1 Introduction
Let
$x_{1},\ldots ,x_{N}$
be numbers in the unit interval. The distribution of the pair correlations of these numbers is described by the function
where
$\Vert \cdot \Vert$
denotes the distance to the nearest integer. If for an infinite sequence
$(x_{n})_{n}$
we have
for all
$s\geqslant 0$
, then we say that the distribution of pair correlations is (asymptotically) Poissonian. Note that a sequence of independent, identically distributed (i.i.d.) random points, picked from a uniform distribution on
$[0,1]$
, almost surely has Poissonian pair correlations. The term “Poissonian” comes from a similarity with the distribution of the spacings between points in a Poisson process, which, however, only becomes really meaningful when also considering higher correlations (triple, quadruple, etc.) or so-called level spacings (which are in general much more difficult to handle than pair correlations).
The interest in such problems goes back to a paper by Berry and Tabor [Reference Berry and Tabor3], where they gave a conjectural framework for the distribution of energy spectra of integrable quantum systems (see [Reference Marklof11] for a survey). Their model led to strong mathematical interest in distributional properties of spacing of sequences such as
$(n\unicode[STIX]{x1D6FC})_{n}$
mod 1 (corresponding to the “harmonic oscillator”) and
$(n^{2}\unicode[STIX]{x1D6FC})_{n}$
mod 1 (corresponding to the “boxed oscillator”). The case of
$(n\unicode[STIX]{x1D6FC})_{n}$
is easier to analyse; one can use considerations based on continued fractions to show that the pair correlations of this sequence cannot be Poissonian for any
$\unicode[STIX]{x1D6FC}$
, since for some
$N$
the initial segment
$(\unicode[STIX]{x1D6FC},2\unicode[STIX]{x1D6FC},\ldots ,N\unicode[STIX]{x1D6FC})$
mod 1 is too regularly spaced. The case of
$(n^{2}\unicode[STIX]{x1D6FC})_{n}$
is much harder and is far from being well understood. It is conjectured that the pair correlations for this sequence should be Poissonian, unless
$\unicode[STIX]{x1D6FC}$
is very well approximable by rationals; however, there exist only some partial results in this direction (see, for example, [Reference Heath-Brown9, Reference Rudnick, Sarnak and Zaharescu13, Reference Truelsen15]). From the metric perspective, the situation is easier: it is known that the pair correlations of
$(n^{2}\unicode[STIX]{x1D6FC})_{n}$
mod 1 are Poissonian for almost all
$\unicode[STIX]{x1D6FC}$
, in the sense of Lebesgue measure. The same is true if
$(n^{2})_{n}$
is replaced by
$(n^{d})_{n}$
for some integer
$d\geqslant 3$
, or by an exponentially growing sequence
$(a_{n})_{n}$
of integers; see [Reference Rudnick and Sarnak12, Reference Rudnick and Zaharescu14]. We denote this property by saying that these sequences have the metric pair correlation property. In a recent paper [Reference Aistleitner, Larcher and Lewko2], a connection was established between the question whether a sequence has the metric pair correlation property, and the asymptotic order of its so-called additive energy. Let
$(a_{n})_{n}$
be a sequence of distinct positive integers, let
$A_{N}$
denote its initial segment
$a_{1},\ldots ,a_{N}$
, and denote by
$E(A_{N})$
the additive energy of
$A_{N}$
, which is defined as
Trivially, the additive energy is always between
$N^{2}$
and
$N^{3}$
. Throughout this paper we will use the formulation “the order of the additive energy of a sequence”, when more precisely speaking we mean the order (as a function of
$N$
) of the additive energy of the
$N$
first elements of the sequence.
The main results of [Reference Aistleitner, Larcher and Lewko2] say that a sequence has the metric pair correlation property if its additive energy is of order at most
$N^{3-\unicode[STIX]{x1D700}}$
for some
$\unicode[STIX]{x1D700}>0$
, while it does not have the metric pair correlation property if the additive energy exceeds
$cN^{3}$
for infinitely many
$N$
for some constant
$c>0$
. This fits together very well with the examples from above, since sequences of the form
$(n^{d})_{n}$
for
$d\geqslant 2$
and lacunary sequences are known to have very small additive energy, while the additive energy of the sequence
$a_{n}=n,n\geqslant 1,$
is of the maximal possible order.
So the general philosophy is that a sequence has the metric pair correlation property as soon as its additive energy is slightly below the maximal possible order. However, a precise threshold is not known. Some results in this direction are as follows.
∙ The primes do not have the metric pair correlation property, as shown by Walker [Reference Walker16]. The additive energy of the sequence of primes is roughly of order
$N^{3}/(\log N)$
.∙ There exists a sequence having additive energy of order
$N^{3}/(\log N\log \log N)$
which does not have the metric pair correlation property [Reference Lachmann and Technau10].∙ For every
$\unicode[STIX]{x1D700}>0$
there exists a sequence having additive energy of order
$N^{3}/(\log N(\log \log N)^{1+\unicode[STIX]{x1D700}})$
which has the metric pair correlation property (unpublished, but not difficult to construct using methods from [Reference Bloom, Chow, Gafni and Walker4, Reference Lachmann and Technau10]).
These results indicate that there is a sort of transitional behaviour when the additive energy lies around the “critical” order of roughly
$N^{3}/(\log N\log \log N)$
. The methods used in [Reference Bloom, Chow, Gafni and Walker4, Reference Lachmann and Technau10] indicate a close connection between this sort of question and problems from metric Diophantine approximation, where the classical theorem of Khintchine gives a zero–one law in terms of the convergence/divergence of the series of measures of the target intervals (see, for example, [Reference Harman8]). It is tempting to speculate that a similar convergence/divergence criterion might also exist for the metric theory of pair correlations, where the crucial quantity is the additive energy of
$(a_{n})_{n}$
. This idea was discussed in a recent paper of Bloom et al [Reference Bloom, Chow, Gafni and Walker4], where they noted that there “appears to be reasonable evidence to speculate a sharp Khintchine-type threshold, that is, to speculate that the metric Poissonian property should be completely determined by whether or not a certain sum of additive energies is convergent or divergent”. They raise the following problem, which they call the “fundamental question”:
Is it true that if
$E(A_{N})\sim N^{3}\unicode[STIX]{x1D713}(N)$
, for some weakly decreasing function
$\unicode[STIX]{x1D713}:\mathbb{Z}_{{\geqslant}1}\rightarrow [0,1]$
, then
$(a_{n})_{n}$
is metric Poissonian if and only if
converges?
In the present paper, we show that the answer to the question above is negative, and that the metric pair correlation property cannot be fully characterized in terms of the additive energy alone. For this purpose, we construct a sequence
$(a_{n})_{n}$
whose additive energy is of order roughly
$N^{3}/(\log N)^{3/4}$
, and which does have the metric pair correlation property. More precisely, we prove the following theorem.
