1 Introduction
The main goal of this article is to initiate the study of horospherical varieties over algebraically closed fields of positive characteristic. Horospherical varieties form a natural subclass of spherical varieties, encompassing both flag varieties and toric varieties, yet their combinatorial structure is considerably more tractable. The combinatorial classification proceeds in two stages: first, one classifies the underlying homogeneous spaces (the focus of the present article); next, one applies Luna–Vust theory to classify equivariant embeddings of a fixed homogeneous space – a program already carried out by Knop [Reference KnopKno91] over an arbitrary algebraically closed base field.
Building on this, our ultimate aim (in a forthcoming paper) is to classify smooth projective horospherical varieties with Picard number one, in analogy with Pasquier’s work [Reference PasquierPas09] over algebraically closed fields of characteristic zero, which produced new families of almost homogeneous varieties with rich and intricate geometry (see, e.g., [Reference Gonzales, Pech, Perrin and SamokhinGPPS22, Reference KimKim17, Reference Kim and ParkKP18, Reference Pasquier and ManivelPM23]).
We now turn to the main definitions and setup. Let G be a (connected) reductive group over an algebraically closed field of characteristic
$p> 0$
. If H is a subgroup (scheme) of G, we denote by
$N_G(H)$
the normalizer of H in G. A subgroup
$H \subset G$
is called horospherical if it contains a maximal unipotent smooth connected subgroup of G. A subgroup H is called strongly horospherical if, in addition,
$N_G(H)$
is a parabolic subgroup of G.
Note that if we were in characteristic
$0$
, the notions of horospherical subgroups and strongly horospherical subgroups would align, as the normalizer of any horospherical subgroup is then necessarily parabolic (see [Reference PasquierPas08, Proposition 2.2]). This is not necessarily the case in positive characteristic as the next example shows.
Example 1.1 Let
$p=2$
and consider the following connected subgroup of
$\operatorname {\mathrm {SL}}_2$
, whose definition can be found in [Reference KnopKno95, Section 2]:
Setting
$a=1$
, we see that H indeed contains
$U=H_{\mathrm {red}}$
; however, an explicit computation done in loc. cit. shows that the normalizer of H is equal to H itself. In particular, H is horospherical but not strongly horospherical. Note also that
$\operatorname {\mathrm {Lie}}(H)=\operatorname {\mathrm {Lie}}(B)$
is T-stable (for the restriction of the adjoint action), where
$B \subset \operatorname {\mathrm {SL}}_2$
is a Borel subgroup and
$T \subset B$
is a maximal torus, although H itself is not normalized by T.
However, and quite surprisingly, it turns out that the existence of horospherical but not strongly horospherical subgroups occurs only in characteristic
$2$
. The main result of this article is as follows.
Theorem 1.2 (Theorem 5.6)
Assume that
$p \geq 3$
. Let G be a reductive group and let H be a subgroup of G. Then H is horospherical if and only if H is strongly horospherical.
Moreover, when
$p \geq 3$
, any strongly horospherical subgroup
$H \subset G$
satisfies that
$N_G(H)/H$
is a torus (see Proposition 4.4), whereas this is not always the case when
$p=2$
(see Example 4.6). Consequently, over a field of characteristic
$p \geq 3$
, horospherical subgroups are easily classified.
Corollary 1.3 (Corollary 4.9)
Assume that
$p \geq 3$
and denote by
$\mathcal {P}$
the set of functions
$\Phi ^+ \to \mathbb {N} \cup \{\infty \}$
associated with parabolic subgroups of G (see Section 2.1). There is a one-to-one correspondence between the set of conjugacy classes of horospherical subgroups of G and the set of pairs
$(\varphi , M)$
, where
$\varphi \in \mathcal {P}$
and M is a sublattice of
$X^\ast (P_\varphi )$
, with
$P_\varphi $
the standard parabolic subgroup of G associated with the function
$\varphi $
.
Remark 1.4 It would be interesting to extend the classification of horospherical subgroups of G to the case
$p=2$
. In this setting, two additional difficulties occur:
-
• There exist strongly horospherical subgroups $H \subset G$
such that
$N_G(H)/H$
is not a torus (see Example 4.6). This issue can be circumvented by replacing
$N_G(H)$
with the smaller parabolic subgroup
$HT$
(see Remark 4.8). -
• More seriously, there exist horospherical subgroups of G that are not strongly horospherical (see Example 1.1). Hence restricting to strongly horospherical subgroups is not sufficient.
Let us note that, even when
$p \neq 2$
, the situation over a field of characteristic
$p>0$
is much richer than over a field of characteristic
$0$
. Consider, for instance, the toy case
$G=\operatorname {\mathrm {SL}}_2$
. Over a field of characteristic
$0$
, any nontrivial horospherical subgroup of
$\operatorname {\mathrm {SL}}_2$
is conjugate either to a Borel subgroup
$B \subset \operatorname {\mathrm {SL}}_2$
or to
$\boldsymbol {\mu }_n \ltimes U$
, with
$U := R_u(B)$
and
$\boldsymbol {\mu }_n$
the subgroup of the multiplicative group
$\mathbf {G}_m$
defined by
$t^n = 1$
. In contrast, over a field of characteristic
$p \geq 3$
, any nontrivial horospherical subgroup of
$\operatorname {\mathrm {SL}}_2$
is conjugate to the pullback, via an iterated Frobenius morphism, of either B or
$\boldsymbol {\mu }_n \ltimes U$
for some
$n \geq 1$
(see Section 5.2).
As mentioned earlier, now that a complete classification of horospherical homogeneous spaces has been achieved (for
$p \geq 3$
), we plan in forthcoming work to study smooth projective horospherical varieties of Picard number one, with the goal of identifying new and interesting families – beyond flag varieties – that do not occur in characteristic
$0$
.
1.1 Outline of the article
Section 2 reviews the classification of parabolic subgroup schemes for
$p \geq 3$
, together with a description of their character lattices. In Section 3, we show that almost all Lie subalgebras of
$\operatorname {\mathrm {Lie}}(G)$
containing
$\operatorname {\mathrm {Lie}}(U)$
are T-stable when
$p \geq 3$
. Section 4 is devoted to strongly horospherical subgroups of G: we establish some basic properties and then provide a complete classification in the case
$p \geq 3$
(Corollary 4.9). Finally, Section 5 presents the proof of our main result (Theorem 5.6).
1.2 Notation and setting
We work over an algebraically closed field
$\mathbb {K}$
of characteristic
$p> 0$
. Throughout, we consider group schemes of finite type over
$\mathbb {K}$
, so all subgroups are understood as subgroup schemes and are not necessarily smooth. For background on the theory of group schemes, we primarily refer to [Reference Demazure and GabrielDG70, Reference MilneMil17], and to a lesser extent [Reference JantzenJan03].
Let G be a (smooth) connected reductive algebraic group. Since any connected reductive algebraic group G admits a finite central isogeny from a product
$C \times G'$
, where
$C \subset G$
is a maximal central torus and
$G' \subset G$
is the derived subgroup, we may assume from now on, without loss of generality, that
$G \simeq C \times G'$
, where C is a torus and
$G'$
is a simply-connected semisimple group.
We fix once and for all a Borel subgroup
$B \subset G$
and a maximal torus
$T \subset B$
. Let U denote the unipotent radical of B. A parabolic subgroup is a subgroup
$P \subset G$
containing a Borel subgroup of G; since we are working over an algebraically closed field, this is equivalent to the homogeneous space
$G/P$
being projective. Parabolic subgroups are not assumed to be smooth in general. Given a subgroup
$H \subset G$
, we denote by
$N_G(H)$
the (scheme-theoretic) normalizer of H in G, and by
$H_{\mathrm {red}}$
its associated reduced subscheme, which is a subgroup of H.
Let
$\Phi \supset \Phi ^+ \supset \Delta $
be the sets of roots, positive roots, and simple roots of G with respect to T and B, respectively. For each root
$\gamma \in \Phi $
, let
$U_\gamma $
denote the corresponding root subgroup,
$u_\gamma \colon \mathbb {G}_a \to U_\gamma $
the associated root homomorphism, and
$\mathfrak {g}_\gamma $
the corresponding root subspace in
$\mathfrak {g} = \operatorname {\mathrm {Lie}}(G)$
. For a simple root
$\alpha \in \Delta $
, let
$P^\alpha $
denote the maximal smooth parabolic subgroup not containing
$U_{-\alpha }$
.
Let
$F^m \colon G \to G^{(m)}$
be the q-th (relative) Frobenius morphism, where
$q = p^m$
for some
$m \geq 1$
. Its kernel is denoted by
${}_m G$
. If H is a subgroup of G, then
$F^m$
induces a short exact sequence of
$\mathbb {K}$
-group schemes
Note that
$F^m(H) \subset H^{(m)}$
with equality when H is smooth (see, e.g., [Reference JantzenJan03, Part I, Section 9.5]). Given a subgroup H of G, we call height of H the smallest integer m such that
$F^m(H) \simeq H/{}_m H$
is smooth. In particular, a connected finite group scheme J has height m if m is the smallest integer such that
$J={}_mJ$
. For any integer
$n \geq 1$
, we denote by
$\boldsymbol {\mu }_n$
the subgroup of the multiplicative group
$\mathbf {G}_m$
defined by
$t^n = 1$
; in particular,
$\boldsymbol {\mu }_{p^r} = {}_r \mathbf {G}_m$
. We denote by
$\boldsymbol {\alpha }_{p^r}$
the r-th Frobenius kernel of the additive group
$\mathbf {G}_a$
. A group scheme is called infinitesimal if its associated reduced subscheme consists of a single point; this is equivalent to the group scheme having finite height.
