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Return-time $L^q$-spectrum for equilibrium states with potentials of summable variation

Published online by Cambridge University Press:  06 June 2022

M. ABADI
Affiliation:
Instituto de Matemática e Estatística, Universidade de São Paulo, São Paulo, Brasil (e-mail: leugim@ime.usp.br)
V. AMORIM
Affiliation:
Instituto Federal de São Paulo, São Paulo, Brasil (e-mail: vitoramorim@usp.br)
J.-R. CHAZOTTES*
Affiliation:
CPHT, CNRS, IP Paris, Palaiseau, France
S. GALLO
Affiliation:
Departamento de Estatística, Universidade Federal de São Carlos, São Carlos, Brasil (e-mail: sandro.gallo@ufscar.br)
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Abstract

Let $(X_k)_{k\geq 0}$ be a stationary and ergodic process with joint distribution $\mu $, where the random variables $X_k$ take values in a finite set $\mathcal {A}$. Let $R_n$ be the first time this process repeats its first n symbols of output. It is well known that $({1}/{n})\log R_n$ converges almost surely to the entropy of the process. Refined properties of $R_n$ (large deviations, multifractality, etc) are encoded in the return-time $L^q$-spectrum defined as

provided the limit exists. We consider the case where $(X_k)_{k\geq 0}$ is distributed according to the equilibrium state of a potential with summable variation, and we prove that

where $P((1-q)\varphi )$ is the topological pressure of $(1-q)\varphi $, the supremum is taken over all shift-invariant measures, and $q_\varphi ^*$ is the unique solution of $P((1-q)\varphi ) =\sup _\eta \int \varphi \,d\eta $. Unexpectedly, this spectrum does not coincide with the $L^q$-spectrum of $\mu _\varphi $, which is $P((1-q)\varphi )$, and it does not coincide with the waiting-time $L^q$-spectrum in general. In fact, the return-time $L^q$-spectrum coincides with the waiting-time $L^q$-spectrum if and only if the equilibrium state of $\varphi $ is the measure of maximal entropy. As a by-product, we also improve the large deviation asymptotics of $({1}/{n})\log R_n$.

Information

Type
Original Article
Copyright
© The Author(s), 2022. Published by Cambridge University Press
Figure 0

Figure 1 Illustration of Theorem 3.1. Plot of when $\mu =m^{\mathbb {N}}$ (product measure) with m being the Bernoulli distribution (that is, $\mathcal A=\{0,1\}$) with parameter $p= 1/3$. This corresponds to a potential $\varphi $ which is locally constant on the cylinders $[0]$ and $[1]$, and therefore it obviously fulfils the conditions of the theorem. See Subsection 3.4). For a general potential of summable variation which is not of the form $u-u\circ \theta -\log |\mathcal {A}|$, the above graphs have the same shapes.