)$
which is the inverse of
$\nu$
, and hence
$\nu$
is injective. Thus, we show the following.
Theorem 9.1.
$\mathrm{P}\Sigma _n(3)/\mathrm{P}\Sigma _n(4)$
is generated by
-
(E1) :
$[K_{ij}, K_{il}, K_{im}]$
for any distinct
$1 \leq i, j, l, m \leq n$
such that
$j\gt l\lt m$
, -
(E2) :
$[K_{ij}, K_{il}, K_{ij}]$
for any distinct
$1 \leq i, j, l \leq n$
, -
(E3) :
$[K_{ij}, K_{il}, K_{ji}]$
for any distinct
$1 \leq i, j, l \leq n$
such that not
$i\gt j, k$
, -
(E4) :
$[K_{ij}, K_{ji}, K_{ij}]$
for any distinct
$1 \leq i, j \leq n$
as a
$\mathbf{Z}$
-module. The number of the above elements is
$n(n-1)^2(n+1)/3$
.
Proof.
First, we count the number of the elements. The number of elements of (E1) and (E2) is equal to the total number of choices of
$i \in \{ 1, \ldots , n\}$
times the total number of choices of
$j, l, m \in \{ 1 \ldots,{} i-1, i+1, \ldots , n\}$
such that
$j\gt l \leq m$
. It is
$n \times 2 \binom {(n-1)+1}{3}$
. The number of elements of (E3) is
$\binom {n}{3} \times 4$
. The number of elements of (E4) is
$n(n-1)$
. Thus, the total number of the elements is equal to
$n(n-1)^2{}(n+1)/3$
.
From (5), we see that
$\mathrm{P}\Sigma _n(2)/\mathrm{P}\Sigma _n(3)=\mathrm{gr}^2(\mathcal{P}_n)$
is generated by
Hence,
$\mathrm{P}\Sigma _n(3)/\mathrm{P}\Sigma _n(4)$
is generated by
\begin{align*} \begin{cases} [K_{ij}, K_{il}, K_{pq}] \hspace {1em} & i \neq l\lt j \neq i, \\ [K_{ij}, K_{ji}, K_{pq}] & i \neq j \end{cases} \end{align*}
for any
$p \neq q$
. We reduce these generators.
(I) The generators type of
$X\,:\!=[K_{ij}, K_{il}, K_{pq}]$
.
Set
$N\,:\!=\sharp \{ i, j, l, p, q \}$
. If
$N=5$
, then
$X=0$
since as an automorphism of
$F_n$
,
$[K_{ij}, K_{il}, K_{pq}]=1$
in
$\mathrm{Aut}\,F_n$
. Consider the case where
$N=4$
. In this case,
$p \in \{ i, j, l \}$
or
$q \in \{i, j, l \}$
. If
$p=i$
and
$l\lt q$
, then
$X$
is of type (E1). If
$p=i$
and
$l\gt q$
, by using the Jacobi identity, we see
If
$p=j$
, by the Jacobi idenity and
$[K_{ij}, K_{jq}]=-[K_{ij}, K_{iq}]$
from the relation (P3), we have
This is the same case as
$p=i$
. Hence, in each of the above cases,
$X$
can be written as a sum of elements type of (E1). So, we can remove
$X$
from the generating set in this case. Similarly, we can reduce the generators in other cases. For simplicity, we give a list as follows.


Here (E3)’ means
We show that any element type of (E3)’ can be written as that of (E3) later.
(II) The generators type of
$Y\,:\!=[K_{ij}, K_{ji}, K_{pq}]$
.
Set
$N'\,:\!=\sharp \{ i, j, p, q \}$
. By arguments similar to those in (I), we have the following.

Finally, we consider (E3)’. For any distinct
$1 \leq i, j, l \leq n$
, we have

where
$\stackrel {\text{J}}{=}$
and
$\stackrel {\textbf {(P3)}}{=}$
mean the equlities induced from the Jacobi identity and the relation (P3), respectively. Hence for any
$1 \leq l\lt j\lt i \leq n$
, we can remove
$[K_{ij}, K_{il}, K_{ji}]$
and
$[K_{il}, K_{ij}, K_{li}]$
from the generating set.
Therefore, we obtain the required result. This completes the proof of Theorem 9.1.
Hence, we obtain the following.
Corollary 9.2.
For
$n \geq 3$
, we have
$\mathcal{P}_n(4)=\mathrm{P}\Sigma _n(4)$
.