For the notion of a restricted Lie algebra (or p-Lie algebra), which will be used throughout this article, we refer to [Reference MilneMil17, Definition 10.39]. Recall that a restricted Lie algebra is a Lie algebra
$\mathfrak {g}$
endowed with a map
$\mathfrak {g} \to \mathfrak {g},\ x \mapsto x^{[p]}$
, satisfying certain compatibility conditions. In particular, whenever a Lie algebra arises from an algebraic group (in characteristic p), it carries a natural restricted structure.
2 Parabolic subgroups and classification for
$\boldsymbol{p \geq 3}$
Over an algebraically closed field of characteristic
$0$
, it is well known that any horospherical subgroup is normalized by a parabolic subgroup, and that this parabolic subgroup is uniquely determined, up to conjugation, by a subset of the simple roots of G. In positive characteristic, the situation becomes more intricate; nonetheless, parabolic subgroups remain crucial in the study of horospherical subgroups. To address this, we begin by presenting the classification of parabolic subgroups for
$p \geq 3$
, which synthesizes several classical results. Specifically, this classification builds upon the works of [Reference Haboush and LauritzenHL93, Reference WenzelWen93] for the case
$p \geq 5$
and of [Reference MaccanMac24, Reference MaccanMac25] to cover the remaining cases when
$p=3$
.
2.1 Associated function
Let G be a simply-connected semisimple group over
$\mathbb {K}$
. For a (non-necessarily smooth) parabolic subgroup P with reduced part
$P_{\mathrm {red}}$
, we denote as
its intersection with the unipotent radical of the opposite reduced parabolic of
$P_{\mathrm {red}}$
. The subgroup
$U_P^-$
is unipotent, infinitesimal and satisfies
where both identities are isomorphisms of schemes given by the multiplication of G (see [Reference WenzelWen93, Lemma 2 and Proposition 4]). Thus, P can be recovered from its reduced part
$P_{\mathrm {red}}$
, together with its intersections with all the root subgroups contained in the opposite unipotent radical
$R_u(P_{\mathrm {red}}^-)$
. Let us reformulate this statement in a more combinatorial fashion, introducing a numerical function. This follows [Reference WenzelWen93, Notation 9]. Recall that we denote the kernel of the n-th iterated Frobenius of the additive group
$\mathbf {G}_a$
as
$\boldsymbol {\alpha }_{p^n}$
; while
$\boldsymbol {\alpha }_{p^\infty }$
is understood to be
$\mathbf {G}_a$
.
Definition 2.1 Let P be a parabolic subgroup of G containing B. The associated function
is defined by the formula
In other words, any positive root
$\gamma $
not belonging to the root system of the Levi subgroup
$P_{\mathrm {red}} \cap P_{\mathrm {red}}^-$
is sent to the natural number corresponding to the height of the finite unipotent subgroup
$P \cap U_{-\gamma }$
, while all other roots are sent to infinity.
For instance, in characteristic zero, or when P is a smooth parabolic subgroup, the associated function
$\varphi $
takes only the values
$0$
and
$\infty $
. As a first example specific to positive characteristic, let us mention that the function associated with the parabolic subgroup
$_mG P^\alpha $
sends all positive roots to
$\infty $
, except for those whose support contains
$\alpha $
, which are assigned the value m.
Theorem 2.2 [Reference WenzelWen93, Theorem 10]
The parabolic subgroup P is uniquely determined by the function
$\varphi $
, with no assumption on the characteristic or on the Dynkin diagram of G.
The following is (probably) a well-known result for experts, but for which the authors could not locate any reference in the literature. In the case of a reduced parabolic subgroup, this is a result due to Chevalley (see [Reference MilneMil17, Corollary 17.49]).
Corollary 2.3 Let P be a parabolic subgroup of G; then
$P = N_G(P)$
.
Proof Let
$Q = N_G(P)$
; then Q is a parabolic subgroup containing P, and in particular, it is determined by the height of the intersections
$Q \cap U_{-\gamma }$
, where
$\gamma $
ranges over the positive roots of G. To prove that
$Q=P$
, by Theorem 2.2, it is enough to show that the corresponding heights coincide. Assume that
$P\cap U_{-\gamma }$
has height
$r \in \mathbf {N} \cup \{\infty \}$
and consider the copy of
$\operatorname {\mathrm {SL}}_2$
generated by
$U_{-\gamma }$
and
$U_\gamma $
. Then assume (on the functor of points) that
$c^{p^r}=0$
and compute
If we want the matrix on the right-hand side to be still in P, we need
Since there are no particular conditions on the variables
$a,b,d$
(other than the fact that the corresponding matrix above must belong to
$\operatorname {\mathrm {SL}}_2$
), we get that
$w^{p^r} = 0$
, that is, that the subgroup
$Q \cap U_{-\gamma }$
has height r, as wanted.
2.2 A very special isogeny
Assume that G is simple and that its Dynkin diagram contains a single edge of multiplicity p: that is, either G is of type
$B_n$
,
$C_n$
, or
$F_4$
in characteristic
$p = 2$
, or G is of type
$G_2$
in characteristic
$p = 3$
. Under these assumptions, one can define the so-called very special isogeny of G as the quotient
by a subgroup
$K = K_G$
which is normal, non-central, contained in the first Frobenius kernel, and minimal with respect to these properties.
This subgroup is uniquely determined by its Lie algebra, which is defined as the smallest restricted Lie subalgebra containing the root subspaces corresponding to all short roots. More precisely, the isogeny
$\pi _G$
acts as Frobenius on the additive groups associated with short roots, and as the identity on those associated with long roots.
The quotient group
$\overline {G}$
is simple and simply-connected, and its root system is dual to that of G. Moreover, the composition
$\pi _{\overline {G}} \circ \pi _G$
equals the Frobenius morphism. For further details, see the original work of Borel and Tits [Reference Borel and TitsBT72], as well as [Reference Conrad, Gaber and PrasadCGP15, Chapter 7].
2.3 Classification for
$\boldsymbol{p \geq 3}$
The following two results (Theorems 2.4 and 2.5) provide a complete classification of the parabolic subgroups of a simply-connected semisimple group G over an algebraically closed field of characteristic
$p \geq 3$
. We will use this classification in the proof of the main result of this article (Theorem 5.6).
Note that every parabolic subgroup of a product
$G = G' \times G"$
, where
$G'$
and
$G"$
are simply-connected simple groups, is the product of a parabolic subgroup of
$G'$
and a parabolic subgroup of
$G"$
(see [Reference MaccanMac25, Lemma 1.2], whose proof relies on the structure results of Theorem 2.2 and [Reference WenzelWen93, Theorem 8]). This observation allows us to reduce to the case where G is a simply-connected simple group.
The first result concerns parabolic subgroups whose reduced part is maximal among reduced parabolic subgroups, and it was established in [Reference MaccanMac24].
Theorem 2.4 Assume that
$p \geq 3$
. Let G be a simply-connected simple group, and let P be a parabolic subgroup of G such that
$P_{\mathrm {red}} = P^\alpha $
.
If either
$p \geq 5$
, or G is simply laced, or
$p=3$
and G is of type
$B_n$
,
$C_n$
, or
$F_4$
, then there exists an integer
$r \geq 0$
such that
Otherwise, G is of type
$G_2$
and
$p=3$
. In this case, there exists an integer
$r \geq 0$
such that
where K denotes the kernel of the very special isogeny
$\pi _G \colon G \to \overline {G}$
.
The second result completes the classification of parabolic subgroups of G for
$p \geq 3$
and is proven in [Reference MaccanMac25].
Theorem 2.5 Let P be a parabolic subgroup of a reductive group G, and let
$\beta _1,\ldots , \beta _r$
be the simple roots of G such that
$P_{\mathrm {red}}$
is the intersection of the parabolic subgroups
$P^{\beta _i}$
. Then
where
$Q^i$
is the smallest subgroup of G containing both P and
$P^{\beta _i}$
. In particular, every parabolic subgroup P can be expressed as the intersection of parabolic subgroups whose reduced part is maximal.
2.4 Character lattice
We now describe explicitly the character lattice of an arbitrary parabolic subgroup of a simply-connected simple group. The reductive case follows by taking direct sums. Such a description will be needed later to show that any horospherical subgroup is strongly horospherical when
$p \geq 3$
. In characteristic at least
$5$
, the following result, due to [Section 2, Reference Haboush and LauritzenHL93], holds.
Lemma 2.6 Let
$p \geq 5$
. Then the character lattice of the parabolic subgroup
is given by
where
$\varpi _\alpha $
denotes the fundamental weight associated with the simple root
$\alpha $
.
For
$p=3$
, the only additional input in the classification of parabolic subgroups comes from the very special isogeny, which occurs when the group is of type
$G_2$
. In that case, we denote by
the preimage of K under the r-th iterated Frobenius. By Theorems 2.4 and 2.5, an arbitrary parabolic subgroup is then of the form
for some integers
$r_\alpha \geq 0$
and
$r_\nu \geq 1$
and some distinct subsets of simple roots I and J. This description is unique under the assumption that each factor in the above intersection is minimal with respect to inclusion.
Lemma 2.7 Let
$p=3$
, and let P be a parabolic subgroup as in (2.3). Then its character group is given by
Proof Recall that the character group of P is naturally identified with the Picard group of the corresponding homogeneous space
$G/P$
(see, e.g., [Reference BrionBri04, Remark 1.4.2]). From the description of the Picard group in terms of Schubert divisors (given in [Reference MaccanMac24, Theorem 3.12]) together with the notations of Theorem 2.5, the character group of P is the direct sum of the character groups of the corresponding
$Q^i$
. More precisely, when P is of the form (2.3), we have
Since pulling back by a Frobenius multiplies the generator of the character group by p, it only remains to compute the character group of
$KP^\nu $
for a simple root
$\nu $
. We claim that
from which it follows that the character group of
${}^{r_\nu -1}KP^\nu $
is freely generated by
$p^{r_\nu }\varpi _\nu $
, for any
$r_\nu \geq 1$
.