Theorem 1. For every
$\unicode[STIX]{x1D700}>0$
there exists a strictly increasing sequence
$(a_{n})_{n}$
of positive integers which has the metric pair correlation property, and whose additive energy satisfies
Note that the additive energy of the sequence from the conclusion of Theorem 1 is significantly larger than the putative threshold, which is around
$N^{3}/(\log N)$
. Furthermore, as the examples above showed, the additive energy of a sequence which does not have the metric pair correlation property can be of asymptotic order
$N^{3}$
, but it can also be of asymptotic order roughly
$N^{3}/(\log N)$
. Thus the metric theory of pair correlations cannot simply be reduced to a convergence/divergence criterion in terms of the additive energy alone. Instead, the picture is more complicated and can be described as follows.
∙ If the additive energy is below a certain threshold, then the sequence does have the metric pair correlation property.
∙ If the additive energy is above a certain threshold (for infinitely many
$N$
), then the sequence cannot have the metric pair correlation property. (This threshold is different from the one in the point above.)∙ Between these upper and lower thresholds there is a transition zone, where knowing the additive energy alone is not sufficient to determine the metric pair correlation behaviour of the sequence. Thus, in this range the metric pair correlation property is determined by some additional arithmetic properties of the sequence.
We note that while our result says that the metric pair correlation property cannot be characterized in terms of the additive energy alone, it leaves the problem of finding some other way of characterizing the metric pair correlation property in terms of some arithmetic properties of
$(a_{n})_{n}$
. It is likely that there is a zero–one law in the metric theory of pair correlations, but actually even this is not known. Also, our result still leaves questions concerning the quantitative connection between additive energy and the metric theory of pair correlations. For example, is it possible that a sequence having additive energy of order
$N^{3}/(\log \log N)$
also has the metric pair correlation property? In the other direction, is it possible that the additive energy is of order
$N^{3}/(\log N)^{2}$
and the sequence does not have the metric pair correlation property?Footnote
1
Closing the gaps in our knowledge in this field would be very desirable, as phenomena from both additive combinatorics and Diophantine approximation seem to be at work here.
2 Preliminaries
2.1 Construction of the sequence
We will construct our sequence
$(a_{n})_{n}$
as the concatenation of successive “blocks”. All these blocks are either finite arithmetic or finite geometric progressions. The geometric blocks will contain the majority of the numbers which constitute the final sequence, but they will not be responsible for making the additive energy of the final sequence large, since geometric progressions always have small additive energy. The contribution of the geometric blocks to the distribution of pair correlations will be “random”, in accordance with the well-known heuristic that lacunary systems exhibit properties which are also shown by independent random systems (see, for example, [Reference Rudnick and Zaharescu14] for this phenomenon in connection with pair correlations, and [Reference Aistleitner1] for the wider context). In our context “random” behaviour means Poissonian behaviour of the pair correlations, so the geometric blocks are responsible for the final sequence being metric Poissonian. The arithmetic blocks contain only a minority of all the elements of the final sequence, while being responsible for making the additive energy large. The main task will be to show that while these arithmetic blocks boost the additive energy, their contribution to the distribution of pair correlations is asymptotically negligible. To control the contribution of arithmetic blocks we will use tools from metric Diophantine approximation.
The key point of the construction lies in the fact that the arithmetic blocks which are used in the construction have different prime numbers as their step sizesFootnote 2 . The fact that the step sizes of the arithmetic blocks are prime numbers will play a key role in two parts of the proof. On the one hand, using the theory of continued fractions at some point we will be led to counting the number of solutions of a certain equation; the assumption that the step size is a (large) prime will imply that we only have to count solutions which are a multiple of that prime, thus effectively reducing the number of solutions. This will allow us to control the contribution which comes from elements contained within one and the same arithmetic block. On the other hand, to control the contribution of the interaction of elements from two different arithmetic blocks, we will use a variance estimate which boils down to counting the maximal number of solutions of a simple Diophantine equation. Again, the fact that the moduli are (different) primes will reduce the maximal number of solutions of the equation. We will add some further comments on the heuristic reasoning behind the proof after first formulating precisely the way in which our sequence is constructed.
Notation
We fix some
$\unicode[STIX]{x1D700}>0$
. Throughout the rest of this paper we assume without loss of generality that
$\unicode[STIX]{x1D700}$
is “small”, say
$\unicode[STIX]{x1D700}<1/100$
. We will use Landau notation
$o,{\mathcal{O}}$
, and Vinogradov symbols
$\ll ,\gg$
, with their usual meaning in analytic number theory (i.e.
$f\ll g$
meaning that
$|f|$
is bounded by a constant times
$|g|$
, for all possible arguments). The symbol
$f\asymp g$
means that
$f\ll g$
as well as
$f\gg g$
. If the implied constant depends on some parameter, we will indicate the dependence by a corresponding subscript. However, we will not indicate any dependence on
$\unicode[STIX]{x1D700}$
, since throughout the proof
$\unicode[STIX]{x1D700}$
is assumed to be fixed. We write
$\unicode[STIX]{x1D706}$
for the Lebesgue measure on
$\mathbb{R}$
. Finally, we write
$\lfloor \cdot \rfloor$
for the integer part of a real number.
In Lemma 1 below we construct the moduli of the arithmetic blocks.
Lemma 1. There exist an index
$j_{0}\geqslant 1$
and a sequence
$(m_{j})_{j\geqslant j_{0}}$
of primes such that
and such that
$m_{j}\neq m_{i}$
whenever
$j-3\log j<i<j$
, for all
$i,j\geqslant j_{0}$
.
Before proving the lemma, we briefly explain its meaning. The numbers
$m_{j}$
will be the moduli of the arithmetic progressions in our construction. The first condition in the lemma says that these moduli are of asymptotic order roughly
$j^{1/4}$
. The second condition guarantees that the step size of the
$j$
th arithmetic progression is different from the step size of the
$i$
th arithmetic progression, whenever
$i$
is “close” to
$j$
. So arithmetic blocks whose indices are close by can never have the same step size, which will guarantee that there is no undesired interaction between such blocks (this will play a crucial role in the proof of Lemma 7 below). On the other hand, if
$i$
and
$j$
are not close to each other, then the corresponding arithmetic blocks are allowed to have the same step size—this is the “recycling process”, which was mentioned in the preceding footnote, and which is necessary since the step sizes of the blocks grow more slowly than the indices of the blocks themselves. However, this will not cause any problems since the block sizes increase very quickly and any interaction between a block and some other block of much smaller cardinality will always be negligible.
Proof of Lemma 1.
To define the value of
$m_{j}$
for all indices
$j$
in the range
$16^{d}\leqslant j<16^{d+1}$
,
$d\geqslant 0$
, we note that the number of primes in the range
is certainly at least
$d^{2}$
for all sufficiently large
$d$
, by the prime number theorem. So assume that
$d$
is “large”, and let
$p_{d,1}<\cdots <p_{d,d^{2}}$
denote the first
$d^{2}$
primes in the interval (7). We set
where
$r(j)$
is the unique remainder when reducing
$j$
mod
$d^{2}$
. Then (6) holds since
$2^{d}=(16^{d})^{1/4}\asymp j^{1/4}$
. Furthermore, it can easily be seen that the second assertion of the lemma holds as well for sufficiently large
$d$
, since (8) guarantees that
$m_{j}$
cannot equal
$m_{i}$
whenever
$|i-j|$
is small. Observe here that
$d^{2}$
is of order roughly
$(\log j)^{2}$
, and thus much larger than
$3\log j$
for all sufficiently large
$j$
and
$d$
.◻
Let
$j_{0}$
be as in Lemma 1. For
$j\geqslant j_{0}$
we recursively define sets
$P_{G}(j)$
and
$P_{A}(j)$
by setting
To make the construction well defined we need to specify the initial value
$\max P_{A}(j_{0}-1)$
, which is necessary for (9) in the case
$j=j_{0}$
; it does not matter what we choose, but let us agree that this quantity should be read as 1, and that accordingly
$P_{G}(j_{0}):=\{2+3^{j_{0}^{h}}:h=0,\ldots ,2^{j_{0}}-1\}$
.