10. Remarks on
$H_2(\mathrm{P}\Sigma _n, \mathbf{Z})$
In this section, as applications of our results above, we give some remarks on the second homology and the second cohomology groups of
$\mathrm{P}\Sigma _n$
. All of the results in this subsection were alreday obtained by Brownstein and Lee [Reference Brownstein and Lee8], and Jensen, McCammond and Meiyer [Reference Jensen, McCammond and Meier21]. The method is the same as that in the study of the integral second homology group of the lower-triangular IA-automorphism group of
$F_n$
in [Reference Satoh31].
We prepare some notation. Let
$F$
be the free group of rank
$n(n-1)$
with a basis
$K_{ij}$
for all
$1 \leq i \neq j \leq n$
. Let
$\pi\,:\,F \rightarrow \mathrm{P}\Sigma _n$
be the standard surjective homomorphism, and set
$R\,:\!=\mathrm{Ker}(\pi )$
. Then we have the group extension
From Theorem 5.1, since the abelianization of
$\mathrm{P}\Sigma _n$
is a free abelian group generated by (the coset classes of) all
$K_{ij}$
s, we see that
$\pi$
induces an isomorphism
From the homological five-term exact sequence of (14), we have
and hence
Let
$F=\Gamma _F(1) \supset \Gamma _F(2) \supset \cdots$
be the lower central series of
$F$
, and set
$\mathcal{L}_F(k) \,:\!= \Gamma _F(k)/\Gamma _F(k+1)$
for each
$k \geq 1$
. Let
$\{ R_k \}_{k \geq 1}$
be the descending filtration of
$R$
defined by
$R_k \,:\!= R \cap \Gamma _F(k)$
for each
$k \geq 1$
. We have
$R_k=R$
for
$k=1$
and
$2$
since
$R \subset [F,F]$
. For each
$k \geq 1$
, let
$\pi _k\,:\,\mathcal{L}_F(k) \rightarrow \mathrm{P}\Sigma _n(k)/\mathrm{P}\Sigma _n(k+1)$
be the homomorphism induced from
$\pi\,:\,F \rightarrow \mathrm{P}\Sigma _n$
. By observing
$R_k/R_{k+1} \cong (R_k \, \Gamma _F(k+1))/\Gamma _F(k+1)$
, we obtain an exact sequence
For each
$k \geq 2$
. The natural projection
$R \rightarrow R/R_{k+1}$
induces the surjective homomorphism
$\psi _k\,:\,H_1(R,\mathbf{Z}) \rightarrow H_1(R/R_{k+1},\mathbf{Z})$
. By considering the right action of
$F$
on
$R$
, defined by
we see that
$\psi _k$
is
$F$
-equivariant. Hence, it induces the surjective homomorphism
which is also denoted by
$\psi _k$
. For
$k=2$
,
$H_1(R/R_{3},\mathbf{Z})_{F} = R/R_{3}$
since
$F$
acts on
$R/R_{3}$
trivially.
Proposition 10.1.
For
$n \geq 3$
,
$H_2(\mathrm{P}\Sigma _n,\mathbf{Z}) \cong \mathbf{Z}^{\frac {1}{2}n^2(n-1)(n-2)}$
.
Proof.
Observe that
$\mathrm{P}\Sigma _n(2)/\mathrm{P}\Sigma _n(3)=\mathrm{gr}^2(\mathcal{P}_n)$
is a free abelian group of rank
$n(n-1)^2/2$
as mentioned above. (See the table at the end of Section 7.) By considering (15) for
$k=2$
, we see
\begin{align*} \begin{split} \mathrm{rank}_{\mathbf{Z}}(R/R_{3}) & = \mathrm{rank}_{\mathbf{Z}}(\mathcal{L}_F(2)) - \mathrm{rank}_{\mathbf{Z}}(\mathrm{gr}^2(\mathcal{P}_n)) \\ & = \frac {1}{2}n(n-1)(n(n-1)-1) - \frac {1}{2}n(n-1)^2 \\ & = \frac {1}{2}n^2(n-1)(n-2). \end{split} \end{align*}
This means
$H_2(\mathrm{P}\Sigma _n,\mathbf{Z})$
contains a free abelian group of rank
$n^2(n-1)(n-2)/2$
. On the other hand,
$H_1(R,\mathbf{Z})_F \cong R/[F,R]$
is generated by (P1), (P2) and (P3) as a
$\mathbf{Z}$
-module. Since the total number of elements of (P1), (P2) and (P3) is
$n^2(n-1)(n-2)/2$
, we see that
$\psi _2\,:\,R/[F,R] = H_1(R,\mathbf{Z})_F \rightarrow H_1(R/R_3,\mathbf{Z})_{F}=R/R_3$
is an isomorphism, and obtain the required result.