Indeed, since
$P^\nu \subset KP^\nu \subset {}_1G P^\nu $
, we obtain the inclusions
Because there are no intermediate sublattices, one of the two inclusions must be strict. Suppose, for contradiction, that
$\varpi _\nu $
is defined on
$KP^\nu $
. Then it is also defined on the restriction to
$KP^\nu \cap G_\gamma $
, where
$\gamma $
is a short root containing
$\nu $
in its support with multiplicity one (for instance, the sum of all simple roots). This intersection is
Since the multiplicity of
$\nu $
in
$\gamma $
is
$1$
, we have
$\langle \varpi _\nu , \gamma ^\vee \rangle = 1$
. Thus, the restriction of
$\varpi _\nu $
to
$T \cap G_\gamma $
coincides with the fundamental weight
$\omega $
of
$G_\gamma $
. However,
$X^*(P^\prime )$
is generated by
$p\omega $
, and
$\omega $
itself is not defined on this parabolic. Hence, the restriction of
$\varpi _\nu $
cannot be defined either, a contradiction. We conclude that
$X^*(KP^\nu )$
is freely generated by
$p\varpi _\nu $
.
3 Most Lie subalgebras containing
$\boldsymbol{\mathrm{Lie}(U)}$
are T-stable for
$\boldsymbol{p \geq 3}$
Let G be a reductive group, which we may assume, without loss of generality, to be of the form
$G = C \times G'$
, where C is a torus and
$G' = \prod _{j \in J} G_{(j)}$
is a simply connected semisimple group. Assume that
$p \geq 3$
. In this section, we prove that almost all Lie subalgebras of
$\operatorname {\mathrm {Lie}}(G)$
containing
$\operatorname {\mathrm {Lie}}(U)$
are T-stable (see Propositions 3.8 and 3.10 for precise statements). This will be useful in the proof of Proposition 5.4.
Throughout this section, we denote by
a Chevalley basis of
$\operatorname {\mathrm {Lie}}(G_{(i)})$
, where
$G_{(i)}$
is a simple factor of G. If G is simple, we use the same notation, omitting the index i throughout.
We will need the following bracket relations between elements of such a basis (see [Reference HumphreysHum78, Section 25.2] for details):
-
(i) $[V_\alpha , V_\beta ] = 0$
for all
$\alpha , \beta \in \Delta $
; -
(ii) $[X_{-\alpha }, X_\alpha ] = V_\alpha $
for all
$\alpha \in \Delta $
; -
(iii) $[V_\alpha , X_\gamma ] = \gamma (V_\alpha ) X_\gamma $
; -
(iv) $[X_\gamma , X_\delta ] = 0$
if
$\gamma + \delta $
is not a root; -
(v) $[X_\gamma , X_\delta ] = \mathcal {N}_{\gamma ,\delta } X_{\gamma +\delta }$
if
$\gamma + \delta $
is a root, in which case
$\gamma - (\mathcal {N}_{\gamma ,\delta } - 1)\delta $
is also a root, while
$\gamma - \mathcal {N}_{\gamma ,\delta } \delta $
is not.
Note that the structure constants
$\mathcal {N}_{\gamma ,\delta } \in \{\pm 1, \pm 2, \pm 3\}$
satisfy
$\mathcal {N}_{\gamma ,\delta } = -\mathcal {N}_{\delta ,\gamma }$
. Moreover, in the simply-laced case, we have
$\mathcal {N}_{\gamma ,\delta } \in \{\pm 1\}$
. Note also that, by restricting to the
$\mathrm {SL}_2$
copy generated by a fixed root
$\gamma $
, the above relations imply:
-
(vi) $[[X_{-\gamma }, X_\gamma ], X_\gamma ] = 2X_\gamma $
.
Remark 3.1 Let G be a simple group over a field of characteristic
$p \geq 3$
, not of type
$F_4$
or
$G_2$
. Fix a Lie subalgebra
$\mathfrak {h} \subset \operatorname {\mathrm {Lie}}(G)$
. Then, for any positive root
$\gamma \in \Phi ^+$
, if
$X_{-\alpha } \in \mathfrak {h}$
for every
$\alpha \in \text {Supp}(\gamma )$
, it follows that
$X_{-\gamma } \in \mathfrak {h}$
as well. This is due to the fact that the relevant structure constants
$\mathcal {N}_{\gamma ,\delta }$
lie in
$\{\pm 1, \pm 2\}$
, and hence are nonzero in characteristic
$p \geq 3$
. For groups of type
$F_4$
or
$G_2$
over a field of characteristic
$p \geq 5$
, the same conclusion holds. Note, however, that these root systems have structure constants equal to
$\pm 3$
, which explains the restriction on the characteristic.
Remark 3.2 We follow the root system conventions of [Reference BourbakiBou68].
-
• For $F_4$
: A basis is given by
$\{\alpha _1, \alpha _2, \alpha _3, \alpha _4\}$
, where
$\alpha _1$
and
$\alpha _2$
are long roots, and
$\alpha _3$
and
$\alpha _4$
are short roots. 
-
• For $G_2$
: A basis is given by
$\{\alpha _1, \alpha _2\}$
, where
$\alpha _1$
is the short root and
$\alpha _2$
is the long root.

Lemma 3.3 Let G be a simple group of type
$F_4$
over a field of characteristic
$p \geq 3$
. Let
$\mathfrak {h}$
be a Lie subalgebra of
$\operatorname {\mathrm {Lie}}(G)$
containing
$\operatorname {\mathrm {Lie}}(U)$
. Then, for any positive root
$\gamma $
, if
$X_{-\alpha } \in \mathfrak {h}$
for every
$\alpha \in \operatorname {\mathrm {Supp}}(\gamma )$
, it follows that
$X_{-\gamma } \in \mathfrak {h}$
.
Proof If
$\gamma $
is simple, there is nothing to prove. If
$\operatorname {\mathrm {Supp}}(\gamma ) \subsetneq \Delta $
, then we may restrict to a subsystem of type
$B_3$
(generated by
$\alpha _1, \alpha _2, \alpha _3$
) or
$C_3$
(generated by
$\alpha _2, \alpha _3, \alpha _4$
), where no structure constant is equal to
$\pm 3$
, so the claim follows from Remark 3.1 in these cases.
Thus, it remains to consider the case where
$\operatorname {\mathrm {Supp}}(\gamma ) = \Delta $
. We will show that if
$X_{-\alpha _i} \in \mathfrak {h}$
for all
$i = 1, \dots , 4$
, then all negative root vectors belong to
$\mathfrak {h}$
. From the previous step (restriction to a subsytem of type
$B_3$
), we already know that
$X_{-\alpha _1 - \alpha _2 - \alpha _3} \in \mathfrak {h}$
, which serves as a starting point. There are exactly 10 positive roots to check, and we proceed inductively via brackets:
Remark 3.4 Assume that
$p=3$
and that G is a simple group of type
$G_2$
. Let
$\mathfrak {h}$
be a Lie subalgebra of
$\operatorname {\mathrm {Lie}}(G)$
containing
$\operatorname {\mathrm {Lie}}(U)$
. Let
$\gamma $
be a positive root of
$G_2$
. Then it is not true that
$X_{-\gamma }$
belongs to
$\mathfrak {h}$
if and only if
$X_{-\alpha } \in \mathfrak {h}$
for all
$\alpha \in \operatorname {\mathrm {Supp}}(\gamma )$
. Actually, both implications fail.
-
• Recall that K denotes the kernel of the very special isogeny (see Section 2.2). Consider the parabolic subgroup $H = K B$
. Then, by [Reference MaccanMac24, Proposition 2.20], we have $$\begin{align*}\operatorname{\mathrm{Lie}}(H) = \operatorname{\mathrm{Lie}}(K) + \operatorname{\mathrm{Lie}}(B) = \operatorname{\mathrm{Lie}}(T) \oplus \operatorname{\mathrm{Lie}}(U) \oplus \mathbb{K} X_{-\alpha_1} \oplus \mathbb{K} X_{-\alpha_1-\alpha_2} \oplus \mathbb{K} X_{-2\alpha_1-\alpha_2}. \end{align*}$$In particular, $X_{-2\alpha _1-\alpha _2} \in \operatorname {\mathrm {Lie}}(H)$
, but
$X_{-\alpha _2} \notin \mathfrak {h}$
. Hence, the implication $$\begin{align*}X_{-\gamma} \in \mathfrak{h} \;\;\Rightarrow\;\; X_{-\alpha} \in \mathfrak{h}, \;\; \forall\, \alpha \in \operatorname{\mathrm{Supp}}(\gamma) \end{align*}$$does not hold.
-
• Consider the parabolic subgroup $H' = K P^{\alpha _1}$
: again by [Reference MaccanMac24, Proposition 2.20], its Lie algebra is $$\begin{align*}\operatorname{\mathrm{Lie}}(H') = \operatorname{\mathrm{Lie}}(H) \oplus \mathbb{K} X_{-\alpha_2}. \end{align*}$$Thus, both $X_{-\alpha _1}, X_{-\alpha _2} \in \operatorname {\mathrm {Lie}}(H')$
. However, the highest root
$\gamma = 3\alpha _1 + 2\alpha _2$
does not satisfy
$X_{-\gamma } \in \operatorname {\mathrm {Lie}}(H')$
. This shows that the converse implication $$\begin{align*}\big( X_{-\alpha} \in \mathfrak{h}, \;\;\forall\, \alpha \in \operatorname{\mathrm{Supp}}(\gamma) \big) \;\;\Rightarrow\;\; X_{-\gamma} \in \mathfrak{h} \end{align*}$$is also false.