The set
$P_{G}(j)$
is a (shifted) geometric progression for each
$j$
, while the set
$P_{A}(j)$
is a (shifted) arithmetic progression for each
$j$
. The sets
$P_{G}(j)$
and
$P_{A}(j)$
are arranged in increasing order; more precisely, we have
for all
$j\geqslant j_{0}$
, where the symbol “
${<}$
” means that every element of the set on the right-hand side exceeds every element of the set on the left-hand side.
The exponential factors
$2^{(\cdots \,)}$
which appear in the definitions of all the sets
$P_{G}$
and
$P_{A}$
are quite arbitrary; what matters is only that the smallest element of
$P_{A}(j)$
is much larger than the largest elements of
$P_{G}(j)$
, and so on. Thus the respective sets in our construction are not only ordered as shown by (11), but there actually are huge gaps separating one item in this chain of inequalities from the next.
Finally, we specify the sequence
$(a_{n})_{n}$
by defining
$a_{n}=a_{n}(\unicode[STIX]{x1D700})$
as the
$n$
th (smallest) element of
for all
$n\geqslant 1$
. So
$(a_{n})_{n}$
contains all the numbers which are contained in
$P_{G}(j)$
or
$P_{A}(j)$
for some
$j$
, sorted in increasing order. We claim that the additive energy of this sequence is as large as specified in (5), and that the pair correlations of
$(a_{n}\unicode[STIX]{x1D6FC})_{n}$
mod 1 are Poissonian for almost all
$\unicode[STIX]{x1D6FC}$
.
2.2 The heuristic behind the construction
Before turning to the proof of Theorem 1, we want to explain the heuristic behind the construction of the sequence
$(a_{n})_{n}$
. In particular, we want to show why our construction allows is to go beyond the alleged “Khintchine threshold”. Note that the distribution of the pair correlations of
$(a_{n}\unicode[STIX]{x1D6FC})_{n}$
mod 1 depends not so much on the sequence
$(a_{n})_{n}$
itself as on the set of differences
$\{a_{n}-{a_{m}\}}_{m,n}$
(as does the additive energy). Thus it is this difference set that has to be controlled.
Obviously the difference set of a finite arithmetic progression has a very special structure; it is essentially an arithmetic progression itself, and the cardinality of the difference set of an arithmetic progression is small while the additive energy is large. More precisely, the positive part of the difference set of an arithmetic progression with step size
$d$
and length
$M$
is itself an arithmetic progression with step size
$d$
and length
$M-1$
, and each of the elements of the difference sets has at least one and at most
$M-1$
representations as a difference of elements of the original set. In our construction we combine arithmetic progressions with different prime moduli
$m_{j}$
. The number of such arithmetic progressions and their respective length is so large that they boost the additive energy of the total sequence; in contrast, we have to show that their contribution to the distribution of pair correlations is asymptotically negligible. In our setting, at the
$j$
th building block we have constructed roughly
$N\approx 2^{j}$
elements of our sequence
$(a_{n})_{n}$
. Each arithmetic progression at this level consists of roughly
${\approx}N/(\log N)^{1/4+\unicode[STIX]{x1D700}/3}$
elements. One can easily check that this leads to the required lower bound for the additive energy. The size of the prime moduli
$m_{j}$
is roughly
$(\log N)^{1/4}$
.
To make sure that the contribution which one of these arithmetic progressions makes to the pair correlations is asymptotically negligible, we have to show (roughly speaking) that
for “typical”
$\unicode[STIX]{x1D6FC}$
in the sense of Lebesgue measure (where for simplicity we took
$1/N$
rather than
$s/N$
for the length of the test interval). Here the factor
$N/(\log N)^{1/4+\unicode[STIX]{x1D700}/3}$
on the very left arises as the maximal number of representations which the number
$m_{j}q$
has as a difference of two elements of the arithmetic progression with step size
$m_{j}$
, and the upper bound
$q\leqslant N/(\log N)^{1/4+\unicode[STIX]{x1D700}/3}$
which restricts the maximal size of
$q$
comes from the length of the arithmetic blocks. The estimate (12) is true as long as the cardinality of the set on the left is asymptotically negligible in comparison to
$(\log N)^{1/4+\unicode[STIX]{x1D700}/3}$
.
Essentially, the cardinality of this set only exceeds
$(\log N)^{1/4+\unicode[STIX]{x1D700}/3}$
when there is a
such that
$\Vert m_{j}q\unicode[STIX]{x1D6FC}\Vert$
is less than
$1/(N(\log N)^{1/4+\unicode[STIX]{x1D700}/3})$
, so that for the next
$(\log N)^{1/4+\unicode[STIX]{x1D700}/3}$
multiples of
$q$
we also have
$\Vert m_{j}q\unicode[STIX]{x1D6FC}\Vert \leqslant 1/N$
, and so that all these multiples are still smaller than
$N/(\log N)^{1/4+\unicode[STIX]{x1D700}}$
. Accordingly, one has to check if for typical
$\unicode[STIX]{x1D6FC}$
one should expect that there is a
$q$
such that
Writing
$N/(\log N)^{1/2+2\unicode[STIX]{x1D700}/3}=:Q$
, the inequality above essentially becomes
By Khintchine’s convergence/divergence criterion this inequality looks like it should have infinitely many solutions for “typical” alpha, since the expression on the right-hand side is not summable as a function of
$Q$
. However, one major aspect is missing. The right-hand side of (13) is so small that the solutions of this inequality can be explicitly characterized by continued fraction theory; all solutions necessarily come from best approximations to
$\unicode[STIX]{x1D6FC}$
. We will show that (for typical alpha) we may assume that the denominators of best approximations to alpha are not divisible by the prime
$m_{j}$
; thus the number
$m_{j}q$
cannot be a best approximation denominator itself. Rather, it must be the multiple of
$m_{j}$
and of a best approximation denominator, and accordingly for
$q$
itself to satisfy (13) we must have
The right-hand side of (14) is summable as a function of
$Q$
, and thus by Khintchine’s criterion we should only expect finitely many solutions for typical alpha. It turns out that this heuristic reasoning can be turned into an actual proof.