By the universal coefficient theorem, we have
Proposition 10.2.
For
$n \geq 3$
, the cup product map
$\cup\,:\,\wedge ^2 H^1(\mathrm{P}\Sigma _n, \mathbf{Z}) \rightarrow H^2(\mathrm{P}\Sigma _n, \mathbf{Z})$
is surjective.
Proof.
By observing the cohomological five-term exact sequence of (14), we can see that
$H^2(\mathrm{P}\Sigma _n,\mathbf{Z}) \cong H^1(R,\mathbf{Z})^F=H^1(R/[F,R],\mathbf{Z})$
. From the argument in the proof of Proposition 10.1, since the natural map
$R/[F,R] \rightarrow R/R_3$
is an isomorphism,
$H^2(\mathrm{P}\Sigma _n,\mathbf{Z}) \cong H^1(R/R_3,\mathbf{Z})$
. Since
$H^1(R/R_3,\mathbf{Z})$
coincides with the image of the cup product map, we obtain the required result. (For details, see Lemma 4.1 in [Reference Satoh32].)
11. Twisted first cohomology groups of
$\mathrm{BP}_n$
From the group extension
the symmetric group
$\mathfrak{S}_n$
acts on the integral homology groups
$H_p(\mathrm{P}\Sigma _n, \mathbf{Z})$
for
$p \geq 1$
. We consider
$H_p(\mathrm{P}\Sigma _n, \mathbf{Z})$
as a
$\mathrm{BP}_n$
-module through the homomorphism
$\mathrm{BP}_n \rightarrow \mathfrak{S}_n$
.
Note that
$\mathfrak{p}_n^{\mathbf{Q}}(1)\cong H_{\mathbf{Q}} \otimes \mathcal{L}_n^{\mathbf{Q}}(1) \cong ((n) \oplus (n-1,1)) \otimes (n-1,1)$
as an
$\mathfrak{S}_n$
-module. We can decompose the tensor product representation
$(n-1,1) \otimes (n-1,1) \cong (n) \oplus (n-1,1) \oplus (n-2,2) \oplus (n-2,1^2)$
. (See the example in [[Reference Tokuyama38],1.8].) Therefore, as an
$\mathfrak{S}_n$
-equivariant
$\mathbf{Q}$
-vector space, we have
for
$n \geq 4$
. In this section, we consider the first cohomology groups of
$\mathrm{BP}_n$
with coefficients in
$(n)$
and
$(n-1,1)$
.
First, the irreducible
$\mathfrak{S}_n$
-module
$(n)$
. This is isomorphic to the trivial module
$\mathbf{Q}$
. From Theorem 5.2 by Fenn-Rimányi-Rourke, we see
The free part is generated by (the coset class of)
$\sigma _1$
, and the torsion part is generated by (the coset class of)
$s_1$
. Thus, by the universal coefficient theorem, we obtain
$H^1(\mathrm{BP}_n, \mathbf{Z}) \cong \mathbf{Z}$
, and
$H^1(\mathrm{BP}_n, \mathbf{Q}) \cong \mathbf{Q}$
.
Next, we consider the standard
$\mathfrak{S}_n$
-representation
$(n-1,1)$
. Recall the standard
$\mathrm{GL}(n,\mathbf{Z})$
-representation
$H$
. Let
$\boldsymbol{e}_1, \ldots , \boldsymbol{e}_n \in H$
be the standard basis of
$H$
. For any element
$x=x_1\boldsymbol{e}_1 + \cdots + x_n \boldsymbol{e}_n \in H$
, we write
$x=(x_1, \ldots , x_n)$
for simplicity. As an
$\mathfrak{S}_n$
-representation, the module
$H$
is decomposed into the direct sum of the two irreducible representations
The representation
$W$
is the trivial representation, and
$V \otimes _{\mathbf{Z}} \mathbf{Q} \cong (n-1,1)$
. We compute the first cohomology group of
$\mathrm{BP}_n$
with coefficients in
$V$
. Here we consider
$\boldsymbol{e}_1-\boldsymbol{e}_n, \ldots , \boldsymbol{e}_{n-1}-\boldsymbol{e}_n$
as a basis of
$V$
, and write any element
$v=v_1(\boldsymbol{e}_1-\boldsymbol{e}_n) + \cdots + v_{n-1}(\boldsymbol{e}_{n-1}-\boldsymbol{e}_n) \in V$
as
$v=(v_1, \ldots , v_{n-1})$
for simplicity.