Lemma 3.5 Let G be a simple group of type
$F_4$
over a field of arbitrary characteristic. For any positive root
$\gamma \in \Phi ^+$
which is not simple, and for any
$i \in \{1,2,3,4\}$
, the weights
$3\gamma - 2\alpha _i$
and
$3\gamma - \alpha _i$
are not roots.
Proof The two cases are analogous, so we only prove that the weight
$3\gamma - 2\alpha _i$
is not a root.
Let
$l(\gamma ) \geq 2$
denote the length of the positive root
$\gamma $
, and fix a simple root
$\alpha _i$
. If
$\alpha _i \notin \text {Supp}(\gamma )$
, then there is nothing to prove, so assume
$\alpha _i \in \text {Supp}(\gamma )$
.
If
$3\gamma - 2\alpha _i$
were a root, its length would be
because the highest root has length
$11$
. We list all positive roots
$\delta $
of these lengths.
Those with
$l(\delta ) = 4$
are exactly:
For any choice of i, none of these roots
$\delta $
satisfies that
$\delta + 2\alpha _i$
has all coefficients divisible by
$3$
. Hence, it is impossible that
$\delta + 2\alpha _i = 3\gamma $
.
The same reasoning applies for the roots
which are, respectively, those of length
$7$
or
$10$
.
Lemma 3.6 For any (non-simple) positive root
$\gamma $
of G, there is always some
$\alpha \in \operatorname {\mathrm {Supp}}(\gamma )$
such that
$\gamma -\alpha $
is still a root.
Proof This fact is classical (see, e.g., [Reference Dimitrov and FioresiDF24, Corollary 1.12(i)]).
Lemma 3.7 Let G be a simple group of type
$F_4$
over a field of characteristic
$p \geq 3$
. Then, for any (non-simple) positive root
$\gamma ,$
there is some simple root
$\alpha \in \operatorname {\mathrm {Supp}}(\gamma )$
such that the structure constant
$\mathcal {N}_{\gamma ,-\alpha }$
does not vanish.
Proof As in the proof of Lemma 3.3, for all the roots
$\gamma $
such that the support of
$\gamma $
is not the full basis of simple roots, then we can restrict to a subgroup of type
$B_3$
or
$C_3$
, where none of the structure constants vanish for
$p\geq 3$
. Thus, we only have to consider the roots
$\gamma _1,\ldots , \gamma _{10}$
listed above, which are exactly those satisfying
$\operatorname {\mathrm {Supp}}(\gamma ) = \Delta $
.
Let us consider the following pairs
$(\gamma _j,\alpha _{i(j)})$
:
Then, by looking at the full list of positive roots in type
$F_4$
, we notice the following: for each
$j= 1,\ldots ,10,$
the weight
$\gamma _j-\alpha _{i(j)}$
is a root, while the weight
$\gamma _j + \alpha _{i(j)}$
is not. By the bracket relation v, this implies exactly that
$\mathcal {N}_{\gamma _j, -\alpha _{i(j)}}$
is equal to
$\pm 1$
.
Proposition 3.8 Assume that
$p \geq 3$
. Let
$\mathfrak {h} \subset \operatorname {\mathrm {Lie}}(G)$
be a Lie subalgebra containing
$\operatorname {\mathrm {Lie}}(U)$
. If
$p \geq 5$
, or if
$p = 3$
and G does not contain any simple factor of type
$G_2$
, then
$\mathfrak {h}$
is T-stable.
Proof Consider
for some
$a_\gamma ^j \in \mathbb {K}$
and
$W \in \operatorname {\mathrm {Lie}}(T)$
. Fix a simple factor
$G_{(i)}$
, and define the support of X with respect to this factor as
From now on, we drop the index i and denote the Chevalley basis vectors for
$G_{(i)}$
by
$X_\delta $
and
$V_\beta $
. Assume that either
$p \geq 5$
, or that
$G_{(i)}$
is not of type
$G_2$
. We aim to show that
$a_\gamma ^i \neq 0$
implies
$X_{-\gamma }^i \in \mathfrak {h}$
. In fact, we will prove a stronger statement: if
$a_\gamma ^i \neq 0$
, then
$X_{-\alpha }^i \in \mathfrak {h}$
for all
$\alpha \in \operatorname {\mathrm {Supp}}(X, i)$
. This suffices, since either
$G_{(i)}$
is of type
$F_4$
, in which case we may invoke Lemma 3.3, or we appeal to Remark 3.1.
Let us prove this claim by induction on the length of X with respect to
$G_{(i)}$
:
where
$l(\gamma ) = \sum _{\beta \in \Delta _i} n_\beta $
if
$\gamma = \sum _{\beta } n_\beta \beta $
.
Base case:
$l = 1$
. Then X takes the form
Note that, for all
$\beta \in \Delta $
, the bracket
$[X, X_\beta ] \in \mathfrak {h}$
because
$\operatorname {\mathrm {Lie}}(U) \subset \mathfrak {h}$
. Hence,
Now consider the linear map
whose image lies in
$\mathfrak {h}$
. Its matrix is the Cartan matrix
$(\alpha (V_\beta ))_{\alpha ,\beta \in \operatorname {\mathrm {Supp}}(X,i)}$
, which is invertible. Hence,
$X_{-\alpha } \in \mathfrak {h}$
for all
$\alpha \in \operatorname {\mathrm {Supp}}(X,i)$
.
Induction step: Assume the claim holds for all vectors Y with
$l(Y) < l$
. Let X be as in (3.1), with
$l(X) = l \geq 2$
. Pick
$\alpha _0 \in \operatorname {\mathrm {Supp}}(\gamma _0) \subset \operatorname {\mathrm {Supp}}(X, i)$
such that
$\gamma _0 \in \Phi _i^+$
,
$a_{\gamma _0} \neq 0$
, and
$l(\gamma _0) = l(X) = l$
. Our goal is to show that
$X_{-\alpha _0} \in \mathfrak {h}$
(then one easily concludes by induction).
Case 1: Suppose that
$\delta _0 := \gamma _0 - \alpha _0 \in \Phi ^+$
. Then:
where
$W_0 := a_{\delta _0}[X_{-\delta _0}, X_{\delta _0}] \in \operatorname {\mathrm {Lie}}(T)$
. Moreover, for any
$\gamma $
such that
$\gamma - \delta _0 \in \Phi _i^+$
, we have
$l(\gamma - \delta _0) < l(\gamma )$
. In particular, we may replace the vector X from (3.1) with the vector
which satisfies
$l(Y) < l(X) = l$
. By our assumption on p, or by Lemma 3.5 (for
$G_{(i)}$
of type
$F_4$
and
$p=3$
), we have
$\mathcal {N}_{-\gamma _0,\delta _0} \neq 0$
. Hence, we conclude by induction that
$X_{-\alpha _0} \in \mathfrak {h}$
.
Case 2: If the above does not hold directly for
$\alpha _0$
, then there exists another simple root
$\alpha _1 \in \operatorname {\mathrm {Supp}}(\gamma _0)$
with
$\alpha _1 \neq \alpha _0$
, such that
$\delta _1 := \gamma _0 - \alpha _1 \in \Phi ^+$
and
$\mathcal {N}_{\gamma _0, -\alpha _1} \neq 0$
(see Lemmas 3.6 and 3.7). Consider now:
As in the previous case, we replace the vector X from (3.1) with the new vector
which satisfies
$l(Y') < l(X) = l$
and still has
$\alpha _0$
in its support; indeed,
$\alpha _0 \in \operatorname {\mathrm {Supp}}(\delta _1) \subset \operatorname {\mathrm {Supp}}(Y', i)$
. By induction, we conclude that
$X_{-\alpha _0} \in \mathfrak {h}$
. This concludes the proof of the proposition.
Example 3.9 Assume that
$p=3$
and that G is simple of type
$G_2$
. Recall that we denote as K the kernel of the very special isogeny. Let us denote as
$\alpha _1$
the short simple root and as
$\alpha _2$
the long one. Fix a nonzero scalar
$\lambda \in \mathbb {K}^\times $
and define
Consider the following linear subspace of
$\operatorname {\mathrm {Lie}}(G)$
:
We will show that
$\mathfrak {h}_\lambda $
is a restricted Lie subalgebra of
$\operatorname {\mathrm {Lie}}(G)$
that is not T-stable.
By inspecting the structure constants, we find that
$\mathcal {N}_{-2\alpha _1-\alpha _2,-\alpha _1}$
,
$\mathcal {N}_{-\alpha _1-\alpha _2,\alpha _1}$
, and similar terms vanish (recall that
$p=3$
). Furthermore, a direct computation shows that both
$V_{\alpha _1}$
and
$V_{\alpha _2}$
stabilize
$X_\lambda $
. This confirms that
$\mathfrak {h}_\lambda $
is closed under the Lie bracket, that is, it is a Lie subalgebra of
$\operatorname {\mathrm {Lie}}(G)$
. Also, it is clear from the definition of
$\mathfrak {h}_\lambda $
that this Lie subalgebra is not T-stable, since it does not contain the subspace
$\mathbb {K} X_{-\alpha _2} \oplus \mathbb {K} X_{-3\alpha _1-\alpha _2}$
.