We emphasize again that the fact that
$m_{j}$
always is a prime played a crucial role in this reasoning, together with the fact that we may assume that the denominators of best approximations are not divisible by
$m_{j}$
(we will prove this fact in Lemma 2 below). Another crucial aspect is to show that two different arithmetic blocks do not “interact” in an undesired way; that is, we have to show that the difference sets of these respective progressions do not overlap too much. For this it will again be important that all the moduli are (different) primes, since then a fixed integer can only show up in the difference set of two arithmetic progressions if it is a product of the two primes which constitute the respective step sizes. This will be proved in the form of a variance bound in Lemma 7.
Finally, let us explain why it is not possible to obtain even larger additive energy with such a construction. Obviously, the additive energy is increased when the length of the arithmetic blocks is increased, so we might try to do that. Furthermore, as (14) shows, increasing the size of the prime moduli
$m_{j}$
would also improve the argument, so we might try to do that as well. So let us assume that the length of the arithmetic blocks is changed from roughly
$N/(\log N)^{1/4+\unicode[STIX]{x1D700}/3}$
to
$N/(\log N)^{\unicode[STIX]{x1D6FD}}$
for some
$\unicode[STIX]{x1D6FD}$
, and that the size of the prime moduli
$m_{j}$
is changed from roughly
$(\log N)^{1/4}$
to
$(\log N)^{\unicode[STIX]{x1D6FE}}$
for some
$\unicode[STIX]{x1D6FE}$
. If we do so, then instead of (12) we will have to show that
for “typical” alpha, with
$m_{j}$
of size roughly
$m_{j}\approx (\log N)^{\unicode[STIX]{x1D6FE}}$
. Now recall that Legendre’s theorem from continued fraction theory allows us to characterize the solutions
$(a,b)$
to
$|b\unicode[STIX]{x1D6FC}-a|<1/(2b)$
. We want to use this for
$b=m_{j}q$
, and thus in our application
$b$
might be as large as
$N(\log N)^{\unicode[STIX]{x1D6FE}-\unicode[STIX]{x1D6FD}}$
. The term
$1/N$
in (15) is preassigned, since it comes from the definition of pair correlations. So in order to apply Legendre’s theorem we have to make sure that
$N(\log N)^{\unicode[STIX]{x1D6FE}-\unicode[STIX]{x1D6FD}}\ll N$
, which implies
$\unicode[STIX]{x1D6FE}\leqslant \unicode[STIX]{x1D6FD}$
. This restricts the size of the prime moduli (in terms of the length of the arithmetic progressions). When we carry out the heuristic reasoning above with general parameters
$(\unicode[STIX]{x1D6FD},\unicode[STIX]{x1D6FE})$
instead of
$(1/4+\unicode[STIX]{x1D700}/3,1/4)$
, then instead of (14) we will arrive at
The right-hand side is summable if
$3\unicode[STIX]{x1D6FD}+\unicode[STIX]{x1D6FE}>1$
. Since the additive energy is maximized by taking
$\unicode[STIX]{x1D6FD}$
as small as possible, and since we already know that we need to take
$\unicode[STIX]{x1D6FE}\leqslant \unicode[STIX]{x1D6FD}$
, the minimal permissible value for
$\unicode[STIX]{x1D6FD}$
is restricted by the requirement
$\unicode[STIX]{x1D6FD}>1/4$
. This is the choice of parameters which is made in our construction. One can also show that our choice of parameters is optimal with respect to the conditions imposed by the variance bound in Lemma 7, which also requires that
$3\unicode[STIX]{x1D6FD}+\unicode[STIX]{x1D6FE}>1$
. Thus some significant new ideas would be necessary to further increase the additive energy while preserving the metric pair correlation property.
2.3 A useful partition, and organization of the paper
The following partitioning underpins the rest of this paper. Here we need some notation from additive combinatorics. We write
$X-Y$
for the difference set
of two sets
$X,Y\subseteq \mathbb{Z}$
. By
$\#X$
we denote the cardinality of
$X$
. Furthermore, we write
$\text{r}_{X-Y}$
for the number of ways in which
$d\in \mathbb{Z}$
can be represented as a difference of elements of
$X,Y\subseteq \mathbb{Z}$
, that is,
If no confusion can arise, we will simply write
$\text{r}\left(d\right)$
for
$\text{r}_{X-Y}\left(d\right)$
. Recall that trivially
Moreover, let
$X^{+}:=X\cap \mathbb{Z}_{{\geqslant}1}$
denote the set of positive elements of a set
$X\subseteq \mathbb{Z}$
. Since
$A_{N}-A_{N}$
is symmetric around the origin, we can confine attention to its positive part.
Assume that
$d\geqslant 0$
is the difference of two elements of
$A_{N}$
, that is,
$d=x-y$
. We will classify these differences, according to the origin of
$x$
and
$y$
. More precisely, we will distinguish between the following cases.
∙ Case (
$GG$
):
$x$
and
$y$
both come from geometric blocks, that is,
$x,y\in \bigcup _{j}P_{G}(j)$
.∙ Case (
$AG$
):
$x$
comes from an arithmetic block, and
$y$
comes from a geometric block, that is,
$x\in \bigcup _{j}P_{A}(j)$
and
$y\in \bigcup _{j}P_{G}(j)$
. Or, reciprocally,
$x$
comes from a geometric block and
$y$
comes from an arithmetic block.∙ Case (
$AA_{\text{diff}}$
):
$x$
and
$y$
come from different arithmetic blocks, that is,
$x\in P_{A}(j_{1})$
for some
$j_{1}$
and
$y\in P_{A}(j_{2})$
for some
$j_{2}$
, such that
$j_{1}\neq j_{2}$
.∙ Case (
$AA_{\text{same}}$
):
$x$
and
$y$
come from the same arithmetic block, that is,
$x,y\in P_{A}(j)$
for some
$j$
.
We write
${\mathcal{D}}_{N}(GG)$
for the set of those
$d$
in the difference set
$(A_{N}-A_{N})^{+}$
which can be represented as Case (
$GG$
). In a similar way, we define
${\mathcal{D}}_{N}(AG),{\mathcal{D}}_{N}(AA_{\text{diff}})$
, and
${\mathcal{D}}_{N}(AA_{\text{same}})$
.
The function
$R$
which was defined in (1) can be decomposed in a similar way in the form
For this decomposition, we set
$$\begin{eqnarray}\displaystyle \begin{array}{@{}c@{}}R(GG):=R(GG,\unicode[STIX]{x1D6FC},s,N):=\displaystyle \frac{2}{N}\mathop{\sum }_{d\in {\mathcal{D}}_{N}(GG)}r(d)I_{s,N}(d\unicode[STIX]{x1D6FC}),\\ I_{s,N}(x):=\left\{\begin{array}{@{}ll@{}}1\quad & \Vert x\Vert \leqslant s/N,\\ 0\quad & \text{otherwise,}\end{array}\right.\end{array} & & \displaystyle\end{eqnarray}$$
where
$r(d)$
counts only the number of Case (
$GG$
) representations which
$d\geqslant 1$
has in the form
$d=x-y$
such that
$x,y\in A_{N}$
. Note that the factor 2 in (19), which is not present in (1), comes from the fact that we restricted ourselves to the positive part of the difference set
$A_{N}-A_{N}$
. Similarly, we define
$R(AG)$
,
$R(AA_{\text{diff}})$
and
$R(AA_{\text{same}})$
, where the function
$r(d)$
is instead restricted to representations of
$d$
as Case (
$AG$
), Case (
$AA_{\text{diff}}$
) and Case (
$AA_{\text{same}}$
), respectively.