Here we give the outline of the computation. Let
$Z^1(\mathrm{BP}_n, V)$
be the
$\mathbf{Z}$
-module of all crossed homomorphisms from
$\mathrm{BP}_n$
to
$V$
, and
$B^1(\mathrm{BP}_n, V)$
be the
$\mathbf{Z}$
-module of all principal crossed homomorphisms from
$\mathrm{BP}_n$
to
$V$
. Then we have
$H^1(\mathrm{BP}_n, V) \cong Z^1(\mathrm{BP}_n, V)/B^1(\mathrm{BP}_n, V)$
. We compute
$Z^1(\mathrm{BP}_n, V)$
by using the presentation of
$\mathrm{BP}_n$
in Theorem 5.2. Let
$F$
be the free group with a basis
$\sigma _i$
and
$s_i$
for
$1 \leq i \leq n-1$
, and
$\varphi\,:\,F \rightarrow \mathrm{BP}_n$
the standard projection. Then the kernel
$R$
of
$\varphi$
is the normal closure of all of the relators coming from the relations in Theorem 5.2. Considering the five-term exact sequence of the Lyndon–Hochshild–Serre spectral sequence of the group extension
we obtain the exact sequence
By observing this sequence at the cocycle level, we also obtain the exact sequence
where
$\iota ^*$
is the map induced from the inclusion
$\iota\,:\,R \hookrightarrow F$
. Thus, we consider
$Z^1(\mathrm{BP}_n,V)$
as a subgroup of
$Z^1(F,V)$
which are killed by
$\iota ^*$
. In other words,
$Z^1(\mathrm{BP}_n,V)$
consists of all elements of
$Z^1(F,V)$
which preserve all of the relations in Theorem 5.2. By the universality of the free group
$F$
, it is easily seen that a crossed homomorphism
$f\,:\, F \rightarrow V$
is uniquely determined by the images of the basis
$\sigma _i$
and
$s_i$
for
$1 \leq i \leq n-1$
, and hence
$Z^1(F,V)$
is isomorphic to
$V^{\oplus 2(n-1)}$
.
Theorem 11.1.
For
$n \geq 3$
,
$H^1(\mathrm{BP}_n, V) \cong \mathbf{Z}^{\oplus 2} \oplus \mathbf{Z}/4\mathbf{Z}$
.
Proof.
First, we determine
$B^1(\mathrm{BP}_n,V)$
. For any
$v=(v_1, \ldots , v_{n-1}) \in V$
, consider the principal crossed homomorphism
$f_v\,:\,\mathrm{BP}_n \rightarrow V$
associated to
$v$
. The images of
$\sigma _i$
and
$s_i$
for
$1 \leq i \leq n-1$
by
$f_v$
are given as follows.
\begin{align*} \begin{split} f_v(\sigma _i) & = \begin{cases} (0, \ldots , 0, v_{i+1}-v_i, v_i-v_{i+1}, 0, \ldots , 0) \hspace {1em} & i \neq n-1, \\ (0, \ldots , 0, -(v_1+ \cdots + v_{n-2} + 2v_{n-1})) & i=n-1, \end{cases} \\ f_v(s_i) & = f_v(\sigma _i). \end{split} \end{align*}
Here
$v_{i+1}-v_i$
and
$v_i-v_{i+1}$
are in the
$i$
-th and the
$(i+1)$
-st component of
$f_v$
.
Next, we consider
$Z^1(\mathrm{BP}_n,V)$
. Let
$f\,:\,F \rightarrow V$
be a crossed homomorphism such that
for any
$1 \leq i \leq n-1$
. It suffices to find a condition among
$a_j(i)$
s and
$b_j(i)$
s such that
$f$
preserves all relations in Theorem 5.2.