Next, we check that
$\mathfrak {h}_\lambda $
is stable under the p-mapping. Since
$\operatorname {\mathrm {Lie}} (KB)$
is already known to be a restricted Lie subalgebra, it suffices to compute
$X_\lambda ^{[p]} = X_\lambda ^{[3]}$
. By properties of the p-mapping, we have
which implies that
$X_\lambda ^{[3]}$
lies in the center of
$\operatorname {\mathrm {Lie}}(G)$
. Since this center is trivial, we conclude that
$X_\lambda ^{[3]} = 0$
. Therefore,
$\mathfrak {h}_\lambda $
is indeed a restricted Lie subalgebra of
$\operatorname {\mathrm {Lie}}(G)$
.
As mentioned earlier, our main goal in this section is to prove that almost all Lie subalgebras
$\mathfrak {h}$
of
$\operatorname {\mathrm {Lie}}(G)$
containing
$\operatorname {\mathrm {Lie}}(U)$
are T-stable. We have already treated the case where
$p \ge 5$
, or
$p = 3$
and G has no simple factor of type
$G_2$
, in Proposition 3.8. It remains to consider the case where
$p = 3$
and G has at least one factor of type
$G_2$
. We will show that in this case either
$\mathfrak {h}$
is T-stable, or the component corresponding to the
$G_2$
factor is as in Example 3.9. Thus, even if it is not true in general that all Lie subalgebras
$\mathfrak {h}$
of
$\operatorname {\mathrm {Lie}}(G)$
containing
$\operatorname {\mathrm {Lie}}(U)$
are T-stable, the exceptions are well understood, and this will be essential in the proof of Proposition 5.4.
Proposition 3.10 Assume that
$p = 3$
. Let
$\mathfrak {h} \subset \operatorname {\mathrm {Lie}}(G)$
be a Lie subalgebra containing
$\operatorname {\mathrm {Lie}}(U)$
. Suppose that
$G = C \times G_{(1)} \times \cdots \times G_{(r)}$
contains at least one simple factor of type
$G_2$
. Then either
$\mathfrak {h}$
is T-stable, or there exists an index i such that
$G_{(i)} \simeq G_2$
and
$\mathfrak {h} \cap \operatorname {\mathrm {Lie}}(G_{(i)})=\mathfrak {h}_{\lambda }$
for some
$\lambda \in \mathbb {K}^\times $
(see Example 3.9 for the definition of
$\mathfrak {h}_{\lambda }$
).
Before moving on to the proof, recall that the Cartan matrix of
$G_2$
gives
Also, for the structure constants of
$G_2$
, we use the table given by [Reference KolesnikovKol23, Table 1], with
$\epsilon _1=\epsilon _2=\epsilon _3=\epsilon _4=1$
(Bourbaki’s convention).
Proof If there exists an index i such that
$G_{(i)} \simeq G_2$
and
$\mathfrak {h} \cap \operatorname {\mathrm {Lie}}(G_{(i)}) = \mathfrak {h}_{\lambda }$
for some
$\lambda \in \mathbb {K}^\times $
, then it is clear that the Lie subalgebra
$\mathfrak {h} \subset \operatorname {\mathrm {Lie}}(G)$
is not T-stable. Suppose, on the contrary, that this condition does not hold. We shall then prove that
$\mathfrak {h}$
is indeed T-stable.
We fix an index i. For simplicity of notation, we denote the vectors of the Chevalley basis of
$G_{(i)}$
simply by
$X_\gamma $
and
$V_\alpha $
, instead of
$X_\gamma ^i$
and
$V_\alpha ^i$
. Consider a vector
$X \in \mathfrak {h}$
of the form
where
$X_j \in \operatorname {\mathrm {Lie}}(U^-_j)$
for all
$j \neq i$
, and
$W \in \operatorname {\mathrm {Lie}}(T)$
. If
$G_{(i)}$
is not of type
$G_2$
, then, as in the proof of Proposition 3.8, we deduce that
Assume therefore that
$G_{(i)} \simeq G_2$
. In this case, we shall show that either (once again), for every
$\gamma \in \Phi ^+_i$
,
$a_\gamma \neq 0$
implies
$X_{-\gamma } \in \mathfrak {h}$
, or else
which in turn yields the desired result. Recall that if
$G_{(i)}$
is of type
$G_2$
, then
Hence, we may write X in the form
where at least one coefficient
$a,\dots ,f \in \mathbb {K}$
is nonzero. We now distinguish cases according to
where
$l(\gamma )$
denotes the length of the root
$\gamma $
. Note that the case
$l=5$
will be considered before the case
$l=4$
, since only in the latter does the Lie subalgebra
$\mathfrak {h}_\lambda $
appear.
$\bullet $
Case
$l=1$
. Consider
Assume first that
$a \neq 0$
. Then
Using again the hypothesis that
$\operatorname {\mathrm {Lie}}(U) \subset \mathfrak {h}$
, we deduce that
$V_{\alpha _1} \in \mathfrak {h}$
, and hence also
If moreover
$b=0$
, the claim follows. Otherwise, if
$b \neq 0$
, we compute
which implies
$V_{\alpha _2} \in \mathfrak {h}$
, and finally
Thus, in either case,
$X_{-\alpha _1}, X_{-\alpha _2} \in \mathfrak {h}$
. If instead
$a=0$
and
$b \neq 0$
, then
and we proceed analogously to conclude that
$X_{-\alpha _2} \in \mathfrak {h}$
.
$\bullet $
Case
$l=2$
. Up to rescaling, we may assume that
$c=1$
, so that
By the result of Case
$l=1$
, it suffices to show that
$X_{-\alpha _1-\alpha _2} \in \mathfrak {h}$
. We first take brackets with
$X_{\alpha _2}$
, and then with
$X_{\alpha _1}$
:
Since
$\operatorname {\mathrm {Lie}}(U) \subset \mathfrak {h}$
by assumption, it follows that
$V_{\alpha _1} \in \mathfrak {h}$
. Now consider
If
$a=0$
, then
$Y = -X_{-\alpha _1-\alpha _2} \in \mathfrak {h}$
, and we are done. If instead
$a \neq 0$
, then
which implies
Thus, in either case,
$X_{-\alpha _1-\alpha _2} \in \mathfrak {h}$
, as required.
$\bullet $
Case
$l=3$
. Up to rescaling, let us assume
$d=1$
and consider
Thanks to the previous cases, it suffices to show that
$X_{-2\alpha _1-\alpha _2} \in \mathfrak {h}$
. From now on, set
Taking successive brackets of X first with
$X_{\alpha _1+\alpha _2}$
and then with
$X_{\alpha _1}$
, we obtain
We deduce that
$V_{\alpha _1} \in \mathfrak {h}$
. Consequently,
Now, applying to the vector
$Y'$
one of the previous steps (where the length is at most two), we conclude that
Finally,
which completes the proof.
$\bullet $
Case
$l=5$
. Up to rescaling, let us assume
$f=1$
. In this case, we claim that
First, we have
which, by the argument in the case
$l=3$
, implies that
$X_{-2\alpha _1-\alpha _2} \in \mathfrak h$
. Next,
which, using the proof for
$l=2$
, implies that
$X_{-\alpha _1-\alpha _2} \in \mathfrak h$
. Furthermore,
so
$X_{-\alpha _1} \in \mathfrak h$
. We are therefore left with
Then,
which yields
$V_{\alpha _2} \in \mathfrak {h}$
. Moreover,
which implies that
$X_{-3\alpha _1-\alpha _2} \in \mathfrak {h}$
. Next,
so
$X_{-\alpha _2} \in \mathfrak {h}$
. Finally,
and thus we conclude that
$\mathfrak {h} = \operatorname {\mathrm {Lie}}(G_{(i)})$
, as claimed.
$\bullet $
Case
$l=4$
. Up to rescaling, let us assume that
$e = 1$
(and
$f=0$
since
$l=4$
) and consider
We aim to show that either
$\mathfrak {h}$
is T-stable, or there exists
$\lambda \in \mathbb {K}^\times $
such that
$\mathfrak {h} \cap \operatorname {\mathrm {Lie}}(G_{(i)}) = \mathfrak {h}_\lambda $
.
Assume first that
$d \neq 0$
. Then
which implies
$V_{\alpha _1} \in \mathfrak {h}$
(since
$d \neq 0$
). Consequently,
By the argument in the case
$l=3$
, we can conclude that
$a X_{-\alpha _1}, c X_{-\alpha _1-\alpha _2}, X_{-2\alpha _1-\alpha _2} \in \mathfrak {h}$
. Moreover,
We are therefore left with
Then,
which yields
$V_{\alpha _2} \in \mathfrak {h}$
. In particular,
$\mathfrak {h} \cap \operatorname {\mathrm {Lie}}(G_{(i)})$
contains
$\operatorname {\mathrm {Lie}}(T_{(i)})$
. It follows that
If
$b=0$
, then we are done. Otherwise, setting
$\lambda = b \in \mathbb {K}^\times $
, we obtain that
(Notice that
$X_\lambda $
is exactly the vector considered in Example 3.9.) We deduce that
$\mathfrak {h} \cap \operatorname {\mathrm {Lie}}(G_{(i)})$
contains
$\mathfrak {h}_\lambda $
. If the inclusion is strict, then either
$\mathfrak {h}$
contains a length-five vector, which implies (by the case
$l=5$
) that
$\mathfrak {h} \cap \operatorname {\mathrm {Lie}}(G_{(i)})= \operatorname {\mathrm {Lie}}(G_{(i)})$
, or
In this last case, taking the bracket of
$X_{-\alpha _2}$
and
$X_{-3\alpha _1-\alpha _2}$
again yields
$\mathfrak {h} \cap \operatorname {\mathrm {Lie}}(G_{(i)})= \operatorname {\mathrm {Lie}}(G_{(i)})$
.