By using the same methods as in [Reference Aistleitner, Larcher and Lewko2], one can easily conclude that
as
$N\rightarrow \infty$
, for almost all
$\unicode[STIX]{x1D6FC}\in [0,1]$
and each
$s>0$
. This follows from the fact that geometric progressions have small additive energy, and the fact that the cardinality of the geometric blocks is dominant over the total cardinality of the arithmetic blocks which implies that
$1/N$
really is the correct normalization factor such that
$R(GG)$
converges as desired for
$N\rightarrow \infty$
.
Thus it remains to show that all the remaining terms
$R(AG)$
,
$R(AA_{\text{diff}})$
and
$R(AA_{\text{same}})$
vanish in the limit
$N\rightarrow \infty$
, for almost all
$\unicode[STIX]{x1D6FC}$
.
The outline of the next sections is as follows. First, in §3, we analyse the contribution of
$R(AA_{\text{same}})$
. Here Diophantine approximation determines the countingFootnote
3
. Then, in §4, we prove variance estimates to control
$R(AG)$
and
$R(AA_{\text{diff}})$
. Once these steps are completed, in §5 we use the Borel–Cantelli lemma with a sandwiching argument to finish the proof of Theorem 1.
3 Analysing the contribution of the small differences
Before proceeding further, we need to recall some notions and results about continued fractions. For a (possibly finite) sequence
$(\unicode[STIX]{x1D6FC}_{i})_{i}$
of strictly positive integers, we denote by
$$\begin{eqnarray}\unicode[STIX]{x1D6FC}:=[\unicode[STIX]{x1D6FC}_{1},\unicode[STIX]{x1D6FC}_{2},\ldots ]=\frac{1}{\unicode[STIX]{x1D6FC}_{1}+\displaystyle \frac{1}{\unicode[STIX]{x1D6FC}_{2}+\displaystyle \frac{1}{\ddots }}}\end{eqnarray}$$
the associated (possibly finite) continued fraction in the unit interval
$[0,1]$
. Moreover, let
$p_{n}/q_{n}$
denote the
$n$
th convergent to
$\unicode[STIX]{x1D6FC}$
. Then the following are well-known facts; cf. for instance, [Reference Bugeaud6, Ch. 1].
(1) Legendre’s theorem. If
$a/b$
is a fraction with then
$$\begin{eqnarray}\bigg|\unicode[STIX]{x1D6FC}-\frac{a}{b}\bigg|<\frac{1}{2b^{2}},\end{eqnarray}$$
$a/b$
is a convergent to
$\unicode[STIX]{x1D6FC}$
.(2) We have
(21)where the implied constants are independent of
$$\begin{eqnarray}\bigg|\unicode[STIX]{x1D6FC}-\frac{p_{n}}{q_{n}}\bigg|\asymp \frac{1}{\unicode[STIX]{x1D6FC}_{n}q_{n}^{2}},\end{eqnarray}$$
$\unicode[STIX]{x1D6FC}$
.(3) Borel–Bernstein theorem. Let
$B:=(b_{n})_{n}$
be a sequence of (strictly) positive real numbers, and consider the series (22)If
$$\begin{eqnarray}\mathop{\sum }_{n\geqslant 1}\frac{1}{b_{n}}.\end{eqnarray}$$
$V_{B}\subset [0,1]$
denotes the set of numbers
$\unicode[STIX]{x1D6FC}=[\unicode[STIX]{x1D6FC}_{1},\unicode[STIX]{x1D6FC}_{2},\ldots ]$
satisfying
$\unicode[STIX]{x1D6FC}_{n}\leqslant b_{n}$
for all sufficiently large
$n\geqslant 1$
, then
Lemma 2. Let
$(m_{j})_{j\geqslant 1}$
be the sequence of primes from Lemma 1, which was used in (10) for the construction of our sequence. Then for almost all
$\unicode[STIX]{x1D6FC}\in [0,1]$
there exist only finitely many pairs of indices
$(j,n)$
such that the prime
$m_{j}$
divides
$q_{n}$
, and such that additionally
$q_{n}/m_{j}\in [2^{j}/j^{2},2^{j}]$
, where
$q_{n}$
is the denominator of a convergent to
$\unicode[STIX]{x1D6FC}$
.
Proof. Assume that the denominator
$q_{n}$
of a convergent is divisible by a prime
$m_{j}$
, that is, there is a
$k$
such that
$q_{n}=km_{j}$
. When
$q_{n}$
is a convergent to
$\unicode[STIX]{x1D6FC}$
we have that
$\Vert q_{n}\unicode[STIX]{x1D6FC}\Vert \leqslant 1/q_{n}$
, and thus
$\Vert km_{j}\unicode[STIX]{x1D6FC}\Vert \leqslant 1/(km_{j})$
. Thus to prove the lemma we have to show that almost all
$\unicode[STIX]{x1D6FC}\in [0,1]$
are contained in at most finitely many sets of the form
We have
Furthermore, we have
Recall that to construct our sequence
$(m_{j})_{j\geqslant 1}$
in Lemma 1 we selected
$d^{2}$
primes from the range
$(2^{d},2^{d+1})$
, for each (sufficiently large)
$d$
. Thus
Thus, by the Borel–Cantelli lemma, almost all
$\unicode[STIX]{x1D6FC}$
are contained in only finitely many sets
$S_{j,k}$
.◻
Lemma 3. Let
Then for almost all
$\unicode[STIX]{x1D6FC}\in [0,1]$
we have
Proof. In this proof we suppress the potential dependence of the symbols “
$\ll$
” and “
$\gg$
” on
$s$
.
Let
$B$
denote the sequence
$(n^{1+\unicode[STIX]{x1D700}/3})_{n}$
, and suppose that
$\unicode[STIX]{x1D6FC}\in V_{B}$
is an irrational number (recall that the set
$V_{B}$
was defined in the statement of the Borel–Bernstein theorem, before the statement of Lemma 2). By the Borel–Bernstein theorem,
$V_{B}$
has full Lebesgue measure. In the sequel we will assume that
$\unicode[STIX]{x1D6FC}\in [0,1]$
is a fixed number which is contained in
$V_{B}$
, and for which the conclusion of Lemma 2 holds. Note that the set of such
$\unicode[STIX]{x1D6FC}$
has full Lebesgue measure.
Let us note the following. Let
$q_{m}$
be the denominator of a convergent to
$\unicode[STIX]{x1D6FC}$
. Assume that
Then, as noted above, we have
Since
$q_{m}$
grows at least exponentially in
$m$
, and since
$\unicode[STIX]{x1D6FC}\in V_{B}$
implies that
$\unicode[STIX]{x1D6FC}_{m}\ll m^{1+\unicode[STIX]{x1D700}/3}\ll (\log q_{m})^{1+\unicode[STIX]{x1D700}/3}$
, we thus see that (23) is only possible if
which in turn is only possible if
Now we argue in two steps.