(B1): From the relation (B1) for any
$1 \leq i \leq n-2$
, we have
$f(\sigma _i \sigma _{i+1} \sigma _i) = f(\sigma _{i+1} \sigma _{i} \sigma _{i+1})$
. It is equivalent to
For
$i \leq n-3$
, we have
\begin{align*} \begin{split} (\text{LHS})&=(a_1(i), \ldots , a_{i-1}(i), a_{i+2}(i), a_{i+1}(i)-a_{i+2}(i)+a_i(i), a_{i+2}(i), \ldots , a_{n-1}(i)), \\ (\text{RHS})&=(a_1(i+1), \ldots , a_{i-1}(i+1), a_i(i+1), a_{i+1}(i+1)-a_{i}(i+1)+a_{i+2}(i+1), a_i(i+1), \\ & \hspace {3em} a_{i+3}(i+1), \ldots , a_{n-1}(i+1)), \end{split} \end{align*}
and hence,
Similarly, for
$i=n-2$
, we obtain
where
$|a(i)|=a_1(i)+ \cdots + a_{n-1}(i)$
for any
$1 \leq i \leq n-2$
. Similarly, we obtain the following equations.
(B2): We have
For any
$i\lt j \leq n-2$
,
For any
$i\lt j=n-1$
,
Here we sum up the above equations. From (17) and (20),
for any
$1 \leq i \leq n-2$
, and from (17)
for any
$3 \leq i \leq n-1$
. Moreover, from (18),
This shows that all
$a_i(j)$
s except for
$j =i, i-1$
are equal. Denote it by
$\alpha$
. From (25),
$|a(i)|=-\alpha$
for
$1 \leq i \leq n-3$
. From (19), we see
for any
$1 \leq i \leq n-2$
. Thus, we see that
$f(\sigma _i)$
for any
$1 \leq i \leq n-1$
is determined by
and that there is no extra relations among them from the above equations.
By the same argument as above, from (SY2) and (SY3), if we set
$\beta \,:\!=b_1(2)$
then we see that
$\beta = b_i(j)$
for
$j \leq i-2$
or
$i+1 \leq j$
,
$b_i(i)+b_{i+1}(i) = -(n-2) \beta$
for any
$1 \leq i \leq n-2$
, and hence
$f(s_i)$
for any
$1 \leq i \leq n-1$
is determined by
Consider (SY1). For
$1 \leq i \leq n-2$
, we obtain
$2b_j(i)=0$
for
$j \leq i-2$
and
$b_i(i)+b_{i+1}(i)=0$
for
$1 \leq i \leq n-2$
. For
$i=n-1$
, we obtain
$b_j(n-1)=0$
for
$1 \leq j \leq n-2$
. These conditions are equivalent to
$\beta =0$
.
Consider (BP1). For any
$i\lt j \leq n-2$
,
For any
$i\lt j=n-1$
,
From these equations, we does not obtain a new condition among
$a_i(j)$
s and
$b_i(j)$
s.
Consider (BP2). For any
$i \leq n-3$
,
For the case of
$i=n-2$
,
Thus, we obtain a new condition from (27) and (28) which is equivalent to
for
$1 \leq i \leq n-2$
. From (BP3), we does not obtain a new condition among
$a_i(j)$
s and
$b_i(j)$
s.
Therefore, we conclude that the homomorphism
$\rho\,:\,Z^1(\mathrm{BP}_n,V) \rightarrow \mathbf{Z}^{\oplus n+1}$
defined by
$f \mapsto (\alpha , a_1(1), \ldots , a_{n-1}(n-1), b_1(1))$
is an isomorphism. By combining the result for
$B^1(\mathrm{BP}_n,V)$
, in order to compute
$H^1(\mathrm{BP}_n,V)$
through
$\rho$
, it suffices to calculate the elementary divisors of the matrix

From this, we obtain the required result.
We remark that if we consider the braid group
$B_n$
and the symmetric group
${\mathfrak{S}}_n$
as subgroups of
${\mathrm{BP}}_n$
, then by the same argument as the proof of Theorem 11.1, we obtain the following results.
Corollary 11.2.
For
$n \geq 3$
, we have
Acknowledgments
The author would like to express their sincere gratitude to the referee and the editor for the careful reading and helpful comments for the original version of the article.
Also, the authors would like to express their sincere gratitude to Professor Yusuke Kuno for valuable comments for Lie algebras of tangential and special derivations of the free Lie algebras and Professor Toshiyuki Akita for valuable comments for the cohomology rings of the McCool groups. We also would like to express their sincere gratitude to Professor Jaques Darné for valuable comments for the McCool groups in private communications.
The first author was supported by JSPS KAKENHI Grant Number 18K03204. The second author was supported by JSPS KAKENHI Grant Number 22K03299.