Now, returning to the beginning, assume instead that
$d=0$
. Taking the bracket of X with
$X_{2\alpha _1+\alpha _2}$
again shows that
$X_{-\alpha _1}$
, and hence
$V_{\alpha _1}$
, lie in
$\mathfrak {h}$
. Proceeding as above, we deduce that
$\mathfrak {h}$
also contains
$X_{-2\alpha _1-\alpha _2}$
and
$X_{-\alpha _1-\alpha _2}$
, and the remainder of the proof is analogous to the argument given above (when
$Y'$
appears). This completes the proof of the proposition.
4 Strongly horospherical subgroups and classification for
$\boldsymbol{p \geq 3}$
Let G be a connected reductive group. In this section, we establish some basic properties of strongly horospherical subgroups of G, and then provide a complete classification in the case
$p \geq 3$
(Corollary 4.9).
4.1 Structure of the quotient group
Let H be a strongly horospherical subgroup of G. Over a field of characteristic
$0$
, the quotient group
$N_G(H)/H$
is always a torus. We will see that this is no longer necessarily the case over a field of characteristic
$2$
.
Lemma 4.1 Let H be a strongly horospherical subgroup of G with normalizer P. Let
$\gamma $
be a positive root of G. Let R be a
$\mathbb {K}$
-algebra,
$r \in \mathbf {N} \cup \{\infty \}$
and consider some
$x \in \boldsymbol {\alpha }_{p^r}(R)$
such that
$u_{-\gamma } (x) \in P(R)$
. Then we have that
$u_{-\gamma }(x^2) \in H(R)$
.
Proof Since the derived subgroup of G is simply-connected, it is enough to work inside of the copy of
$\operatorname {\mathrm {SL}}_2$
generated by
$U_\gamma $
and
$U_{-\gamma }$
, so we can assume that
$G=\operatorname {\mathrm {SL}}_2$
and that
$\gamma $
is the only positive root. Let
$t \in R^\times =\mathbf {G}_m(R)$
, then by the assumption that
$u_{-\gamma }(x) \in P(R)$
, we have that
Since this is true for arbitrary t (as H is assumed to be strongly horospherical), we can take the limit for
$t \to 0$
. (More specifically, the homomorphism
$\mathbf {G}_m \to H$
sending t to the above matrix can be extended to a scheme morphism
$\mathbf {A}^1 \to H$
, the value at
$0$
is what we call its limit: for more details, see [Reference MilneMil17, Section 13.b].) This yields that
$u_{-\gamma } (-x^2) \in H(R)$
and concludes the proof.
Lemma 4.2 Let H be a strongly horospherical subgroup of G with normalizer P, and let
$\gamma $
be a positive root of G. Then
Proof The inequality
$\operatorname {\mathrm {ht}}(H \cap U_{-\gamma }) \leq \operatorname {\mathrm {ht}}(P \cap U_{-\gamma })$
is clear. To prove the reverse inequality, let
$r \in \mathbf {N} \cup \{\infty \}$
denote the height of
$P \cap U_{-\gamma }$
. Set
$R=\mathbb {K}[y]/(y^{p^r})$
, and let
$x \in \boldsymbol {\alpha }_{p^r}(R)\simeq (P \cap U_{-\gamma })(R)$
. Since
$u_{-\gamma }(x)\in (P \cap U_{-\gamma })(R)$
, Lemma 4.1 implies that
$u_{-\gamma }(x^2)\in (H \cap U_{-\gamma })(R)$
. Suppose that the height of
$H \cap U_{-\gamma }$
is strictly smaller than r. Then
In particular,
$y^{2p^{r-1}}=0$
in R. If
$p\ge 3$
, this is impossible, since the nilpotence index of y in R is
$p^r$
. Therefore,
$H \cap U_{-\gamma }$
also has height r. If
$p=2$
, the above argument only yields
$\operatorname {\mathrm {ht}}(P \cap U_{-\gamma }) \le \operatorname {\mathrm {ht}}(H \cap U_{-\gamma })+1$
.
Remark 4.3 Assume that
$p \geq 3$
. Let H be a strongly horospherical subgroup of G. By Lemma 4.2, we have
$P = N_G(H) = HT$
. In particular, if H is smooth, then P is smooth as well.
Proposition 4.4 Let H be a strongly horospherical subgroup of G with normalizer P. The following hold:
-
(1) If $p \geq 3$
, then
$\mathbb {T}:=P/H$
is a torus. -
(2) If $p=2$
, then
$P/H \simeq \mathbb {T} \ltimes V$
, where
$\mathbb {T}:=(P/H)_{\mathrm {red}}$
is a torus and V is an infinitesimal unipotent group of height at most
$1$
.
Proof 1: Assume first that
$p \geq 3$
. Then
$P/H$
is a torus since
$H \cap U=P \cap U=U$
and
$H \cap U_{-}=P \cap U_{-}$
by Lemma 4.2. 2: Assume now that
$p=2$
. Then, again by Lemma 4.2,
$\mathbb {T}:=(P/H)_{\mathrm {red}}$
is a torus and there is a split exact sequence
where V is an infinitesimal unipotent group of height at most
$1$
.
Remark 4.5 Let H be a strongly horospherical subgroup with normalizer P. If P is smooth, then
$P/H$
is smooth. In particular,
$P/H$
is a torus.
Example 4.6 Assume
$p=2$
. Let
$G=\operatorname {\mathrm {SL}}_2$
and
Then H is a strongly horospherical subgroup of G,
$P=N_G(H)=F^{-1}(B)$
, and
$\operatorname {\mathrm {ht}}(P \cap U_{-\gamma }) = \operatorname {\mathrm {ht}}(H \cap U_{-\gamma })+1=2$
. In particular,
$P/H \simeq \mathbf {G}_m \ltimes \alpha _2$
is not a torus.
4.2 Classification for
$\boldsymbol{p \geq 3}$
By assuming that the characteristic of the base field
$\mathbb {K}$
is not equal to
$2$
, we get a classification result for strongly horospherical subgroups of G that is analogous to the well-known one in characteristic
$0$
: all such subgroups are obtained by taking kernels of characters on a parabolic subgroup of G.
Proposition 4.7 Assume that
$p \geq 3$
.
-
(1) Let H be a strongly horospherical subgroup of G with normalizer P. Then $H=\bigcap _{\chi \in M} \ker (\chi _i)$
, where M is a sublattice of the character lattice
$X^\ast (P)$
. -
(2) Conversely, given a parabolic subgroup scheme P of G and a sublattice M of the character lattice $X^\ast (P)$
, the scheme-theoretic intersection
$H:=\bigcap _{\chi \in M} \ker (\chi _i)$
is a strongly horospherical subgroup of G such that
$N_G(H)=P$
.
Proof 1: By Proposition 4.4, the quotient
$\mathbb {T}=P/H$
is a torus. Fix an isomorphism of algebraic groups
$\mathbb {T} \simeq \mathbf {G}_m^r$
, with
$r \geq 0$
, and let
$\chi _i \colon P \to \mathbf {G}_m$
denote the element of the character lattice
$X^\ast (P)$
obtained by composing the quotient morphism
$P \to \mathbb {T} \simeq \mathbf {G}_m^r$
with the i-th projection
$\mathbf {G}_m^r \to \mathbf {G}_m$
. Let M be the rank-r sublattice of
$X^\ast (P)$
generated by the
$\chi _i$
. Then
$H=\bigcap _{\chi \in M} \ker (\chi )$
. 2: Let
$ M $
be a sublattice of the character lattice
$ X^\ast (P) $
, and define
$ H := \bigcap _{\chi \in M} \ker (\chi ) $
. For every
$ \chi \in X^\ast (P) $
, we have
$ U \subset \ker (\chi ) $
, which implies that
$ H $
is horospherical. Furthermore, it is clear that
$ P \subset N_G(H) $
. Hence,
$ Q := N_G(H) $
is a parabolic subgroup of
$ G $
. Now, for every positive root
$ \gamma $
of
$ G $
, consider
$ U_{-\gamma } $
. We have
where the first equality follows from Lemma 4.2. Therefore,
$ Q \subset P $
. It follows that
$ N_G(H) = P $
.
Remark 4.8 Assume that the base field has characteristic
$p=2$
. Let H be a strongly horospherical subgroup with normalizer P. Then it may happen that
$HT \subsetneq P$
, yet the quotient
$HT/H$
is still a torus:
Thus, H is always obtained as the intersection of the kernels of characters of the parabolic subgroup
$HT$
, whereas its normalizer
$P=N_G(H)$
can be larger, the excess being measured precisely by the unipotent infinitesimal group V defined in Proposition 4.4(2).
Let
$\mathcal {P}$
denote the set of functions
$\Phi ^+ \to \mathbb {N} \cup \{\infty \}$
associated with parabolic subgroups of G (see Section 2.1). By Theorem 2.2, there is a one-to-one correspondence between the set of conjugacy classes of parabolic subgroups of G and the set
$\mathcal {P}$
. This parameterization can be naturally extended to strongly horospherical subgroups of G.
Corollary 4.9 Assume that
$p \geq 3$
. There is a one-to-one correspondence between the set of conjugacy classes of strongly horospherical subgroups of G and the set of pairs
$(\varphi , M)$
, where
$\varphi \in \mathcal {P}$
and M is a sublattice of
$X^\ast (P_\varphi )$
, with
$P_\varphi $
the standard parabolic subgroup of G associated with the function
$\varphi $
.