(i) We first claim the following. If
$j$
is large enough, and if
$M_{j}$
is non-empty, then there exists a unique value of
$n$
such that
$q_{n}$
is the denominator of a convergent to
$\unicode[STIX]{x1D6FC}$
, such that
$q_{n}\geqslant 2^{j}/j^{2}$
, and such that
Indeed, if some
$q$
is contained in
$M_{j}$
, then for this
$q$
we have
$\Vert m_{j}q\unicode[STIX]{x1D6FC}\Vert \leqslant s/2^{j}<1/(2m_{j}q)$
, if
$j$
is sufficiently large. This is a consequence of our construction, where we have
$m_{j}\asymp j^{1/4}$
and
$q\leqslant 2^{j}/j^{1/4+\unicode[STIX]{x1D700}/3}$
. Let
$p\in \mathbb{Z}$
be such that
$\Vert m_{j}q\unicode[STIX]{x1D6FC}\Vert =|m_{j}q\unicode[STIX]{x1D6FC}-p|$
. Then Legendre’s theorem implies that there is some
$n\geqslant 1$
with
As a consequence, since
$p_{n}$
and
$q_{n}$
are coprime, there is some integer
$g\geqslant 1$
such that
$m_{j}q=gq_{n}$
and
$p=gp_{n}$
. Then we have
$\Vert m_{j}q\unicode[STIX]{x1D6FC}\Vert =|gq_{n}\unicode[STIX]{x1D6FC}-gp_{n}|=g|q_{n}\unicode[STIX]{x1D6FC}-p_{n}|$
, and from the reasoning following equation (23) we can deduce that
$q_{n}\gg 2^{j}/j^{1+\unicode[STIX]{x1D700}/3}$
. Thus, provided that
$j$
is sufficiently large,
$q_{n}/m_{j}$
lies in the range
$[2^{j}/j^{2},2^{j}]$
, and then, by Lemma 2, we can assume that
$q_{n}$
is not divisible by
$m_{j}$
.
Since we have now figured out that we may assume that
$m_{j}$
does not divide
$q_{n}$
, we conclude that
$p$
and
$q$
can actually both be written in the form
$p=hm_{j}p_{n}$
and
$q=hm_{j}q_{n}$
for some integer
$h\geqslant 1$
. Observe that (21) implies
and thus
Thus the well-known recursion
$q_{n+1}=\unicode[STIX]{x1D6FC}_{n}q_{n}+q_{n-1}$
yields
$q_{n+1}\geqslant \unicode[STIX]{x1D6FC}_{n}q_{n}\gg j^{1/4}2^{j}$
for sufficiently large
$j$
. However,
$M_{j}$
by definition is a subset of
$\{1,\ldots ,2^{j}/j^{1/4+\unicode[STIX]{x1D700}/3}\}$
. This shows that
$q_{n+1}$
is already too large to be contained in
$M_{j}$
, and consequently
$M_{j}$
consists only of integer multiples of
$q_{n}$
.
(ii) We now give an upper bound for the largest possible value of
$h\geqslant 1$
such that
$hm_{j}q_{n}\in M_{j}$
. From (26) and the definition of
$M_{j}$
we deduce that
As noted above, we have
$2^{j}/j^{1+\unicode[STIX]{x1D700}/3}\ll q_{n}\ll 2^{j}/j^{1/4+\unicode[STIX]{x1D700}/3}$
. Thus
where the
$x\in \mathbb{R}$
maximizing the right-hand side, under the given constraints, is determined via
Thus, using
$\unicode[STIX]{x1D6FC}_{n}\ll (\log q_{n})^{1+\unicode[STIX]{x1D700}/3}\ll j^{1+\unicode[STIX]{x1D700}/3}$
, we finally obtain
Thus
$\#M_{j}\ll j^{1/4}$
, which proves the lemma.◻
4 Analysing the contribution of the large differences
The Fourier series expansion of the indicator functions
$I_{s,N}(\unicode[STIX]{x1D6FC})$
is given by
where we write
$e(\unicode[STIX]{x1D6FC})$
for
$\exp (2\unicode[STIX]{x1D70B}\text{i}\unicode[STIX]{x1D6FC})$
. The next lemma is of a technical nature, and is used in a decoupling argument for the variance bounds, which are derived in §4.1.
Lemma 4. Define for integers
$u,v>0$
the quantity
Then
Moreover, for
$u\neq 0$
, we have
Proof. Note that
$n_{1}u=n_{2}v$
holds if and only if there is an integer
$h\neq 0$
satisfying
$n_{1}=hu/\text{gcd}(u,v)$
and
$n_{2}=hv/\text{gcd}(u,v)$
. Moreover, we observe that
$|c_{n}|\leqslant \min \{2s/N,1/|n|\}$
for
$n\neq 0$
. Combining these estimates with the Cauchy–Schwarz inequality yields
$$\begin{eqnarray}\displaystyle |C(u,v)|^{2} & {\leqslant} & \displaystyle \mathop{\sum }_{h\in \mathbb{Z}\setminus \{0\}}c_{h(u/\text{gcd}(u,v))}^{2}\mathop{\sum }_{h\in \mathbb{Z}\setminus \{0\}}c_{h(v/\text{gcd}(u,v))}^{2}\nonumber\\ \displaystyle & {\leqslant} & \displaystyle \mathop{\sum }_{h\in \mathbb{Z}\setminus \{0\}}\frac{(\text{gcd}(u,v))^{2}}{(uh)^{2}}\mathop{\sum }_{h\in \mathbb{Z}\setminus \{0\}}\frac{(\text{gcd}(u,v))^{2}}{(vh)^{2}},\nonumber\end{eqnarray}$$
which implies (29).
Furthermore,
which implies (30).◻
From orthogonality relations, combined with (27), we obtain
$$\begin{eqnarray}\displaystyle N^{2}\,\text{Var}(R(AG,\cdot ,s,N)) & = & \displaystyle \int _{0}^{1}\bigg(\mathop{\sum }_{d\in {\mathcal{D}}_{N}(AG)}r(d)\mathop{\sum }_{n\in \mathbb{Z}\setminus \{0\}}c_{n}e(dn\unicode[STIX]{x1D6FC})\bigg)^{2}\,d\unicode[STIX]{x1D6FC}\nonumber\\ \displaystyle & = & \displaystyle \mathop{\sum }_{u,v\in {\mathcal{D}}_{N}(AG)}r(u)r(v)C(u,v),\end{eqnarray}$$
where
$r(\cdot )$
is the representation function which counts representations as Case (
$AG$
). A perfect analogue holds when (
$AG$
) is replaced by (
$AA_{\text{diff}}$
) everywhere in the formula (including in the definition of the representation function
$r$
).
The main term on the right-hand side, as we shall see, is the sum over the diagonal
$(r(u))^{2}C(u,u)$
. To prove this, the next lemma shows that the contribution from the off-diagonal terms is small. More precisely,
$C(u,v)$
is extremely small for two elements
$u\neq v$
of
${\mathcal{D}}_{N}(AG)$
or
${\mathcal{D}}_{N}(AA_{\text{diff}})$
.
