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Effects of rotation on the gravitational momentum transfer in neutron-star kicks and implications for spin-kick alignment

Published online by Cambridge University Press:  29 September 2026

Yiming Lu
Affiliation:
Physics and Astronomy, University of Rochester, USA
Eric G. Blackman*
Affiliation:
Physics and Astronomy, University of Rochester, USA
*
Corresponding author: Eric G. Blackman; Email: blackman@pas.rochester.edu
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Abstract

Neutron stars are often born with large recoil velocity kicks, whose physical origin remains an open question in core-collapse supernova theory. Observations suggest that the spin-kick angle distribution is somewhat skewed towards a spin-kick vector alignment. One possible kick mechanism is the gravitational tug-boat effect, in which anisotropic ejecta gravitationally accelerate the proto-neutron star over a timescale of seconds after shock revival, although the long-term importance of this relative to other hydrodynamic forces remains debated. Previous derivations of the tug-boat mechanism do not include the effect of initial stellar rotation. Here, we derive a minimalist extension to assess how rotation of the expanding asymmetric mass distribution influences spin-kick alignment of gravitational momentum transfer. We show that the spin-kick angle is determined by the product of two factors, one that depends on the ratio of shock expansion time to the rotation period and the other that depends on the orientation of the asymmetric mass distribution with respect to the spin-axis. For fast enough rotation, the first factor amounts to axially averaging out non-axisymmetry thereby suppressing the perpendicular tug and leaving only a spin-aligned force. However, the rotation speed required for this effect would be unrealistically large unless magnetic fields transport angular momentum from core to outflow efficiently. Spin-kick alignment by the tug-boat mechanism would otherwise require a preferentially spin-aligned mass flux asymmetry. The rotational-averaging framework here suggests that for any kick mechanism not itself sourced by rotation, including rotation will tend to spin-align the kick, but reduce the kick magnitude.

Information

Type
Research Article
Creative Commons
Creative Common License - CCCreative Common License - BY
This is an Open Access article, distributed under the terms of the Creative Commons Attribution licence (https://creativecommons.org/licenses/by/4.0/), which permits unrestricted re-use, distribution and reproduction, provided the original article is properly cited.
Copyright
© The Author(s), 2026. Published by Cambridge University Press on behalf of Astronomical Society of Australia
Figure 0

Figure 1. Schematic illustration of the non-rotating gravitational tug-boat model.

Figure 1

Figure 2. Time evolution of the NS velocity predicted by Equation (15), including the additional correction factor of 2 as discussed below Equation (7). The fiducial parameters are ri=2000km$r_i = 2\,000\,\mathrm{km}$, vs=104kms−1$v_s = 10^4\,\mathrm{km\,s^{-1}}$, M=1.5M⊙$M = 1.5\,\mathrm{M}_\odot$, and Δm(0)=2×10−2M⊙$\Delta m(0) = 2\times10^{-2}\,\mathrm{M}_\odot$. The time origin is shifted to t=0.2s$t=0.2\,\mathrm{s}$, corresponding to the onset of the tug-boat phase.

Figure 2

Figure 3. Schematic illustration of the rotating tug-boat model. (a) Side view in the x−z$x-z$ plane. The effective asymmetric point mass is located in polar angle θ$\theta$, with the rotation axis aligned with the z-axis. Its radial position increases at a constant velocity vs$v_s$. (b) Top-down view of the model. ϕ$\phi$ is the azimuthal angle in the x−y$x-y$ plane and is given by Equation (25). The perturbed mass spirals outward during the explosion.

Figure 3

Figure 4. Probability distribution of the spin-kick angle α$\alpha$ for different values of β$\beta$, calculated from Equation (31). The initial asymmetry direction is assumed to be isotropically distributed, so that p(θ)∝sin⁡θ$p(\theta)\propto \sin\theta$.

Figure 4

Figure 5. Rotational-averaging factor |sinc(β/2)|=|sin⁡(β/2)/(β/2)|$|\mathrm{sinc}(\beta/2)|=|\sin(\beta/2)/(\beta/2)|$ as a function of β$\beta$. The first zero occurs at β=2π$\beta=2\pi$.