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LOG-TRANSFORM AND THE WEAK HARNACK INEQUALITY FOR KINETIC FOKKER-PLANCK EQUATIONS

Published online by Cambridge University Press:  16 May 2022

Jessica Guerand
Affiliation:
Department of Pure Mathematics and Mathematical Statistics, University of Cambridge, Wilberforce Road, CB3 0WB Cambridge, United Kingdom (jg900@cam.ac.uk)
Cyril Imbert*
Affiliation:
Département de Mathématiques et applications, École Normale Supérieure, CNRS, PSL Research University, 45 rue d’Ulm, 75005 Paris, France
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Abstract

This article deals with kinetic Fokker–Planck equations with essentially bounded coefficients. A weak Harnack inequality for nonnegative super-solutions is derived by considering their log-transform and adapting an argument due to S. N. Kružkov (1963). Such a result rests on a new weak Poincaré inequality sharing similarities with the one introduced by W. Wang and L. Zhang in a series of works about ultraparabolic equations (2009, 2011, 2017). This functional inequality is combined with a classical covering argument recently adapted by L. Silvestre and the second author (2020) to kinetic equations.

Information

Type
Research Article
Copyright
© The Author(s), 2022. Published by Cambridge University Press
Figure 0

Figure 1 Expansion of positivity.

Figure 1

Figure 2 Geometric setting of the weak Poincaré inequality.

Figure 2

Figure 3 Reducing to the case with a time lap.

Figure 3

Figure 4 Geometric setting of the expansion of positivity lemma. It is the same as the one of the weak Poincaré inequality, except that $Q_{\mathrm {ext}}$ and $Q_{\mathrm {zero}}$ are replaced with $\mathcal {Q}_{\mathrm {whi}}$ and $Q_{\mathrm {pos}}$. Here, $Q_{\mathrm {pos}}$ denotes a set ‘in the past’ where $\{f \ge 1\}$ occupies half of it.

Figure 4

Figure 5 Intermediate cylinders in the proof of the expansion of positivity. The great parts are obtained after a scaling with a parameter $1+\iota $ close to $1$. This is necessary in order to keep f vanishing in a ‘good ratio’ of $S_{(1+\iota )}(Q_{\mathrm {zero}})$.

Figure 5

Figure 6 Stacking cylinders above an initial one contained in$Q_{-}$. We see that the stacked cylinder obtained after $N+1$ iterations by doubling the radius leaks out of the domain. This is the reason why $Q[N+1]$ is chosen in a way that it is contained in the domain and its ‘predecessor’ is contained in $Q[N]$. Notice that the cylinders $Q[k]$ are in fact slanted since they are not centered at the origin. We also mention that $Q[N+1]$ is choosen centered if the time $t_{0}+T_{N}$ is too close to the final time $0$.