Hostname: page-component-74656f9884-kv2lp Total loading time: 0 Render date: 2026-11-05T23:13:31.389Z Has data issue: false hasContentIssue false

An infinite family of Thue equations with at most two solutions

Published online by Cambridge University Press:  31 July 2026

Anton Kleitman*
Affiliation:
Cornell University , USA
Rights & Permissions [Opens in a new window]

Abstract

For an odd positive integer $n$, define

$$ \begin{align*}P_n(x, y) = \sum\limits_{\substack{0 \leq k \leq n\\k \text{ is even}}}(-1)^{\frac{k}{2}}\binom{n}{k}x^{n - k - 1}y^k. \end{align*} $$
We prove that, for $n \geq 5$, the Thue equation $P_n(x, y) = 1$ has exactly two solutions in integers $x$ and $y$, namely, $(1, 0)$ and $(-1, 0)$, and that the Thue equation $P_n(x, y) = -1$ has no solutions. Our result is a consequence of the famous theorem of Bilu, Hanrot, and Voutier on Lucas sequences.

Information

Type
Article
Creative Commons
Creative Common License - CCCreative Common License - BY
This is an Open Access article, distributed under the terms of the Creative Commons Attribution licence (https://creativecommons.org/licenses/by/4.0), which permits unrestricted re-use, distribution and reproduction, provided the original article is properly cited.
Copyright
© The Author(s), 2026. Published by Cambridge University Press on behalf of Canadian Mathematical Society
Figure 0

Table 1 Binary forms Pn$P_n$ for n=5,7,9,11,13$n = 5, 7, 9, 11, 13$.Table 1 long description.

Figure 1

Table 2 n$n$-defective Lucas pairs (up to equivalence) for 4$4 < n \leq 30$ and n≠6$n \neq 6$.Table 2 long description.