Proof Given a standard parabolic subgroup
$P_\varphi $
of G and a sublattice
$M \subset X^\ast (P_\varphi )$
, we define a strongly horospherical subgroup
$H \subset G$
as the scheme-theoretic intersection
We then map the pair
$(\varphi ,M)$
to the conjugacy class of H.
Conversely, given a conjugacy class of strongly horospherical subgroups of G, we fix the representative H containing the unipotent radical U of B. We define the standard parabolic subgroup
$P := N_G(H)$
. Then there exists a unique element
$\varphi \in \mathcal {P}$
such that
$P = P_\varphi $
. We define M as the sublattice of
$X^\ast (P)$
consisting of all characters
$\chi \in X^\ast (P)$
that vanish on H, that is, those that factor through the quotient torus
$\mathbb {T} = P/H$
.
It is then straightforward, using Proposition 4.7, to verify that these two constructions are well-defined and inverses of each other.
Remark 4.10 Assume that
$p \geq 3$
. The strongly horospherical subgroup H, corresponding to a pair
$(\varphi ,M)$
as above, is smooth if and only if
$P_\varphi $
is smooth and the quotient lattice
$X^\ast (T)/M$
has no p-torsion.
Example 4.11 It is possible for a strongly horospherical subgroup
$H \subset G$
to be non-smooth while P is smooth. For instance, consider the case where
$G = \operatorname {\mathrm {SL}}_2$
,
$q=p^t \geq 3$
, and define
(This subgroup corresponds to
$\mathcal {A}(q,\infty )$
in [Reference KnopKno95, Lemma 3.1].) Then, H is a strongly horospherical non-smooth subgroup of G while
$P = N_G(H) = B$
is smooth. In this case, the quotient lattice is
$X^\ast (T)/M \simeq \mathbf {Z}/q\mathbf {Z}$
.
5 Horospherical subgroups are strongly horospherical when
$\boldsymbol{p \geq 3}$
Let G be a reductive group, which we may assume, without loss of generality, to be of the form
$G = C \times G'$
, where C is a torus and
$G' = \prod _{j \in J} G_{(j)}$
is a simply connected semisimple group. This section is dedicated to proving Theorem 5.6, that is, to proving that horospherical subgroups of G are strongly horospherical when
$p \geq 3$
.
5.1 Subgroups of height at most one
Let us recall a fundamental structure theorem describing finite subgroup schemes of height at most one. It will be useful in the proofs of Proposition 5.4 and Theorem 5.6.
Theorem 5.1 (cf. [Reference Demazure and GabrielDG70, II, Section 7, n
${}^{\circ }$
4])
Let G be a linear algebraic group over
$\mathbb {K}$
. Then:
-
(1) The map $J \mapsto \operatorname {\mathrm {Lie}}(J)$
induces a bijection between the set of subgroup schemes of
${}_1G$
and the set of restricted Lie subalgebras of
$\operatorname {\mathrm {Lie}}(G)$
. Under this correspondence, normal subgroup schemes correspond to restricted Lie ideals. -
(2) Let J and $J'$
be subgroup schemes of
${}_1G$
. Then
$J \subset J'$
if and only if
$\operatorname {\mathrm {Lie}}(J) \subset \operatorname {\mathrm {Lie}}(J')$
. -
(3) If $f_1$
and
$f_2$
are homomorphisms with source
${}_1G$
, then
$f_1 = f_2$
if and only if
$Df_{1,e} = Df_{2,e}$
. -
(4) If J is a subgroup scheme of ${}_1G$
, then there is an equality of restricted Lie algebras $$\begin{align*}\operatorname{\mathrm{Lie}}(N_G(J)) = N_{\operatorname{\mathrm{Lie}}(G)}(\operatorname{\mathrm{Lie}}(J)), \end{align*}$$where $N_G(J)$
denotes the normalizer of J in G, and
$N_{\operatorname {\mathrm {Lie}}(G)}(\operatorname {\mathrm {Lie}}(J))$
the normalizer of the Lie subalgebra
$\operatorname {\mathrm {Lie}}(J)$
in
$\operatorname {\mathrm {Lie}}(G)$
.
-
(5) Let V be a finite-dimensional representation of G. Then a vector subspace of V is ${}_1G$
-stable if and only if it is
$\operatorname {\mathrm {Lie}}(G)$
-invariant.
5.2 Warm-up: The
$\boldsymbol{\operatorname {\mathrm {SL}}_2}$
case
We now consider the simplest case: all subgroup of
$\operatorname {\mathrm {SL}}_2$
have been classified by Knop in [Reference KnopKno95]. Out of this classification, we easily deduce the classification of the horospherical subgroups of
$\operatorname {\mathrm {SL}}_2$
.
Theorem 5.2 (See [Reference KnopKno95, Theorem 5.1 and Lemma 3.1])
Assume that
$p \geq 2$
. Let H be a horospherical subgroup of
$G = \operatorname {\mathrm {SL}}_2$
. Then H is conjugate to the pullback by an iterated Frobenius of one of the following:
-
• G, or B, or $\boldsymbol {\mu }_n \ltimes U$
for some
$n \geq 1$
, in which case the normalizer of the group contains B. -
• If $p = 2$
, the subgroup
$\mathcal {B}(\infty )$
(see Example 1.1), in which case the group coincides with its normalizer.
The next observation will be useful in the proof of Theorem 5.6.
Corollary 5.3 Assume that
$p \geq 3$
. Then every horospherical subgroup of
$\operatorname {\mathrm {SL}}_2$
is strongly horospherical.
5.3 The smooth case
In this section, we prove Theorem 5.6, first under the additional assumption that H is smooth and connected (Proposition 5.4 2), and then under the weaker assumption that H is merely smooth (Corollary 5.5).
Proposition 5.4 Assume that
$p \geq 3$
. Let H be a horospherical subgroup of G. Then:
-
(1) The Lie algebra $\operatorname {\mathrm {Lie}}(H)$
is T-stable (for the restricted adjoint action
$T \curvearrowright \operatorname {\mathrm {Lie}}(G)$
). -
(2) If H is furthermore smooth and connected, then H is strongly horospherical.
Proof If H is a connected smooth horospherical subgroup, then it is strongly horospherical if and only if
$\operatorname {\mathrm {Lie}}(H)$
is T-stable. Hence, it suffices to prove (1).
If
$p \geq 5$
, or if G does not contain any simple factor of type
$G_2$
, then the result follows from Proposition 3.8. Thus, we may assume that
$p = 3$
and that G contains at least one simple factor of type
$G_2$
; fix such a factor and denote it by
$G_{(i)}$
.
By Proposition 3.10, it is enough to show that
$\operatorname {\mathrm {Lie}}(H) \cap \operatorname {\mathrm {Lie}}(U^-_i)$
cannot be of the form
$\mathfrak {h}_\lambda \cap \operatorname {\mathrm {Lie}} (U^-_i)$
for any
$\lambda \in \mathbb {K}^\times $
(see Example 3.9 for the definition of
$\mathfrak {h}_\lambda $
). Assume, for contradiction, that this is the case, that is, that
$\operatorname {\mathrm {Lie}}(H) \cap \operatorname {\mathrm {Lie}} (U^-_i)= \mathfrak {h}_\lambda \cap \operatorname {\mathrm {Lie}} (U^-_i)$
for some
$\lambda \in \mathbb {K}^\times $
.
The kernel
$K_{G_{(i)}}$
of the very special isogeny of
$G_{(i)}$
is a subgroup of height 1 whose Lie algebra is contained in
$\mathfrak {h}_\lambda \subset \operatorname {\mathrm {Lie}}(H)$
. Hence, by Theorem 5.1(2), the kernel
$K_{G_{(i)}}$
is contained in H. Now consider the quotient group:
where
$\overline {G_{(i)}}$
is the image of
$G_{(i)}$
under the very special isogeny and is again a simple group of type
$G_2$
. By construction,
$\overline {H}$
is a horospherical subgroup. Then by Proposition 3.10 applied to
$\operatorname {\mathrm {Lie}}(\overline {H})$
, we again have two possibilities:
-
• either $\operatorname {\mathrm {Lie}}(\overline {H}) \cap \operatorname {\mathrm {Lie}}(\overline {U}^-_i)$
is
$\overline {T}$
-stable; -
• or there exists $\mu \in \mathbb {K}^\times $
such that
$\operatorname {\mathrm {Lie}}(\overline {H}) \cap \operatorname {\mathrm {Lie}}(\overline {U}^-_i) = \overline {\mathfrak {h}}_\mu \cap \operatorname {\mathrm {Lie}}(\overline {U}^-_i)$
.
In the first case, since
$\operatorname {\mathrm {Lie}}(\overline {H}) \cap \operatorname {\mathrm {Lie}}(\overline {U}^-_i)$
is
$\overline {T}$
-stable, pulling back by the very special isogeny gives that
$\operatorname {\mathrm {Lie}}(H) \cap \operatorname {\mathrm {Lie}}(U^-_i)$
is also T-stable, contradicting the assumption that
$\operatorname {\mathrm {Lie}}(H) \cap \operatorname {\mathrm {Lie}}(U^-_i) = \mathfrak {h}_\lambda \cap \operatorname {\mathrm {Lie}}(U^-_i)$
.
In the second case, we observe that the kernel
$K_{\overline {G_{(i)}}}$
of the very special isogeny of
$\overline {G_{(i)}}$
is then contained in
$\overline {H}$
:
Recall that the composition of the two successive very special isogenies equals the Frobenius morphism (see [Reference Conrad, Gaber and PrasadCGP15, Definition 7.1.3]):
Thus, the inclusion (5.1) implies that the full Frobenius kernel
${}_1 G_{(i)}$
is contained in H. In particular,
which contradicts the assumption that this intersection equals
$\mathfrak {h}_\lambda \cap \operatorname {\mathrm {Lie}}(U^-_i)$
. Hence, in all cases,
$\operatorname {\mathrm {Lie}}(H)$
is T-stable, which proves (2), and therefore also (1).