Lemma 5. We have
where the representation function
$r$
counts representations from Case (
$AG$
). The same estimate holds if
$(AG)$
is replaced by
$(AA_{\text{diff}})$
.
Proof. This is not a critical part in the whole argument, and it is sufficient to use very rough estimates. We only give a brief outline of the proof. Let
$u$
and
$v$
be elements of the difference set
${\mathcal{D}}_{N}(AG)$
such that
$0<u<v$
. Recall that different building blocks of our sequence are separated by huge constants. For
$u$
and
$v$
this leaves only two possibilities.
∙ The first is that
$u$
is of much smaller order than
$v$
, say
$u\ll v^{1/2}$
. By (29) we have
$C(u,v)\ll \gcd (u,v)/\text{max}\{u,v\}$
. Since
$\gcd (u,v)\leqslant u$
, we have
$C(u,v)\ll u/v\ll v^{-1/2}$
.∙ The second possibility is that
$u$
and
$v$
are of very similar size, and that consequently
$v-u$
is very small in comparison with
$v$
. In this case we may assume, for example, that
$v-u\ll v^{1/2}$
. Again using
$C(u,v)\ll \gcd (u,v)/\text{max}\{u,v\}$
, and now observing that
$\gcd (u,v)\leqslant v-u\ll v^{1/2}$
, we obtain
$C(u,v)\ll v^{-1/2}$
.
So in both cases
$C(u,v)$
is small in comparison with
$v$
. By construction the difference set
${\mathcal{D}}_{N}(AG)$
is an extremely sparse set, due to the very fast growth of our sequence. Thus after summing over
$u$
and
$v$
we can obtain (32). A similar argument works when instead of
${\mathcal{D}}_{N}(AG)$
we consider
${\mathcal{D}}_{N}(AA_{\text{diff}})$
.◻
4.1 Variance bounds
We now have the tools at hand to derive the variance bounds for the auxiliary functions
$R(AG,\cdot ,s,N)$
and
$R(AA_{\text{diff}},\cdot ,s,N)$
which were defined in (19).
Lemma 6. For every fixed
$s>0$
, we have
Proof. Again this is not a crucial lemma, and it is sufficient to use very rough estimates. Note that trivially
$\#{\mathcal{D}}_{N}(AG)\leqslant N^{2}$
. Let
$u\in {\mathcal{D}}_{N}(AG)$
. Then, using again the fact that our sequence increases very quickly, we can easily show that the number of Case (
$AG$
) representations
$r(u)$
which
$u$
has as the difference of two elements from
$A_{N}$
is very small. To give a quantitative statement, we could easily show that
$r(u)\ll N^{1/4}$
, uniformly in
$u$
(this is just a very rough estimate). Hence (30) implies
The contribution coming from numbers which arise as the difference between two numbers from different arithmetic blocks is a bit more difficult to control. To see this, note that when there are two arithmetic progressions with different step sizes
$m_{j_{1}}$
and
$m_{j_{2}}$
, there are certain numbers which have many representations as a number from the first arithmetic progression, minus a number from the second arithmetic progression. To control the contribution from such numbers, we will make crucial use of the fact that in our construction the step sizes
$m_{j_{1}}$
and
$m_{j_{2}}$
are prime numbers.
Lemma 7. For every fixed
$s>0$
, we have
Proof. Let
$N$
be given. There is some
$J$
such that
$a_{N}\in P_{A}(J)\cup P_{G}(J)$
, and by construction for this value of
$J$
we have
$J\asymp \log N$
. By (31) and Lemma 5 we have
$$\begin{eqnarray}\displaystyle \text{Var}(R(AA_{\text{diff}},\cdot ,s,N)) & {\leqslant} & \displaystyle \frac{1}{N^{2}}\mathop{\sum }_{u,v\in {\mathcal{D}}_{N}(AA_{\text{diff}})}r(u)r(v)|C(u,v)|\nonumber\\ \displaystyle & \ll & \displaystyle \frac{1}{N^{2}}\bigg(1+\mathop{\sum }_{1\leqslant j_{1}<j_{2}\leqslant J}\mathop{\sum }_{u\in P_{A}(j_{2})-P_{A}(j_{1})}r(u)^{2}|C(u,u)|\bigg),\nonumber\end{eqnarray}$$
where
$r(u)$
counts the number of representation of
$u$
as the difference between an element of
$P_{A}(j_{2})$
and an element of
$P_{A}(j_{1})$
. Here we used the fact that due to the huge constants which separate different blocks in our construction, for given
$u$
there is only one pair
$(j_{1},j_{2})$
such that
$u\in P_{A}(j_{2})-P_{A}(j_{1})$
, except perhaps for finitely many (small) values of
$u$
.
Let
$j_{1}<j_{2}$
be fixed. First assume that
$j_{1}<J-2\log J$
. We note that the cardinality of the set
$P_{A}(j_{2})-P_{A}(j_{1})$
is bounded by
$$\begin{eqnarray}\displaystyle \#\{P_{A}(j_{2})-P_{A}(j_{1})\} & \ll & \displaystyle \max \{P_{A}(j_{2})-P_{A}(j_{1})\}-\min \{P_{A}(j_{2})-P_{A}(j_{1})\}\nonumber\\ \displaystyle & \ll & \displaystyle m_{j_{2}}\frac{N}{(\log N)^{1/4+\unicode[STIX]{x1D700}/3}}\nonumber\\ \displaystyle & \ll & \displaystyle \frac{N}{(\log N)^{\unicode[STIX]{x1D700}/3}}.\end{eqnarray}$$
Then by the trivial estimate
$r(u)\ll \#P_{A}(j_{1})\ll N/(\log N)^{2\log 2+1/4}$
, and since
$2\log 2+1/4>16/10$
, we have
$$\begin{eqnarray}\displaystyle \frac{1}{N^{2}}\mathop{\sum }_{\substack{ j_{1},j_{2}, \\ j_{1}<J-2\log J}}\mathop{\sum }_{u\in P_{A}(j_{2})-P_{A}(j_{1})}r(u)^{2}|C(u,u)| & \ll _{s} & \displaystyle \frac{J^{2}}{N^{2}}\frac{N^{3}}{(\log N)^{16/5}}\frac{1}{N}\nonumber\\ \displaystyle & \ll & \displaystyle \frac{1}{(\log N)^{6/5}}.\end{eqnarray}$$
It remains to control the contribution from the range
$J-2\log J\leqslant j_{1}<j_{2}\leqslant J$
. Here it plays a crucial role that, for
$j_{1},j_{2}$
in this range, by construction there are two different primes
$m_{j_{1}}$
and
$m_{j_{2}}$
which form the step sizes of the arithmetic progression
$P_{A}(j_{1})$
and
$P_{A}(j_{2})$
, respectively (cf. Lemma 1). Therefore, in such a situation
$r(u)$
is bounded by the number of solutions
$(x,y)\in \mathbb{Z}^{2}$
to the linear Diophantine equation
and
$(x,y)$
satisfies the additional restriction that