Corollary 5.5 Assume that
$p \geq 3$
. Let H be a smooth horospherical subgroup of G. Then H is strongly horospherical.
Proof Since H is horospherical,
$H^\circ $
is also horospherical, and thus strongly horospherical by Proposition 5.4(2). Hence, by Proposition 4.4(1), the quotient group
$N_G(H^\circ )/H^\circ $
is a torus. In particular, the quotient variety
is again a torus. That is,
$N_G(H^\circ )$
normalizes H, which implies that
$N_G(H) = N_G(H^\circ )$
is a parabolic subgroup of G, and thus H is strongly horospherical.
5.4 The general case
We are now ready to prove the main result of this article.
Theorem 5.6 Assume that
$p \geq 3$
. Let H be a horospherical subgroup of G. Then H is strongly horospherical.
Proof To simplify the argument, we assume that G is simple. The general case is similar, but slightly more technical to write down. We proceed by induction on the height of H. If the height of H is equal to
$0$
, then H is smooth, and we conclude by Corollary 5.5.
Assume now that the statement holds for any horospherical subgroup of height at most
$m \in \mathbb {N}_{\geq 0}$
. Let H be a horospherical subgroup of height
$m+1$
. Then
$P := HT$
is a parabolic subgroup of G, and we will prove that
$P = N_G(H)$
.
By Theorems 2.4 and 2.5, there exists a subset
$I \subset \Delta $
such that
where the second case occurs only if
$p = 3$
and G is of type
$G_2$
. Here, K denotes the kernel of the very special isogeny
$\pi _G\colon G \to \overline {G}$
(see Section 2.2);
$ r_\nu \geq 0 $
in the first case, and
$ r_\nu \geq 1 $
in the second. The subgroup
$P^\nu $
denotes the maximal reduced parabolic subgroup of G associated with the simple root
$\nu $
. Then, as discussed in Section 2.4, the character group of P is of the form
Note that
$P_{\mathrm {red}} = H_{\mathrm {red}}T = N_G(H_{\mathrm {red}})$
, where the second equality follows from the smooth case (Corollary 5.5) and Remark 4.3. Since
$H \cap T$
contains
$H_{\mathrm {red}} \cap T$
, and since
$H_{\mathrm {red}}$
is obtained by taking kernels of characters of
$P_{\mathrm {red}}=\bigcap _{\nu \in \Delta \setminus I} P^\nu $
, only the fundamental weights associated with
$\nu \in \Delta \setminus I$
can appear when writing
$H \cap T$
as an intersection of kernels of characters of T. Thus,
with F a finite set,
$s_{\nu ,j} \geq 0$
, and
$l_{\nu ,j} \geq 0$
, which – when nonzero – must be coprime to p.
We will first show that all the
$s_{\nu ,j}$
that appear in (5.3) satisfy
$s_{\nu ,j} \geq r_\nu $
, which will allow us to define the strongly horospherical subgroup
whose normalizer is P (Proposition 4.7(2)). Then we will show that
$H = H'$
.
Let
$L := F(H) \simeq H / {}_1 H \subset G^{(1)}$
. By the induction hypothesis, since the height of L is one less than that of H, the subgroup L is strongly horospherical. Additionally, we have
Hence, since L is strongly horospherical, we deduce that
On the other hand, the character group of
$LT^{(1)} = F(P)$
is given by
Thus, we deduce that for any
$\nu \in \Delta \setminus I$
, if
$l_{\nu ,j} \neq 0$
, then
hence either
$s_{\nu ,j} \geq r_\nu $
, or
$(s_{\nu ,j}, r_\nu ) = (0,1)$
.
It remains to check that, if
$l_{\nu ,j} \neq 0$
and
$r_\nu = 1$
, then
$s_{\nu ,j} \neq 0$
. To see this, let
$\gamma $
be the sum of all simple roots and denote as
$G_\gamma $
the corresponding copy of
$\operatorname {\mathrm {SL}}_2$
, with fundamental weight
$\omega $
. Since the multiplicity of
$\nu $
in
$\gamma $
is equal to one, the weight
$\varpi _\nu $
restricts to
$\omega $
on the maximal torus of
$G_\gamma $
. Next, consider the intersection
$H \cap G_\gamma $
, which is a strongly horospherical subgroup of
$G_\gamma $
(see Section 5.2). Since
$r_\nu =1$
, there exists an integer
$m_\gamma \geq 1$
such that
and
In particular, we must have
$s_{\nu ,j} \geq r_\nu = 1$
for every j with
$l_{\nu ,j} \neq 0$
. We can thus define
$H'$
as in (5.4). Notice that if
$p=3$
and the group G has a simple factor of type
$G_2$
, then the choice of
$\gamma $
(in particular, being a short root containing
$\nu $
in its support) guarantees the last equality in (5.5). Indeed, in all other cases,
$r_\nu =1$
implies necessarily that
$Q^\nu = {}_1GP^\nu $
, while in this last case, the existence of the very special isogeny allows for a second possibility, namely,
$Q^\nu = KP^\nu $
. Here, the fact that
$\gamma $
is short is crucial: indeed, for a long root
$\delta $
containing
$\nu $
it its support, we have instead
$Q^\nu \cap G_\delta = B \cap G_\delta $
.
We claim that
$H = H'$
. First, by construction, we have
Thus, to conclude, it suffices to show:
Indeed, these two conditions imply that both H and
$H'$
are extensions of L by
${}_1 H$
, and since one is contained in the other, they must coincide.

(a): This is equivalent to showing that
$\operatorname {\mathrm {Lie}}(H) = \operatorname {\mathrm {Lie}}(H')$
(see Theorem 5.1(1)). We know from Proposition 5.4(1) that both of these Lie subalgebras are T-stable and that they contain
$\operatorname {\mathrm {Lie}}(U)$
. Moreover, by construction,
$H \cap T = H' \cap T$
, so
and it remains to check that the intersections with
$\operatorname {\mathrm {Lie}}(U_-)$
coincide.
On the one hand, we have
since
$P \cap U_- = H' \cap U_-$
by Lemma 4.2, and hence
$\operatorname {\mathrm {Lie}}(P) \cap \operatorname {\mathrm {Lie}}(U_-) = \operatorname {\mathrm {Lie}}(H') \cap \operatorname {\mathrm {Lie}}(U_-)$
. Assume for contradiction that the inclusion (5.6) is strict; that is, there exists some
$\alpha \in \Delta \setminus I$
such that
This means that
$U_{-\alpha } \cap H = 1$
while
$U_{-\alpha } \cap H' \neq 1$
. By Theorem 5.2, and since
$p \geq 3$
, intersecting with the corresponding copy
$G_\alpha \simeq \operatorname {\mathrm {SL}}_2$
yields the inclusion
and thus, multiplying by
$T \cap G_\alpha $
gives
which in turn implies
$H' \cap U_{-\alpha } = P \cap U_{-\alpha } = 1$
, a contradiction.
So the inclusion (5.6) must be an equality. That is, (a) holds.
(b): First note that
$F(H')=F(H)$
implies that
$H^{\prime }_{\mathrm {red}}=H_{\mathrm {red}}$
. Since
$H'$
is strongly horospherical, it is generated by U, together with
$H' \cap T$
and the groups
$H' \cap U_{-\nu }$
for
$\nu \in \Delta $
ranging over the simple roots. In order to conclude that
$H' \subset H$
, it is thus enough to verify that
The first equality holds by the very definition of
$H'$
. Let us now examine the second:
-
• If $\nu \in I$
, then
$U_{-\nu } \subset H_{\mathrm {red}}$
, so in particular, $$\begin{align*}U_{-\nu} = U_{-\nu} \cap H = U_{-\nu} \cap H'. \end{align*}$$
-
• If $U_{-\nu } \cap H = 1$
, then the same argument as in part (a) yields
$U_{-\nu } \cap H' = 1$
. -
• Now assume that $\text {ht}(U_{-\nu } \cap H) = s_\nu \geq 1$
, and let
$\text {ht}(U_{-\nu } \cap H') = s^{\prime }_\nu \in \mathbf {N}_{\geq 0}$
. Note that, by step (a), we must have
$s^{\prime }_\nu \geq 1$
. Then $$\begin{align*}s_\nu - 1 = \text{ht}(F(H \cap U_{-\nu})) = \text{ht}(L \cap U_{-\nu}^{(1)}) = \text{ht}(F(H' \cap U_{-\nu})) = s^{\prime}_\nu - 1 \geq 0, \end{align*}$$which immediately gives $s_\nu = s^{\prime }_\nu $
.
This concludes the proof of the facts (a) and (b), and thus also the proof of the proposition.
Example 5.7 Let us clarify at which step the above proof fails in the unique example of a horospherical subgroup
$H = \mathcal {B}(\infty ) \subset G = \operatorname {\mathrm {SL}}_2$
that is not strongly horospherical when
$p = 2$
. In this case, we have
Hence, we obtain, as in the proof of Theorem 5.6, a strongly horospherical subgroup
$H' \subset \operatorname {\mathrm {SL}}_2$
. But
$H' \not \subset H$
(which is impossible for
$p \geq 3$
). Indeed,
Acknowledgements
We are grateful to the anonymous referee for the careful reading of the former version of this article and for their helpful comments. We also thank Kévin Langlois, Michel Brion, and Friedrich Knop for useful discussions related to this work.