$1\leqslant x,y\leqslant N/(\log N)^{1/4+\unicode[STIX]{x1D700}/3}$
. Since
$m_{j_{1}}$
and
$m_{j_{2}}$
are prime numbers, the set of integer solutions to this equation admits the form
where
$h\in \mathbb{Z}$
and
$(x_{0},y_{0})$
is some solution to the above equation. Moreover, the size of
$j_{1}$
and
$j_{2}$
, together with (6), ensures that
$m_{j_{1}}\asymp m_{j_{2}}\asymp (\log N)^{1/4}$
. Hence,
Thus using (30), (35) and (37), and noting that
$\log J\ll \log \log N\ll (\log N)^{\unicode[STIX]{x1D700}/2}$
, we obtain that
$$\begin{eqnarray}\displaystyle & & \displaystyle \frac{1}{N^{2}}\mathop{\sum }_{\substack{ j_{1},j_{2}, \\ J-2\log J\leqslant j_{1}<j_{2}\leqslant J}}\underset{u\in P_{A}(j_{2})-P_{A}(j_{1})}{\sum }r(u)^{2}|C(u,u)|\nonumber\\ \displaystyle & & \displaystyle \quad \ll _{s}\frac{1}{N^{2}}\mathop{\sum }_{\substack{ j_{1},j_{2}, \\ J-2\log J\leqslant j_{1}<j_{2}\leqslant J}}\frac{N^{3}}{(\log N)^{1+\unicode[STIX]{x1D700}}}\frac{1}{N}\nonumber\\ \displaystyle & & \displaystyle \quad \ll \frac{1}{(\log N)^{1+\unicode[STIX]{x1D700}/2}}.\nonumber\end{eqnarray}$$
5 Proof of Theorem 1
Let
$N$
be given. There is a number
$J$
such that
$a_{N}\in P_{A}(J)\cup P_{G}(J)$
, and for this value of
$J$
we have
$J\asymp \log N$
and
$2^{J}\asymp N$
. Then
where we used that the additive energy of an arithmetic progression is proportional to the third power of its cardinality, and that by construction
$\#P_{A}(J-1)\gg 2^{J}/J^{1/4+\unicode[STIX]{x1D700}/3}\gg N/(\log N)^{1/4+\unicode[STIX]{x1D700}/3}$
. Thus the additive energy of the sequence constructed in our example is indeed as large as claimed in the statement of the theorem.
It remains to show that
$(a_{n})_{n}$
has the metric pair correlation property. Recall that the contribution coming from the geometric blocks gives the desired convergence
$R(GG,\unicode[STIX]{x1D6FC},s,N)\rightarrow 2s$
for almost all
$\unicode[STIX]{x1D6FC}$
, for every fixed
$s>0$
, cf. (20). It is a standard procedure to use the variance estimates and the results from the previous section to conclude that the contribution of the parts
$R(AG)$
and
$R(AA_{\text{diff}})$
tends to zero in the limit; thus we will only give a brief outline. Fix a rational
$s>0$
. Define the sequence
and note that
$N_{m+1}/N_{m}\rightarrow 1$
. If
$N$
is such that
$N_{m}\leqslant N<N_{m+1}$
, then
Denote by
$E_{AG,s}(N_{m})$
the “exceptional” set
where
$\unicode[STIX]{x1D707}_{AG,s}(N_{m})$
is the expected value of
$R(AG,\unicode[STIX]{x1D6FC},N_{m}/N_{m+1}s,N)$
. Observe that
$\unicode[STIX]{x1D707}_{AG,s}(N_{m})\rightarrow 0$
as
$m\rightarrow \infty$
, since the indices of those elements of
$(a_{n})_{n}$
which come from an arithmetic block are contained in a set of zero density within the total index set. Combining Chebyshev’s inequality with the variance estimates from Lemmas 6 and 7, and applying the Borel–Cantelli lemma, we obtain
for all rational
$s$
and for Lebesgue almost all
$\unicode[STIX]{x1D6FC}\in [0,1]$
. Exactly the same argument works if (
$AG$
) is replaced by (
$AA_{\text{diff}}$
).
Finally we have to show that
$R(AA_{\text{same}})\rightarrow 0$
for almost all
$\unicode[STIX]{x1D6FC}$
. Let
$s>0$
be fixed, and assume that
$s$
is rational. By the Borel–Bernstein theorem, almost no
$\unicode[STIX]{x1D6FC}\in [0,1]$
has infinitely many
$d\geqslant N/(\log N)^{3/2}$
such that
$I_{s,N}(d\unicode[STIX]{x1D6FC})=1$
. Hence it is sufficient to estimate the contribution of those differences
$d$
which are contained in
$(P_{A}(j)-P_{A}(j))^{+}$
for a value of
$j$
which is close to
$J$
. More precisely, we can restrict
$j$
to the range
$J-2\log J\leqslant j\leqslant J$
. By Lemma 3, for almost all
$\unicode[STIX]{x1D6FC}\in [0,1]$
we have
$$\begin{eqnarray}\displaystyle & & \displaystyle R(AA_{\text{same}},\unicode[STIX]{x1D6FC},s,N)\nonumber\\ \displaystyle & & \displaystyle \quad \ll \frac{1}{N}\mathop{\sum }_{J-2\log J\leqslant j\leqslant J}\frac{2^{j}}{j^{1/4+\unicode[STIX]{x1D700}/3}}\cdot \#\bigg\{d\in (P_{A}(j)-P_{A}(j))^{+}:~\Vert d\unicode[STIX]{x1D6FC}\Vert \leqslant \frac{s}{N}\bigg\}\nonumber\\ \displaystyle & & \displaystyle \quad \ll _{s}~\frac{1}{N}\mathop{\sum }_{J-2\log J\leqslant j\leqslant J}\frac{2^{j}}{j^{\unicode[STIX]{x1D700}/3}}\nonumber\\ \displaystyle & & \displaystyle \quad \ll (\log N)^{-\unicode[STIX]{x1D700}/6},\end{eqnarray}$$
where we estimated
$\log J\ll \log \log N\ll (\log N)^{\unicode[STIX]{x1D700}/6}$
.
Thus we have
$R(GG)\rightarrow 2s$
,
$R(AG)\rightarrow 0$
,
$R(AA_{\text{diff}})\rightarrow 0$
and
$R(AA_{\text{same}})\rightarrow 0$
, for all rational
$s>0$
, for almost all
$\unicode[STIX]{x1D6FC}$
. However, if this convergence holds for all rational
$s>0$
and almost all
$\unicode[STIX]{x1D6FC}$
, then by monotonicity it must also hold for all real
$s>0$
and almost all
$\unicode[STIX]{x1D6FC}$
. In view of the decomposition (18), this concludes the proof of the theorem.
Acknowledgements
The authors would like to thank the anonymous referee for many valuable suggestions which significantly improved the presentation of this paper. C. A. is supported by the Austrian Science Fund (FWF), projects Y-901 and F 5512-N26. T. L. is also supported by FWF project Y-901. N. T. was supported by FWF project W1230, and by EPSRC Programme Grant EP/J018260/1. A non-trivial proportion of the present work was carried out while N. T. visited the number theory group of the University of York. He wishes to thank this group for its warm hospitality and the pleasant memories.






